Solving Inequalities with Two Absolute Values by Testing Points

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  • Опубліковано 5 жов 2024
  • This may not be an SAT/ACT inequalities question, but it's more difficult than those seen on SAT or ACT. So, if you understand the two techniques demonstrated in this video about solving inequalities, you will become a lot better on your SAT or ACT preparation!
    We are solving the inequality |x+3|+|x-1| less than or equal to 8 by breaking into cases and testing points.
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КОМЕНТАРІ • 28

  • @ahmadmhmd5465
    @ahmadmhmd5465 9 місяців тому +2

    Awesome thank you so much❤❤

    • @GlassofNumbers
      @GlassofNumbers  9 місяців тому

      Thank you! Please help me share the video with others 😁👍

  • @chloe-jw6nt
    @chloe-jw6nt Рік тому +4

    why do we need to draw the number line if u already got x=3,=5? cant u just automatically make the link to [-5,3]

    • @GlassofNumbers
      @GlassofNumbers  Рік тому +4

      Because the solution could been (-inf, -5] or [3, inf), so we need to test points and check.

  • @mubirumahad1004
    @mubirumahad1004 Місяць тому

    How would you do it if it were subtraction of absolutes instead of addition

  • @vc-zo5vn
    @vc-zo5vn 2 місяці тому

    when doing the different cases, why does it have to be an equation (=)? is it not possible to retain the signs and solve it like a regular inequality?

  • @peaceful_flow639
    @peaceful_flow639 10 місяців тому +1

    If we have 0 instead of 8 and it is just |x+3| + |x-1|

    • @GlassofNumbers
      @GlassofNumbers  10 місяців тому

      Correct! In that case, we only consider the equation. And no need to test points since |x+3| and |x-1| must be both zero at the same time in order for the equation to be true. Can we get a solution then?

  • @AlizaAkram-e2l
    @AlizaAkram-e2l 11 місяців тому +1

    If on R.H.S has > 8 then what will be the cases to solve the question

    • @GlassofNumbers
      @GlassofNumbers  10 місяців тому

      Good question! The process is similar, but we want the sum of the absolute values to be greater than 8.

  • @thanhloan4342
    @thanhloan4342 Рік тому +1

    in VIET NAM , we have x+3+x-1 = 8 and -8 . that enought

  • @kingsleyosei3256
    @kingsleyosei3256 Рік тому +1

    Love it ❤

    • @GlassofNumbers
      @GlassofNumbers  Рік тому

      Thank you! Please help me share my video as well! 👍😁

  • @MATHMAN-qz3de
    @MATHMAN-qz3de 6 місяців тому +1

    try and solve something like |x+1|>|x+3|

    • @GlassofNumbers
      @GlassofNumbers  6 місяців тому

      If we move |x+3| to the left side, it is similar to the question in this video.

  • @weneverforgetwearelegion
    @weneverforgetwearelegion Рік тому +1

    does it always work?

  • @rnegoro1
    @rnegoro1 Рік тому +1

    Nice

  • @Hrujula
    @Hrujula 6 місяців тому

    Number line before -5 y isn't it in solution

  • @moonsuyoung2407
    @moonsuyoung2407 7 місяців тому +1

    i love you

    • @GlassofNumbers
      @GlassofNumbers  7 місяців тому

      Thank you! Please help me share my video 😁👍

  • @atineeabanga-jk4gh
    @atineeabanga-jk4gh Рік тому +2

    Abanga

  • @雅玲陳-d8g
    @雅玲陳-d8g Рік тому

    劉有吟