Mechanics of Materials - Column Buckling example 2

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  • Опубліковано 10 гру 2024

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  • @stardustnation2480
    @stardustnation2480 3 роки тому +1

    36.6 kips when divided by pi does not come out to 31.06 ksi. It should instead be 11.65 ksi, or thereabouts.
    I was a little bit confused at first where that number came from but I realized it is what you get when you divide the original computed value for Pcr, 97.57 kips, by pi. I believe this is a mistake.

  • @saheedkasali9793
    @saheedkasali9793 3 роки тому

    The formula used in computing the moment of inertia?........am confused is it not ment to be: 1/64(pi*D**4)

    • @engineeringdeciphered
      @engineeringdeciphered  3 роки тому +3

      Either equation is correct. 1/64 * pi * d^4 is the same as 1/4 * pi * r^4 since r = d/2

  • @kylecatman7738
    @kylecatman7738 3 місяці тому

    36.6 / pi = 11.65 ksi... am I not seeing how you got 31.06 ksi??

  • @braydenallen6119
    @braydenallen6119 3 роки тому

    I wanted to verify this calculation provides a verified factor of safety of 2 for buckling only, correct? We would have to calculate from the original Pcr to have an idea of whether or not the build met an FOS of 2 for yield stress, right? Because if the column failed due to stress at the Pcr value, then stress would control the factor of safety?