Memoryless Property of the Geometric Distribution

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  • Опубліковано 19 жов 2024

КОМЕНТАРІ • 36

  • @gipetgifta8888
    @gipetgifta8888 3 роки тому +10

    Out of all proof that i found in the internet this is the most understandable one. Thank you very much for providing a very comprehensive proof of this memory-less property!

    • @DrHarishGarg
      @DrHarishGarg  3 роки тому +1

      Many thanks for the appreciation.

    • @kalaivanic1008
      @kalaivanic1008 2 роки тому

      S really happy that I can understand geometric distribution this much easier 👍🏻

  • @taeyann6153
    @taeyann6153 Рік тому

    this is the most understandable proof of the memory-less property! Thanks alot!

  • @enzokuhlemsotra6383
    @enzokuhlemsotra6383 3 місяці тому

    thank you sir for this great explaination

  • @Newfacts-18
    @Newfacts-18 Рік тому

    I couldn't understand before seen your lecture but i got completely after to seen your lecture sir you are so genius i am so happy to learn probability to you

  • @shaonlipal8225
    @shaonlipal8225 3 роки тому +2

    Thank you, Sir! Awesome explanation!

    • @DrHarishGarg
      @DrHarishGarg  3 роки тому +1

      Many thanks

    • @kyloramon4970
      @kyloramon4970 3 роки тому

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      @kasonadrien1585 3 роки тому

      @Kylo Ramon instablaster :)

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      @kyloramon4970 3 роки тому

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      @kyloramon4970 3 роки тому

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  • @Newfacts-18
    @Newfacts-18 Рік тому +1

    You are best sir i am able to got that you tought us

  • @rasikashetye2698
    @rasikashetye2698 3 місяці тому

    Thank you!

  • @035mdatiqurrahmanakash7
    @035mdatiqurrahmanakash7 3 роки тому +4

    sir , please solve those practice questions

  • @sneakybinders
    @sneakybinders 3 роки тому +1

    Very well explained !

  • @soumyaagrahari2107
    @soumyaagrahari2107 2 роки тому +1

    Sir please make a video how to solve questions using memory less property

  • @venkatnaidunallabothula1910
    @venkatnaidunallabothula1910 2 роки тому +1

    Thank you so much sir

  • @ai.art_ara
    @ai.art_ara 2 роки тому +1

    Sir, alternatively could you explain proof of P(Y=t|X >=k) = pq^t = P(X=t)? It is the prood given in VK Kapoor book.

  • @snehashirgaonkar1065
    @snehashirgaonkar1065 Рік тому

    Thank you so much sir 🙏🙏

  • @priyansukumar3875
    @priyansukumar3875 2 роки тому

    Thanku so much sir ❤️ for this series

    • @DrHarishGarg
      @DrHarishGarg  2 роки тому

      So glad!... Keep watching and sharing

  • @ridhimachauhan4962
    @ridhimachauhan4962 2 роки тому

    Amazing session sir!!

    • @DrHarishGarg
      @DrHarishGarg  2 роки тому

      Many thanks....
      Join my telegram link of Probability and Statistics
      t.me/gargProbability

  • @elomi8092
    @elomi8092 2 роки тому

    Thank you so much ❤

  • @hariniharini5692
    @hariniharini5692 Рік тому

    It's very useful and understandable but please put the solution for practice problems

  • @user-gv3lq2qy2g
    @user-gv3lq2qy2g 2 роки тому

    Thankkkkkkkkk u very much sir🙃

    • @DrHarishGarg
      @DrHarishGarg  2 роки тому

      My pleasure always. Keep watching and sharing.

  • @harshbari9066
    @harshbari9066 Рік тому

    What are the answers of the given 2 questions at the end ?

  • @jayeshpatil5112
    @jayeshpatil5112 Рік тому +1

    done

  • @Dvibes2899
    @Dvibes2899 Рік тому

    👏👏🙏🙏

  • @Dupamine
    @Dupamine 2 роки тому

    this is the hardest video of yours so far

    • @DrHarishGarg
      @DrHarishGarg  2 роки тому +1

      But it is the easiest one too. .. Keep watching