Thevenin's Theorem with Independent & Dependent Source || Must Watch || Ex 4.10, PP 4.10 & 4.9 ||

[@AyushGupta-fn7ux]

Sir this video really healped me a lot. Thank you SIR

[@ElectricalEngineeringAcademy]

Welcome Gupta G. Best wishes.

[@لبيبعدنان-ذ4ق]

@@ElectricalEngineeringAcademy You can continue with you a very necessary theme plays

[@Suly.m005]

Thank you ,sir.
❤❤❤❤👍

[@ElectricalEngineeringAcademy]

Welcome dear

[@fazlayelahieeeaust]

Sir I don't know how to thank u. Your video is extremely helpful. Love and Respect from Bangladesh 🇧🇩 ❤

[@ElectricalEngineeringAcademy]

So nice of you. Just pray for me.

[@fazlayelahieeeaust]

@@ElectricalEngineeringAcademy Sir you also keep me in your prayers. ❤️

[@alexlaura1486]

Really well explained, thanks!

[@cocmagic6460]

Thank you sir for your help.. This helped a lot in my exams

[@ElectricalEngineeringAcademy]

Good luck dear.

[@Thefakisgoinon]

Hello, in example 14:08, if I have a dependent current source somewhere, do I make it open and continue with same calculations?

[@ElectricalEngineeringAcademy]

Yes. Please see Note at time 10:41

[@iyrg]

MAY ALLAH BE WITH YOU SIR, THANKS :)

[@ElectricalEngineeringAcademy]

Jazak Allah Khairan, dear.

[@ramasubramaniang1638]

Bible for circuit analysis beginners!!

[@sanaulemon1616]

thank u so much sir. Hope we Will get too may tutorials...In Sha Allah.

[@ElectricalEngineeringAcademy]

Thanks dear. Let me know if u have diffilculty in any topic.

[@sanaulemon1616]

@@ElectricalEngineeringAcademy yes sir, Thanks a lot for your kindness. We miss some tutorials about Zener diode.

[@ElectricalEngineeringAcademy]

@@sanaulemon1616 ok, Inshaa Allah

[@ElectricalEngineeringAcademy]

@@sanaulemon1616 Please tell me which book you are following.

[@sanaulemon1616]

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[@hamidunatg478]

Assalamu 'Alaikum Sir
Your prsentation is very good
May Allah SWT Bless You Always 🌼🌞
AAMEEN 🤲🙏🏻
Thanks and best regadas 🌼🙏🏻

[@ElectricalEngineeringAcademy]

Walaikum Assalam. Thanks for your prayers. May Allah SWT accept your prayers. Jazak Allah Khairan.

[@asimabdullah4598]

At 14:50 V0 = 7.4V but you mentioned 13.6V
correction sir.

[@ElectricalEngineeringAcademy]

Thanks Asim. i will look into it.

[@vigneshwaranduraisamy2072]

Thank you sir, great help.thanks lot

[@ElectricalEngineeringAcademy]

Welcome dear. Best wishes.

[@لبيبعدنان-ذ4ق]

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[@ElectricalEngineeringAcademy]

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[@aamirhussain6103]

Good explanation

[@sagarmondal9063]

Excellent

[@samuellamanyeaglago6919]

thank you very much sir, God bless you.

[@ElectricalEngineeringAcademy]

Welcome dear. Best wishes.

[@omorfaruk7343]

Thanks for this video 🙂

[@tajuhossain3021]

Beautiful

[@aamirhussain6103]

But sir i have a question which seems difficult i need ur help how to interact..plz..

[@riyahossen3348]

Thanks a lot

[@hashforeva5996]

Sir can you please tell how you got Vth as 12 at 16:56 ?

[@ElectricalEngineeringAcademy]

Thanks dear. At time 10;40 we had calculated VTH= 12 V.

[@missweety8744]

Great

[@asimabdullah4598]

At 14:30 V1 = 3.6V but you mentioned -3.6V
correction sir.

[@ElectricalEngineeringAcademy]

Yes, you are right, V1 should be +3.6v, and hence V0 will be 7.4V. Thanks, but I hope the concept is clear.

[@asimabdullah4598]

can I have your email id, so I can put forward my doubts to you.

[@ElectricalEngineeringAcademy]

[e-mail]

[@twinkleplace4041]

Thanks a lot!!

[@zillurrahman4859]

Nice 👍

[@mdimam4790]

Nice

[@shorifulislam4473]

Good

[@adambanks4781]

excuse me, at 12:07, should'nt it be i1=(0-(V1+2i))/6 ?? You forgot the bracket.

[@ElectricalEngineeringAcademy]

I don't think so. Initially we ignore any source present in the branch, and just write (0-V1), because the current is flowing from 0 to V1; then we see the direction of current due to any source present in the branch (2i in this case), if the current direction is same as the main branch current (which is what in our case) then we add that source (+2i), the whole expression is then divided by the resistance in the branch.To be more precise, you could write ((0-V1)+2i)/6.

[@adambanks4781]

@@ElectricalEngineeringAcademy Ahh i seeee. Alright thank youu!! You really helped me a lot !! Appreciate it !!

[@ElectricalEngineeringAcademy]

@@adambanks4781 Good Luck.

[@sarithaandra9659]

But sir why you consider v+4vo is it correct, it is v-4vo ?.. could you please reply sir

[@sarithaandra9659]

At7:32

[@ElectricalEngineeringAcademy]

U have to watch my videos on nodal analysis to have a better understanding. Let me try to explain here. we are assuming that the current is flowing from vo to ground. If there was no dependent source, then our equation would have been (vo -0)/(10+5). Now consider the effect of the dependent source; the current due to this source will flow out of its positive terminal, which is in the same direction as current from vo, hence this voltage source will be added. so v0+4vx is ok.

[@md.shamimreza5064]

super

[@sarithaandra9659]

Good explanation sir could you please tell about which book I prefer to learn best especially on this theorems please sir reply

[@ElectricalEngineeringAcademy]

Thanks dear. I follow Alexander and Sadikus book 'Fundamentals of electric circuits'

[@pradeepprakash7105]

Thanks a lot sir , Love from Tamilnadu . Sir kindly tell which book will be helpful for theory among sadiku and hayt. And especially for this topic (thevenin theorem with dependent sources which book is the best) , kindly tell sir

[@ElectricalEngineeringAcademy]

Welcome Pradeep. To me, Sadiku is easy as compared to Hayt. I think my video should be sufficient to understand. Just watch it three times, then you can solve any problem from any book. In case of problem, write me at [e-mail]

[@pradeepprakash7105]

@@ElectricalEngineeringAcademy very kind of you professor , thanks for the reply sir , will sure about network theory in coming days. Thank you sir

[@Withloveshanique]

Thank you so much!

[@ElectricalEngineeringAcademy]

Welcome dear. Best wishes.

[@sonuhalder9211]

Sir here i0 would be negative ...

[@ANGEL-mb9yx]

Thank u sir

[@Abdulla__420]

wow

[@victorzacharia2528]

Now use mesh analysis to that question

[@ElectricalEngineeringAcademy]

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[@tajuhossain3021]

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[@farrahaqilachesam9936]

thanksss

[@ElectricalEngineeringAcademy]

Thanks Farrah. Best wishes.

[@لبيبعدنان-ذ4ق]

@@ElectricalEngineeringAcademy You can continue with you a very necessary theme

[@ElectricalEngineeringAcademy]

@@لبيبعدنان-ذ4ق Jazak Allah Khairan.

[@لبيبعدنان-ذ4ق]

@@ElectricalEngineeringAcademy Can you have your own account please?

[@لبيبعدنان-ذ4ق]

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[@saifasad7706]

V1=+3.6

[@ElectricalEngineeringAcademy]

What time ? What is the issue ?

[@alaminhossain253]

Excellent

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