2 is not primitive root of modulo 7 Because phi(7)=6 Thus 2^6(mod 7)=1 hona chaiye. But 2^3(mod 7)= 1 a reha h Thus 2 is not primitive root of modulo 7. Ha but sr ne reminder glti se 3 leya h video m.
2,3,4,5... all are primitive roots of 7. When you are multiplying any number on left hand side you need to multiply its modulo on the right hand side. In the video you multiplied the number directly without taking its modulo.
Sir aap glt bt diye....jb 16 ko divide krnge 7 se toh remainder 2 aayega aur 2^6 == 1 aayega...then we can say that 2 is also premitive root but it is not....
2 is not primitive root of 7 because reminder is not distinct. 2'=2(mod 7) 2^2=4(mod 7) 2^3=1(mod 7) 2^4=2(mod 7) 2^5=4(mod 7) 2^6=1(mod 7) Here 2,4 and 1 are repeated not distinct.
14:30 pr sir agar hum 3^2 ki jageh sirf 2 likhain tab 4.2 = 8 aaye ga, phir jab ausse 7 se divide karein ge toh - 1 aaye ga.. Why does this happen?? I mean kahin aesa toh nahi positive value lane keliye hum ne 3^2 put kiya hai?? Kindly clear this
Yes, u r right bcz 2 to the power 3 skipped that is mod 1 so here 2 is also primitive it seems.... Sir please let us know if anything wrong we are understanding..
When you divide 16 by 7 you get remainder 2 not 3
Yes
Yes it make me confused
He doesn't even know basic maths how do anyone can accept anything else from him .
sir 2 is the primitive root. 2 power 6 is 64 ,64 is congurent to 1 modulo 7
What about 2 to the power 3 ?? Isn't it an example
Superb sir ! all cleared by you with perfect method !
Galat hai pura
Sir, how can we find the primitive roots of 3^3(three to the power 3),plz reply soon ,I need it..
For 2^3 it will give the remainder 1 no.. ? In last question
2 is not primitive root of modulo 7
Because phi(7)=6
Thus 2^6(mod 7)=1 hona chaiye.
But 2^3(mod 7)= 1 a reha h
Thus 2 is not primitive root of modulo 7.
Ha but sr ne reminder glti se 3 leya h video m.
2 is primitive root of mod 7
Sir apne yahan 2 se jb kia thaa too 2^3 ni li us se remainder 1 hi aye gaa..modulo 7 me
Thank u sir bahot acha laga
But sir AK galti ki ha apne jb app 16m divide krege 7see tho remainder 2aayega
1) 1 hum keu nahi la sakte..?
2) 2 is a primitive root of 7
1 sob ko divide kerte he
Thanks sir. Ur videos are very helpfull
jab ham 2^6 likay gay to us ka remainder to 1 a jata ha jab us ko 7 par divide karay gay lakin ap nay kasy 5 liak ha ?
Sir next example Bala video nhi mil Reha 🙄...plz share e link in discreption box ???
Sir we can also take 3^2 =2
as we solve this above just like we took 3^4 = 4
2,3,4,5... all are primitive roots of 7. When you are multiplying any number on left hand side you need to multiply its modulo on the right hand side. In the video you multiplied the number directly without taking its modulo.
thank u sir😊
Sir number theory ka all video dekhni hai aapki
Thanks you so much sir
Sir one kiun nai lena, plz tell me
2 is primitive root sir
Kiska??
Primitive root of 7
Sir aap padhate bahut Acha h smjhate bhi behtarin h lekin khul k bole Awaaz m karkas h bahut
सर आप अदरक डालकर थोड़ा सा गर्म पानी पिया करो
सर ऐसा लग रहा है जैसे आप रात को 1:00 बजे अपनी गर्लफ्रेंड से बात कर रहे हो
Thanku ❤️
Sir aap glt bt diye....jb 16 ko divide krnge 7 se toh remainder 2 aayega aur 2^6 == 1 aayega...then we can say that 2 is also premitive root but it is not....
Bhi 16 ko jb 7 sa divide kiya to 3 reminder kasa?😁
Very nice
2is primitive root you did wrong bcz reminder is 2 not 3
Galat ha sir ka
bhai 13.00 aapne divison me galti ki hai. 16 ko 7 se divide krne p remainder 3 ni hota h
2 is not primitive root of 7 because reminder is not distinct.
2'=2(mod 7)
2^2=4(mod 7)
2^3=1(mod 7)
2^4=2(mod 7)
2^5=4(mod 7)
2^6=1(mod 7)
Here 2,4 and 1 are repeated not distinct.
Why you not take 2^3, 3^3.
2^6=64=63+1=÷7
Remember 1then 2is a primative root of 7
Use fermant's theorem
Thanku sir
Nice sir
Committed error in 2**6: 2**6-1= 63; divided by 7. Error in division: 16-14=2 and not 3.
2^3 pr to 1 remainder aata hbsir
Thanks sir
2 ke power 4 congruent 2 ni ay ga ??? 3 kasa araha ha?
14:30 pr sir agar hum 3^2 ki jageh sirf 2 likhain tab 4.2 = 8 aaye ga, phir jab ausse 7 se divide karein ge toh - 1 aaye ga.. Why does this happen?? I mean kahin aesa toh nahi positive value lane keliye hum ne 3^2 put kiya hai?? Kindly clear this
You should have known fermats little theorem. Then, you could have avoided this big blunder.
plzz sir theormz about prmitive roots plzz
sir please video ko shi krky vdo upload kejiye
Aap n 16÷7 kra h to sir g remainder 2 bach rha na ki 3 check kro 7 roots wale m esko Shi krke video dobara uplod kro sir g
Sahi kaha.....galat kardiya sawaal pura
Here 2 is primitive root of 7.
There is mistake in calculation.
Yes, u r right bcz 2 to the power 3 skipped that is mod 1 so here 2 is also primitive it seems.... Sir please let us know if anything wrong we are understanding..
yes
thanks u sir
2 is primitive root of 7
Sir 2 primitive root h 7 ka
Awaz to saaf krlayn
What is the primitive root of 41,31 how to solve this type of questions anyone explain pls
Which language is he speaking?
how to find primitive roots of 11??
Aap kon se book follow krte ho
math wallie
In the last question have some mistakes....😢
Aqal kay andhay 16-24=2 hota hay 3 nahi.
Video bnane s phle divide sikh lete to shyd acche hote video
Unka kam Humy primitive root Ka concept dena tha na KY +,- ya divide karna seekhana Jo concept chayei tha mil gya mistake ho JATi it's not a big deal
Apply this to 24 and 25
Remainder 2 aayega
Thnkeww.. ☺
2power 6 mod 7 is primitive root
ore humy ya bolay 2 kayprimitive roots kay hain
One b to Co Prime ha na 6 ka
Gcd kese nikalenge
Gcd matlab hcf
Seond 2 questoion 3 gcd rong bate ha
Find primitive roots of 25
12.03 me vul he
You have done wrong because 16-14=2
Sir vaha 16-14=2 ata
2 primitive h 7 ka
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3
2 rong ha apka please again deke
He
2 b primitive root h
2,3,4,5,6 is also primitive root's of 7
You are learn was wrong 👎
2 ta ho raha hr
Question is not correct
don't follow this ,, this is totally wrong
2 is primitive root of 7