Hey, i have a question in my mind; why didn't we use our calculated spesific volume value while calculating the quality (at 07:53)? BTW great course, thx for everything Sir!
The vf value is the specific volume of a saturated liquid, and ours is not a sat liq, ours is a mixture. So we plug in our v value as “v” and the sat liq value as “vf” and then vfg is vg - vf. Does that make sense?
You can do either! I like to go to A5 and the if my temperature is higher than the tsat for that pressure- then I know it’s superheated. Your other option is going to A4 and if your given pressure is lower than the psat for that temp- then you know it’s superheated. Either table should point you in the right direction!
vf=0.0007435 m3/kg and vg=0.1229. The specific volume of the mixture is v=0.02m3/kg. So the specific volume of our liquid falls between the specific volume of a sat liquid (vf) and a sat vapor (vg). So in simpler terms vf< v
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My teacher doesn’t teach this lesson so I’m browsing your lecture sir to understand it
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Hey, i have a question in my mind; why didn't we use our calculated spesific volume value while calculating the quality (at 07:53)? BTW great course, thx for everything Sir!
I think that’s what I did? I used the specific volume that we calculated = vf + (x)vfg to solve for x
@@engineeringdeciphered i mean why did we use value from table rather then 0.02m3/kg? Why didn’t our vf value become 0.02?
The vf value is the specific volume of a saturated liquid, and ours is not a sat liq, ours is a mixture. So we plug in our v value as “v” and the sat liq value as “vf” and then vfg is vg - vf.
Does that make sense?
hi dr, if the temperature and pressure of liquid-vapor mixture are provided together, which table A4 or A5 is more preferable for us to refer?
You can do either! I like to go to A5 and the if my temperature is higher than the tsat for that pressure- then I know it’s superheated. Your other option is going to A4 and if your given pressure is lower than the psat for that temp- then you know it’s superheated. Either table should point you in the right direction!
H = mh 12:00
total enthalpy = specific enthalpy x mass
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2:09
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The v=0.02m3/kg is larger than vf. How is it between?
vf=0.0007435 m3/kg and vg=0.1229. The specific volume of the mixture is v=0.02m3/kg. So the specific volume of our liquid falls between the specific volume of a sat liquid (vf) and a sat vapor (vg). So in simpler terms vf< v
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Quality ratio of masses, not ratio of volume
when i clicked the video i didnt expect to fully understand the solutions but wow i was wrong