Thanks a million! I had been fruitlessly frustrated after searching for hours for a tutorial on how to decompose functions into their even and odd parts and had not found any! All of the other tutorials I had found only show the definition of an even function and an odd function, not how to decompose them.
I see this correction here, but have seen in other peoples videos they place "comments" within the video that trigger at a certain time. It would be helpful to the viewer if you did this in your video. Thanks for the lesson, it was very informational. It is good that you go through all steps. Really helps.
@ayad91 For a complex valued signal to be even, both its real and imaginary parts must be even. For a complex valued signal to be odd, both its real and imaginary parts must be odd. You can decompose a complex signal into its even and odd components by decomposing the real and imaginary parts separately. The even component of the signal is the even component of the real part + j times the even component of the imaginary part.
Hİ sir Thank you for videos :) I have a question for this video You said "x(t) equal -x(-t) for odd signal" but on 8:32 you found -x(-t) = { -1 for t0} but x(t) = {0 for t0} are these signals equal?
To test if the signal is even, start with x(-t) and see if you can manipulate it mathematically so it is the same as x(t). If you can, it is even. To test if it is odd, start with x(-t) and see if you can manipulate it so it is the same as -x(t).
+t3hb0ss It's not unit step function that equals to u(t)-u(t-1). It is equal to unit impulse function. unit impulse function is [u(t) - u(t-1)] / 1 for example (in continuous).
Thanks a million! I had been fruitlessly frustrated after searching for hours for a tutorial on how to decompose functions into their even and odd parts and had not found any! All of the other tutorials I had found only show the definition of an even function and an odd function, not how to decompose them.
I see this correction here, but have seen in other peoples videos they place "comments" within the video that trigger at a certain time. It would be helpful to the viewer if you did this in your video.
Thanks for the lesson, it was very informational. It is good that you go through all steps. Really helps.
You're awesome. I hate taking professors word, I like to be shown, and you nailed it. Thanks a lot.
You are correct. The equation should be xo = 1/2 [x(t)-x(-t)]
You and your other videos have been a life saver.
@ayad91 For a complex valued signal to be even, both its real and imaginary parts must be even. For a complex valued signal to be odd, both its real and imaginary parts must be odd. You can decompose a complex signal into its even and odd components by decomposing the real and imaginary parts separately. The even component of the signal is the even component of the real part + j times the even component of the imaginary part.
@jordanstanich yes i agree with you mate.
at 05:42, for an odd signal it should be,
xo(t) = 1/2 [ x(t) - x(-t) ]
thanks for the videos. but what if the signal is not a real valued?
Finally a good accent.
same thing
Hİ sir Thank you for videos :)
I have a question for this video
You said "x(t) equal -x(-t) for odd signal" but on 8:32 you found -x(-t) = { -1 for t0}
but x(t) = {0 for t0}
are these signals equal?
Thanks for the video! The only thing that would've made it better would be to derive the x-even and x-odd formulas.
To test if the signal is even, start with x(-t) and see if you can manipulate it mathematically so it is the same as x(t). If you can, it is even. To test if it is odd, start with x(-t) and see if you can manipulate it so it is the same as -x(t).
Why are we decomposing unit step function? Isn't it an even signal if we see the graph? If it's not even signal then why so? Please do tell.
Well explained, but isn't ur definition for the odd component wrong?
how can I determine if the function is even or odd mathematically ??
It is very clear lecture!! Thx^^
i think there should be a negative as you have said ( without writing it down ) 05:52
what do you mean by "mathematically"?
Thankyou very much, i maybe never know if i keep trying to learn with my motherlanguage books!
"unit step function" is step function u(t) - u(t-1) i.e. step for 1 unit. 'step function' is (t>0). small but important distinction.
+t3hb0ss It's not unit step function that equals to u(t)-u(t-1). It is equal to unit impulse function. unit impulse function is [u(t) - u(t-1)] / 1 for example (in continuous).
+Gordon borostraw impulse function aka delta function is not u(t)..
Thanks so much
that's good ! thank you
ok very nice thanks alot
that was very helpfull for me
i cant than you enough
god i hate this class..soo boring!