ANOVA : TWO FACTOR WITH REPLICATION & TUKEY TEST ON EXCEL

Поділитися
Вставка
  • Опубліковано 11 січ 2025

КОМЕНТАРІ • 13

  • @archanasrivastava9842
    @archanasrivastava9842 6 років тому +3

    can you please also make a video showing how to indicate significance in two way ANOVA bar graph

  • @archanasrivastava9842
    @archanasrivastava9842 6 років тому +8

    I think Number of observation will be 12 in your case

    • @pmalik7404
      @pmalik7404  6 років тому +1

      Archana srivastava yes u r ryt there r 12observation in each set... Pls active whereever i use 15 for no.of observation

    • @ekaterinasokolova9345
      @ekaterinasokolova9345 4 роки тому

      @@pmalik7404 my apologies but what does it mean 'pls active'?

  • @cococnk388
    @cococnk388 2 роки тому

    Hello, must the rows in each sample be the same for a two way ANOVA with replication...?

  • @aidansweeney4095
    @aidansweeney4095 3 роки тому +2

    I believe you made a mistake when calculating the abs of the 0.25-1 comparison. It appears you have selected the 0.25 and 0.5 again

  • @chelseacerillo5470
    @chelseacerillo5470 5 років тому +8

    Why is your combination 4 and 2? You only explained why it's 4.

    • @chelseacerillo5470
      @chelseacerillo5470 5 років тому +1

      The formula for combination was [Number of groups (Number of groups -1)] /2

    • @tontush
      @tontush 5 років тому

      the 2 must mean pairs of combinations?

    • @전서준117
      @전서준117 3 роки тому +1

      @@chelseacerillo5470 I believe the function she uses calculates how many possible combinations of 2 groups there are; i.e. out of 4 groups, how many different groups of 2 can there be? (mathematics permutations and combinations)

  • @yvinceloh1022
    @yvinceloh1022 5 років тому

    Hi, can you make a video on Anova, two factor without replication too?

  • @mellviin8496
    @mellviin8496 4 роки тому

    hi...may i know what the formula u do at critical value?

    • @mellviin8496
      @mellviin8496 4 роки тому

      u said like log or something...i just dont get it