7. Randomization: Skip Lists

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  • Опубліковано 29 січ 2025

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  • @ruixue6955
    @ruixue6955 6 років тому +129

    0:26 today's lecture is about randomized data structure called skip list
    0:36 because it is randomized, we have to do probabilistic analysis
    4:01 context of skip list
    4:51 you can think of the skip list as beginning with a simple linked list
    5:09 first think of it as unsorted
    6:00 go ahead to think of it as sorted double-linked list
    6:20 you have a pointer to the front of the list 6:25 and it is double linked list
    6:27 Q: what is the complexity of search in a sorted double linked list
    7:30 sorting does not help with respect to the search
    8:10 say we have two sorted linked list
    9:30 there is not going to be another element on top of each element
    10:21 the other linked list is randomized
    10:38 the given example is the subway stops - 7th revenue express line in New York city
    12:15 basic notion of skip list
    12:53 it is really simple
    14:15 expression of the search algorithm
    16:00

    • @ufotofu9
      @ufotofu9 4 роки тому

      God bless you!

  • @christianrosado8838
    @christianrosado8838 3 роки тому +12

    Not only is he great at teaching, he is also super funny while at it lol Some quality teaching right here!

  • @neerajvijay9258
    @neerajvijay9258 4 роки тому +30

    My professor: skip lists hmmm, I am leaving it , do that in your assignment

    • @AchyutMujoo
      @AchyutMujoo 4 роки тому +16

      skip lists... hmm.. let us just *skip* this.

  • @Ludiusvox
    @Ludiusvox 5 років тому +24

    Thanks for the lecture. My university has a problem of having very limited curriculum for Upper division courses, and most of the staff is teaching lower division. So once I graduated with my bachelors degree I discovered OCW and I am just going to do independant self study and hopefully I can get some help from my school taking "special topics in computer science", over and over and hopefully I can gain higher proficiency than what is normally available to the University.

  • @주재빈-m2r
    @주재빈-m2r 2 роки тому +6

    Comparing skip lists to express lines is amazing.

  • @darley436
    @darley436 5 років тому +30

    this guy teaches better than all my prof ; wish i was an MIT student !!!

  • @alexvilloria26
    @alexvilloria26 4 роки тому +3

    Insertion in Skip Lists: 36:13

  • @ruantristancarlinsky3851
    @ruantristancarlinsky3851 3 роки тому +2

    Chalk board: Every Brilliant teacher's best friend

  • @cphoover11
    @cphoover11 7 років тому +20

    dishing out knowledge and frisbees!

  • @stevenjohnson9466
    @stevenjohnson9466 3 роки тому

    every once in a while the chalk makes a screeching noise and it's the most painful sound in the universe like someone dragging their bare nails on the chalk board.

  • @dush
    @dush 4 роки тому +3

    How i wish, my college professors were half this good with teaching

  • @louishector87
    @louishector87 6 років тому +3

    A Skip List needs a reference to 2 nodes, the previous and the next one. This helps positioning which gives the O(log n). Not gonna go deeper because it's based on Linked List and insert(e) function with a height level added to it.

    • @CodeAndLIfe
      @CodeAndLIfe 6 років тому

      Any idea how can I understand how log n is derived?

    • @cwash08
      @cwash08 5 років тому +3

      @@CodeAndLIfe simple way to think is that skip list structure looks like a binary (search) tree. Another way to think about it is that the number of remaining items to search by when going to other lists to search splits by a constant factor. This constant factor is the base of the log and the log is basically like an inverse of an exponent (repeated multiplication) . Each list we jump to divides the remaining number of inputs to search through.
      That's how I think of it

    • @markday3145
      @markday3145 3 роки тому +1

      I think of a skip list as a multi-way tree with randomized balance. The skip list is like a tree with forward/backward pointers (to the next/previous node at the same level) that turn each level of the tree into a doubly linked list. For new insertions, you randomly choose a height for the node.

  • @gouravbansal994
    @gouravbansal994 4 роки тому +1

    To reach 66, we will move to 72 and then backwards. That was a nice answer.

  • @taylorluttrell-williams6632
    @taylorluttrell-williams6632 3 роки тому +1

    great lecture; thanks for sharing!

  • @Dante3085
    @Dante3085 4 роки тому +1

    12:00 I don't understand why he avoids overshooting here. Since traveling on L1 is faster, going to 72 and then back to 66 should have the minimum amount of nodes, right ?

    • @patils22
      @patils22 4 роки тому +6

      "That will be another algorithm and its analysis will be more painful than the painful analysis which he is already doing for the skip list."

    • @benisrood
      @benisrood Рік тому +1

      The issue comes down to this:
      We have a complete and stativ picture of the subway stops for L0 and L1, so we *know* that overshooting and then going one stop back is faster.
      Your software/algorithm doesn't have this picture.
      How does a piece of software get that complete picture? The only way it can get it for any given moment in time would be by iterating through the complete list, at all levels. Once you've done that, you've lost all of the performance/optimisation advantages that a skip-list offers over a regular linked-list, in fact it's slightly slower 😂
      If computers could have a "bird-eve" view of a data structure, then they could just insert the value at the right place every time in one step. Unfortunately, there is no such magic.

  • @黃柏瑋-o5u
    @黃柏瑋-o5u 6 років тому +2

    Great course!

  • @boomerdev6122
    @boomerdev6122 2 роки тому +1

    Where does that constant (2) comes from 22:33
    2 Sorted Linked List -> 2 * Sqrt(n).
    Can anyone please explain

    • @egemensentin
      @egemensentin 2 роки тому +1

      Search cost is already given as |L1| + (|L0|/|L1|).
      |L1| is found to be sqrt(n). So is |L0|/|L1|, making the sum 2 * sqrt(n).

    • @danielghenghea7104
      @danielghenghea7104 4 місяці тому

      You can bound the cost |L1| + (|L0|/|L1|) = |L1| + n/|L1| by using AM-GM to get 2sqrt(n). For the cases of k lists you can also use AM-GM to minimize the cost.

  • @glithromal566
    @glithromal566 3 роки тому +1

    Skip list is kind of like van Emde Boas Tree, right?

  • @rustcpp
    @rustcpp 2 роки тому

    excellent video, thanks

  • @ГарикКубич
    @ГарикКубич 5 років тому +1

    That's great, thank you a lot!

  • @barile007
    @barile007 8 років тому +1

    7:17 - It's a[i] (a of i, not AFI) - Meaning, the index place in an a array

    • @BoredChinese
      @BoredChinese 8 років тому +11

      You do realize that that's the way he pronounces 'of'?

  • @cr74life96
    @cr74life96 7 років тому +3

    even i want a free frisbee

  • @efbdvtfbrt7027
    @efbdvtfbrt7027 3 роки тому

    7:11 walk of shame

  • @pradeepbalasundaram
    @pradeepbalasundaram 4 роки тому +4

    Frisebee for wrong answer.. where do you teach? .. lol

    • @fathirendrawan5846
      @fathirendrawan5846 3 роки тому +1

      Dude it's MIT, wrong answer is pretty rare there... I think lol

  • @hutonm2314
    @hutonm2314 3 роки тому

    it's good

  • @peterpalumbo1963
    @peterpalumbo1963 5 років тому +2

    How bout express to 72nd street then back to 66th street?

    • @Ulkesh007
      @Ulkesh007 4 роки тому

      Its Fails!

    • @Ulkesh007
      @Ulkesh007 4 роки тому

      Its an Exception case

    • @andrasviczian9262
      @andrasviczian9262 4 роки тому

      Thats what one of the students asked, he said we will not deal with going ahead than back, because it would be harder to analyze.

    • @cacojr5381
      @cacojr5381 4 роки тому

      the answer that you came up with which precondition is u has scan L0 already

  • @0cramoi
    @0cramoi 4 роки тому +5

    i said log n i want my frisbee :(

  • @rohitsharma-vf2tk
    @rohitsharma-vf2tk 4 роки тому +1

    Check out Erik's Video, I liked it better though the video quality is bad,
    ocw.mit.edu/courses/electrical-engineering-and-computer-science/6-046j-introduction-to-algorithms-sma-5503-fall-2005/video-lectures/lecture-12-skip-lists/

  • @amirkhan355
    @amirkhan355 4 роки тому +1

    The other teacher is a lot better.

  • @unnatisingh8569
    @unnatisingh8569 8 років тому +5

    The Skip list is not doublylinkedList rather it is a SinglyLikedList, every node has a pointer to the next element not to the previous one.

    • @madsboyd-madsen3463
      @madsboyd-madsen3463 7 років тому +5

      It's difficult to update a Skiplist efficiently without backpointers

    • @crazymigdet247
      @crazymigdet247 7 років тому +1

      every node has a pointer to the next element of the same height and the element below it.

    • @siddheshkandarkar235
      @siddheshkandarkar235 7 років тому

      every node is a quadnode in skiplist..correct me if im wrong.

    • @tratbagd4500
      @tratbagd4500 5 років тому +1

      It has to be a doubly linked list, other wise you would have disconnections between the levels as a node would not be able to be connected to two other nodes; the next one and the one at the level below.

    • @abhishekshah5961
      @abhishekshah5961 5 років тому

      @@siddheshkandarkar235 what is a quad node?

  • @peterpalumbo1963
    @peterpalumbo1963 5 років тому +2

    How bout express to 72nd street then back to 66th street?