Disadvantages of Semaphores
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- Опубліковано 16 вер 2024
- Operating System: Disadvantages of Semaphores
Topics discussed:
1. Disadvantages of Semaphores.
2. Busy Waiting.
3. Modification of wait() and signal() operations.
4. Deadlocks and Starvation.
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Axol x Alex Skrindo - You [NCS Release]
#OperatingSystemByNeso #OperatingSystem #ProcessSynchronization #Semaphores
stundent starvation for os ends here , indeed such aa gemmm 🙌🙌🙌🙌🙌🙌🙌🙌🙌🙌🙌🙌🙌🙌🙌🙌🙌🙌🙌🙌
1- Semaphores belongs to the non-active waiting solutions for synchronization .
passive waiting solutions : semaphores , locks , cs , monitor .
2 - the solution you discussed , we took it in college as the semaphore form directly .
l enjoyed the tutorial, so insightful and well presented. Thank you!!
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Please unlock rest of the chapters like deadlock, virtual memory etc. so that we can complete the course.
Hi, you can access them on our website/app after getting the Neso Fuel.
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Merci beaucoup.
It is not "need for busy wIting" it should be "overcome the problem of busy waiting".
I think the deadlock is not about only the semaphores with waiting quaes. It can also happens with binary semaphores if we implement them in a same way like in the video, am I right ?
I guess so.
No, deadlock can not happen in a binary semaphore, a binary semaphore is like a mutual exclusion algorithm.
No, bcz binary semaphores only for 2 processes
Nice sir❣️❣️❣️❣️
This busy waiting for all solution you discussed all have this busy waiting.
thats what i think
@@minhhoangcong9155 Indeed i didn't understand the waiting-queue solution to resolve busy waiting problem. It seems to me that the busy waiting exists always.
Deadlock:
Resource1
Assigned to Waiting for
Process1 Process2
Waiting for assigned to
Resource2
Please upload atleast 2 videos for a day sir
End on ONE NIGHT RUN
I didn't understand what is two semaphore S & Q means here
Why process need two semaphore 🤔🤔🤔🤔
Each resources has its own semaphore. So think it as P0 is first trying for resource S and P1 is trying for Resource Q.After they get them P0 will wait for Resource Q which is acquired by P1 and P1 will wait for resource S which is acquired by P0 which is a deadlock condition.Hope this helps.Correct me of I am wrong
@@shaziasamreen8584 cool
@@shaziasamreen8584 nice
👍👍