Thank u so much. This video helped me tremendously. This channel is a life saver! Now I can get full marks in my exam as I was a bit confused with this concept of median in frequency table.
Dude, this is awesome, I can't figure out how to find it for weeks. I watched a lot of videos but it explained too complicated. Thank you so much, it is actually simple
Hi - if you have three people A, B and C... then the person in the middle (median) is B. Notice there are 3 people and the "position of the median" is the 2nd person. That is found by doing 3 + 1 = 4 then divided by 2, to give the 2nd person. If there were 5 people A, B, C, D and E. The position of the median is the 3rd person. 5 + 1 = 6 6 divided by 2 = 3 If there were 4 people A, B, C and D. The position of the median is the 2.5th person. 4 + 1 = 5 5 divided by 2 = 2.5 So to find the exact position of the median, you need to add one, then divided by 2. However there are some situations were you may not "add 1," for instance when using a cumulative frequency curve. The reason for that is it is "grouped" data and it is an estimate anyway. Does that help?
I didn't understand my teacher's explanation in 40 minutes. This video taught me in 3 minutes
my teacher didn't even explain
My exam is this month and I'm revising with your videos.
Your methods are so very helpful! Thank you sooo much
+Tanya Y Thanks very much! I really hope you ace your exam
corbettmaths dude thanks sooooo much this helped me a Lott!
my test is in less than 10 hours away!!!
I had a assessment in a day and didn't know what to do this video helped me a lot.
So glad it helped!
Thank u so much. This video helped me tremendously. This channel is a life saver! Now I can get full marks in my exam as I was a bit confused with this concept of median in frequency table.
Thanku it is good video
Thanks, i got kinda confused when my teacher taught me but you made it easier to understand. Got a maths chapter test next week so thanks again.
1:24 is the second method, the one I’m using. Thanks!
OMG thanks you so much your formula is soooo easy to remember compared to my teachers formula where you're BOOM n+1 over 2 thank you thank you so much
Finding the median by finding the category first, thanks this helped a looooooot
Thank you so much. Got full marks from your vid
Amazing!! Well done!!!
maths exam tmrw hope i do well tysm ur vids really help me
I needed this for my psychology summer work! Thank you 😊
Thank you ,Thank you i was searching for a good explanation for median in frequency table and found it on your channel .
This is great thank you for the help for an exam tomorrow !! :))
MyFlights me too
Thanks Alot sir your video helped me.
You are most welcome
I like how the advert was a maths advert 😂
OMD this guy saved my life i was so confused in class now it makes so much sense 😅
FR
Cheers for such a helpful uniform and video.
omg! thank u so much ! was struggling with this preparing for gre .. its pretty easy now
Woww, very simple and understandable!
So glad the video was useful 😀
thanks so much x helped for a maths test tomorrow!!
Thanks alot!
👍
thank you so much, this cleared the confusion i had with this topic
Dude, this is awesome, I can't figure out how to find it for weeks. I watched a lot of videos but it explained too complicated. Thank you so much, it is actually simple
Thanks boss!
👍
thank you very much it really helped me understand
Thanks so much this really helped for my maths test!
Oooooh thank you so much sir,you saved me life
It helps a lot. ! Thanks god bless you!
Thank a lot, best example on the internet :)
Yh this is a very useful video. My teacher tried to show me a video and it didn't work as well as ur one
I love you you explain it soooooooooooooooooo well and its so easy thnx XD
thnxxx! I have my math mock tomorrow
What did you get?
Thank you helped a lot! ;)
Thanks, this helped!
What if the median is 8.5th...would it be 12 or 13?
thanks brother appreciate ya
This video was very helpful compared to n+1 over 2 the only thing is I wish u would wright a bit bigger
why do you add 1?
Hi - if you have three people A, B and C... then the person in the middle (median) is B. Notice there are 3 people and the "position of the median" is the 2nd person. That is found by doing 3 + 1 = 4 then divided by 2, to give the 2nd person.
If there were 5 people A, B, C, D and E. The position of the median is the 3rd person. 5 + 1 = 6 6 divided by 2 = 3
If there were 4 people A, B, C and D. The position of the median is the 2.5th person. 4 + 1 = 5 5 divided by 2 = 2.5
So to find the exact position of the median, you need to add one, then divided by 2.
However there are some situations were you may not "add 1," for instance when using a cumulative frequency curve. The reason for that is it is "grouped" data and it is an estimate anyway.
Does that help?
corbettmaths Thanks so much this really helped me :)
corbettmaths
can you make the video with the situation that you dont have to add one? and explained it WHY you have to add one????
Cedric Suriapraja I'm putting together a video now to explain when you "add 1" and when you usually "don't add 1"
corbettmaths
Thanks man good job :)
great so helpful
Very nice
Thanks man
No problem 👍
THANK YOU!!!!
Thank you
Thanks vvvvvvvvvvv much
Thanks
lool that is so smart
Thanks, this helped!
Helped me a lot
Thanks
Thanks
Thanks