the derivative with respect to t of e^(5t) is 5 * e^(5t) right. So derivative with respect to t of e^(jwt) is jw * e^(jwt). And the double derivative will be jw*jw *e^(jwt) which is -w^2 e^(jwt). Just e^(jwt) is not mentioned thatsall.
Making the concept more complicated to understand. No clear explaination. Whatever is being written on the board, 50% invisible due to overwritten captions, 50% unreadable
Thank you a lot for all the great explanations.
watch at 1.75x
What is the I here ? Intevsivity ?
Intensity
Endoscope ≈ optical fibre
how did the derivative of time period signal became 'jw' and second deriv as -w^2..... 35:56
j^2 = j . j = (-1)^1/2 . (-1)^1/2 = -1
yeah, no clear explaination.
It comes from electrodynamics. It is a prerequisite for this course.
the derivative with respect to t of e^(5t) is 5 * e^(5t) right. So derivative with respect to t of e^(jwt) is jw * e^(jwt). And the double derivative will be jw*jw *e^(jwt) which is -w^2 e^(jwt). Just e^(jwt) is not mentioned thatsall.
My Thoughtonics is based on superior signal thought
Anyone take this course on 2021 plz reply.
Interfernce plot is wrong.
Making the concept more complicated to understand. No clear explaination. Whatever is being written on the board, 50% invisible due to overwritten captions, 50% unreadable
You can turn off captions