Im a Mechanical Designer and I dont do Math...... so I solved this question in AutoDesk Inventor 3D modelling program with a much more satisfying answer. The length of X is 0.586. It took me half as long as this video. Cheers
i found it simpler to call the segments a & s, use Pythagoras to establish that s^2 = 2a^2. Rearrange to make a the subject and the substitute into s + a = 1 as is given the question. Then just solve for s
That's an actual question of an oxford mathematics admissions test, but the original question is only words, so you have to come up with the scheme, which is the actual harder part 😮😮😮
Fast non-complicated way. Understanding basic geometry the length must be higher than 0.5. That reduces the options to B and D. Again with an understanding of the shape D at 0.71 is clearly too much. B at 0.59 must be the solution. I would get a fail grade for this correct answer.
Im a Mechanical Designer and I dont do Math......
so I solved this question in AutoDesk Inventor 3D modelling program with a much more satisfying answer.
The length of X is 0.586.
It took me half as long as this video.
Cheers
Nice haha!
i found it simpler to call the segments a & s, use Pythagoras to establish that s^2 = 2a^2. Rearrange to make a the subject and the substitute into s + a = 1 as is given the question. Then just solve for s
There is no way such a simple math is question for Oxford Entrance Exam. How do you know this is Oxford q?
That's an actual question of an oxford mathematics admissions test, but the original question is only words, so you have to come up with the scheme, which is the actual harder part 😮😮😮
So easy.
Let x=1-a be the side of the six-sided shape.
So by Pitagoras, x=a*sqr(2)
Then (1+sqr(2))*a=1 ... a=sqr(2)-1 and x= 2-sqr(2), as x=1-a.
Fast non-complicated way. Understanding basic geometry the length must be higher than 0.5. That reduces the options to B and D. Again with an understanding of the shape D at 0.71 is clearly too much. B at 0.59 must be the solution.
I would get a fail grade for this correct answer.
Pretty close, its 0.586 calculated in AutoDesk Inventor 3D modelling program.
X = sqrt2(1-x).
Solve
Pythagoras => SQRT(2) * (1 - x) = x => x = 2-SQRT(2).