Very much appreciated the for the good design and the behavior of the materials that feeding the entire conveyor system. This preview helps to inter act with the maintenance that will work on that specific design. Hence what we can only predict after this kind of design is installed in many kind industrial process lies with in the person that will assign to work with the equipment. Innovation is more than a commitment when we go for a long term productivity and efficiency of the equipent. Its really a great help to recap birds eye view of the design and movement of this kind of design conveyors as you go along your way in maintaining the equipment run effecient and looking for less maintenance.
GREAT INFORMATION thank you!!! I have a question. L the leght of the conveyor Is it the totally leght such the load side as the return side or is it just the leght from center of the drive pulley to the center of the tail pulley?
Dear Norwin, Length should be considered to be the distance from the centerline of the tail pulley to the centerline of the head pulley, assuming material is loaded near the tail and discharged near the head. Mike
MIKE LOCHE! There's a name I haven't heard in a while. I hope you are doing well Mike. We posted a one hour UA-cam video on how to use our bulk calculation program, entitled Webinar #102 ua-cam.com/video/0-Vz5GrFYs4/v-deo.html
@@rulmecacorporation4596 Wonderful to hear from you. So, I sold half of my business to Rema in 2013 and the other half in 2019. It would be great for you guys to get a hold of Ramon regarding your product. I'm out here in Columbia Tn. now. Following my youngest son at a church thebelongingco.com Hoping to get the rest of the grandkids out here. Is there an email that we can correspond through? I'd like to communicate with you regarding further distribution, etc.?
I appreciate your help in providing me a brief equation or rule of thumb to calculate the specific energy consumption as Kwh/Mt/Km , belt speed = 2.5 meter per second, trough angle = 30 , surcharge = 25, material = excavated soil (sand) , lump size less than 150 mm , density =1,550 kg/M3 , belt length = 5 Km (multiple flights ) , Flow = 3500 to 4,000 Mt/Hr , Route inclination= zero inclination, Width = 1,200 mm , considering these inputs , how much electricity will be consumed in electrical motor as Kwh per metric ton (Weight) per Km (distance)
Dear Carlos, We're happy you like the video. In our power calculation program, we assume that conveyors are near the surface of the Earth. So, pound-force and pound-mass may be considered equal for our purposes. Our power calculation software, to which you are welcome, uses slugs when we define mass in our equations. I hope that helps.
I appreciate your help in providing me a brief equation or rule of thumb to calculate the specific energy consumption as Kwh/Mt/Km , belt speed = 2.5 meter per second, trough angle = 30 , surcharge = 25, material = excavated soil (sand) , lump size less than 150 mm , density =1,550 kg/M3 , belt length = 5 Km (multiple flights ) , Flow = 3500 to 4,000 Mt/Hr , Route inclination= zero inclination, Width = 1,200 mm , considering these inputs , how much electricity will be consumed in electrical motor as Kwh per metric ton (Weight) per Km (distance)
I am a huge fan of rumelca material. Thank you guys.
We are happy so many conveyor designers find our free power calculation program useful. We appreciate all of your comments.
Very much appreciated the for the good design and the behavior of the materials that feeding the entire conveyor system. This preview helps to inter act with the maintenance that will work on that specific design. Hence what we can only predict after this kind of design is installed in many kind industrial process lies with in the person that will assign to work with the equipment. Innovation is more than a commitment when we go for a long term productivity and efficiency of the equipent. Its really a great help to recap birds eye view of the design and movement of this kind of design conveyors as you go along your way in maintaining the equipment run effecient and looking for less maintenance.
GREAT INFORMATION thank you!!!
I have a question.
L the leght of the conveyor
Is it the totally leght such the load side as the return side or is it just the leght from center of the drive pulley to the center of the tail pulley?
Dear Norwin, Length should be considered to be the distance from the centerline of the tail pulley to the centerline of the head pulley, assuming material is loaded near the tail and discharged near the head. Mike
@@rulmecacorporation4596 a lot of thanks!!
@@norwingradisrivera1368 It's our pleasure to help in any way we can.
This is absolutely great shares!
You are very welcome. If you have any specific questions, please ask us.
Mr. Bear Whip. It's good to see you , and, that your expertise is still valuable. Please let me know how to use the program.
MIKE LOCHE! There's a name I haven't heard in a while. I hope you are doing well Mike. We posted a one hour UA-cam video on how to use our bulk calculation program, entitled Webinar #102
ua-cam.com/video/0-Vz5GrFYs4/v-deo.html
@@rulmecacorporation4596 Wonderful to hear from you. So, I sold half of my business to Rema in 2013 and the other half in 2019. It would be great for you guys to get a hold of Ramon regarding your product. I'm out here in Columbia Tn. now. Following my youngest son at a church thebelongingco.com
Hoping to get the rest of the grandkids out here.
Is there an email that we can correspond through? I'd like to communicate with you regarding further distribution, etc.?
Hi there. What's the average cost of a 50-60ft mobile belt conveyor for hauling dirt away?
I appreciate your help in providing me a brief equation or rule of thumb to calculate the specific energy consumption as Kwh/Mt/Km , belt speed = 2.5 meter per second, trough angle = 30 , surcharge = 25, material = excavated soil (sand) , lump size less than 150 mm , density =1,550 kg/M3 , belt length = 5 Km (multiple flights ) , Flow = 3500 to 4,000 Mt/Hr , Route inclination= zero inclination, Width = 1,200 mm , considering these inputs , how much electricity will be consumed in electrical motor as Kwh per metric ton (Weight) per Km (distance)
Thanks for this information, it will be great in metric units also...
You are welcome. Our International Group is finalizing a metric version. It should be generally available within one year.
The metric version is now available to the public. Please provide your email address and I will send a link to the program
@@rulmecacorporation4596 rajsekcae012@gmail.com
@@rulmecacorporation4596 nguyendangthelisemco@gmail.com
@@rulmecacorporation4596 harmusar@gmail.com
sir,can you please use Kg rather than pounds
Thanks for information ❤ but I have few doubt
How may we help you resolve your doubts?
I had go threw the rulmecca problem solving section but I haven't found any details about skirt board in equation, how friction act on the conveyor
@@rizanmd9334 ua-cam.com/video/5QJjy67Z-NM/v-deo.html please watch this video
@@rizanmd9334 ua-cam.com/video/T7mgqj3bXSA/v-deo.html please watch this video too
Great video! just one question: lbs units in mass or force?
Dear Carlos, We're happy you like the video. In our power calculation program, we assume that conveyors are near the surface of the Earth. So, pound-force and pound-mass may be considered equal for our purposes. Our power calculation software, to which you are welcome, uses slugs when we define mass in our equations. I hope that helps.
HOW TO CHOOSE WHAT BELT TYPE
Outstanding Explanation, have couple of questions. Can you please share your email I'd.!!
Sir hindi milenga kya
Hello , are you come here
I appreciate your help in providing me a brief equation or rule of thumb to calculate the specific energy consumption as Kwh/Mt/Km , belt speed = 2.5 meter per second, trough angle = 30 , surcharge = 25, material = excavated soil (sand) , lump size less than 150 mm , density =1,550 kg/M3 , belt length = 5 Km (multiple flights ) , Flow = 3500 to 4,000 Mt/Hr , Route inclination= zero inclination, Width = 1,200 mm , considering these inputs , how much electricity will be consumed in electrical motor as Kwh per metric ton (Weight) per Km (distance)
Dear sir, We will be happy to help you. Please provide your name and email address.
Thanks,
Mike