Complement in Conditional Probability | P(A' | B) = 1 - P(A | B)

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[@alikhaled844]

thanks !!

[@Daniel-do2mh]

Thank you!

[@DrMathaholic]

Welcome 😊

[@FakeRaven621]

Thank you

[@DrMathaholic]

Welcome 😀

[@jayavaradhanp8405]

Sir plz take linear transformation and continue real analysis

[@DrMathaholic]

Hi
Lecture on linear transformation can be found in this Playlist::
Linear Algebra: ua-cam.com/play/PLwaXU7G6UrbfMflgIfLgka0k9oRJa9o24.html
After probability, i will try to start real analysis ..😊 thanks for suggesting.

[@abdurrahmanlabib916]

The thumbnails r hilarious 😂

[@DrMathaholic]

😅🤣🤣

[@rachanamandarachana4353]

Then what is p(A/B')

[@DrMathaholic]

One has to use standard definition P( A intersection B')/P(B')

[@user-bx6cv6es8x]

Sir can u tell me the formula for probability of a complement given probability of b complement i.e,
(I need the formula for P[A'|B'])

[@user-bx6cv6es8x]

Can u reply me in the comment section the formula I need time now sir please sir

[@DrMathaholic]

@@user-bx6cv6es8x P(A'|B')= P(A' intersection B')/P(B')= P( (A union B)' )/1- P(B) = [ 1 - P(A union B)] / 1-P(B).
You can use this formula:
[ 1 - P(A union B)]/[1-P(B)].
Hope it helps

[@user-bx6cv6es8x]

@@DrMathaholic thank you sir

[@user-bx6cv6es8x]

@@DrMathaholic sir for
P[B'|A']=[1-P(A union B)]/[1-P(A)]
Is thus the formula or is there another formula

[@DrMathaholic]

@@user-bx6cv6es8x this is correct. There might b other versions, I don't know. But this is correct

[@rupertjames41]

Thank you!

[@DrMathaholic]

Welcome:)