Physics Solution: Four Atwood Machine Problems

Поділитися
Вставка
  • Опубліковано 29 лис 2024

КОМЕНТАРІ • 10

  • @christisrader7821
    @christisrader7821 2 роки тому +4

    Love the idea of having so many situations in one space. I am going to do this with my classes, have different groups whiteboard the different problems. I always love them to see the patterns in the acceleration equations....g(m1-m2(?))in the numerator and (m1+m2) always in the denominator. Physics is beautiful, I am inspired.

  • @hamiltonclough4616
    @hamiltonclough4616 Рік тому +1

    Super helpful to memorize how to associate different atwoods with different acceleration equations, thank you!

  • @onlyonecjb001
    @onlyonecjb001 2 роки тому +3

    Thank you for the clear explanations on this video. Super helpful.

  • @colchi2547
    @colchi2547 2 роки тому +1

    I really like your content, it is extremely helpful. I was thinking of watching your playlists in order, is there a specific order I should follow? Thank you

    • @DotPhysics
      @DotPhysics  2 роки тому

      I have lots of stuff - but if you are looking for some introductory physics-level material, here's a playlist for that (it's at the algebra-based level)
      ua-cam.com/play/PLWFlMBumSLSZVxXn1PQkxje42fhDdErhP.html
      If you are looking for something else, just let me know.

    • @colchi2547
      @colchi2547 2 роки тому

      @@DotPhysics thank you very much! I am actually looking for a Calculus Bases approach. I am currently watching Walter Lewins lectures but I am using your videos to practice

  • @williamperez-hernandez3968
    @williamperez-hernandez3968 2 роки тому

    In problem 4, it was assumed the body on the ramp accelerates up the ramp and assigned a= positive. This is confirmed when the computation gave a=+1.26 m/s^2. If the value gave negative, say a= - 1.4 m/s^2, then the body on the ramp accelerates down the ramp. Must we do the whole problem again using that new knowledge? Answer: NO! We just use the absolute value of our calculation for a. The reason this works is because changing a to -a in our equations does not change the absolute values.

  • @fizixx
    @fizixx 2 роки тому

    It was fun!

  • @fernandodominguez1
    @fernandodominguez1 2 роки тому

    How can g= m/kg be the dame as g= m/ (s*s) ? . But I enjoy very much your lectores.