@@sensoftgpr I´m working with a radar made in Chile that works pretty well, now I´m just studyin the results I have with 2 dipoles of 11m (I can determine the thickness of the glacier while I´m walking through the glacier)
How do I best set my dielectric in clay? Or with water? In part one you said that people that say its not possible to locate when soil is saturated are wrong. How would you go about getting that contrast to locate utilities in those conditions?
Wouldn't the one way travel time be multiplied by two to represent it going through the pipe twice, not divided? I'm not the best at math so I am probably wrong.
Austin Garrison The GPR signal in the data we collect goes through the diameter of the pipe twice. That is two-way travel time. We want to calculate the diameter of the pipe, so we only need the one-way travel time. Therefore, we DIVIDE the two-way travel time by two to calculate the one way travel time
We don’t have any webinars that specifically discuss fractures in rock fractures, but fractures are often strong GPR reflectors because of the contrast between the rock and the air or water in the fracture. They are also somewhat planar, so you get a response like a boundary.
Geat, waiting for new webinars regarding GPR :)😍
Great videos, I´m working in glaciers (Chile) and your classes are great! Thanks for sharing
Thank you for watching our videos. Are you using Sensors & Software products in your project?
@@sensoftgpr I´m working with a radar made in Chile that works pretty well, now I´m just studyin the results I have with 2 dipoles of 11m (I can determine the thickness of the glacier while I´m walking through the glacier)
What a lectures, thanks Prof.
Thank you so much excellent video
How do I best set my dielectric in clay? Or with water? In part one you said that people that say its not possible to locate when soil is saturated are wrong. How would you go about getting that contrast to locate utilities in those conditions?
Thank you so much
Wouldn't the one way travel time be multiplied by two to represent it going through the pipe twice, not divided? I'm not the best at math so I am probably wrong.
Austin Garrison The GPR signal in the data we collect goes through the diameter of the pipe twice. That is two-way travel time. We want to calculate the diameter of the pipe, so we only need the one-way travel time. Therefore, we DIVIDE the two-way travel time by two to calculate the one way travel time
Is there any material that could help me to interpret rock discontinuities (fractures)?
We don’t have any webinars that specifically discuss fractures in rock fractures, but fractures are often strong GPR reflectors because of the contrast between the rock and the air or water in the fracture. They are also somewhat planar, so you get a response like a boundary.
Гениально!
Nice thank you so