Lec 15: Ampère's Law | 8.02 Electricity and Magnetism, Spring 2002 (Walter Lewin)
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- Опубліковано 12 гру 2014
- Ampère's Law - Solenoids - Revisit the Kelvin Water Dropper - Midterm Evaluation
This lecture is part of 8.02 Physics II: Electricity and Magnetism, as taught in Spring 2002 by Dr. Walter Lewin at MIT.
This video was formerly hosted on the UA-cam channel MIT OpenCourseWare.
This version was downloaded from the Internet Archive, at archive.org/details/MIT8.02S02/.
Attribution: MIT OpenCourseWare
License: Creative Commons BY-NC-SA 3.0 US
To view a copy of this license, visit creativecommons.org/licenses/b....
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This UA-cam channel is independently operated. It is neither affiliated with nor endorsed by MIT, MIT OpenCourseWare, the Internet Archive, or Dr. Lewin.
Professor Walter Lewin is truly a gift to humanity. His lectures are the most captivating and Interesting.
It made clear to me what seemed so hectic. ♥
Ditch my college lectures to watch him instead and now getting perfect exam scores.
Thanks Professor
Sincere apologies on behalf of gravity, droplets.
Why we take the x-component of B and why y-component cancels?
because using diametrically oppposite dl would give another {db}y opposite to before dby therfore both cancels out thats y only x component is considered
what book is he using?
+Riken Maharjan he has only his notes, but i recomend you the Serway Jewet vol. 2 it's a very good one
You can NOT stop the video there, are you serious? :(
I always find it amusing how he uses the phrase "physics works." Well nature is just the way it is, and physics is a description of nature validated by empirical study. There is nothing about physics that "works," rather we should say that this physical theory is consistent with nature. If we were instead speaking of the mechanical instrument constructed exhibiting the desired behaviour and hence saying that it "works," then that is engineering, not physics.
it isn't 2πr. its 2R
why? what he said is perfectly correct.
It's not 2pi(r) it's just 2 (r)
+Jessica W yea exactly!!
that is for the circular current loop
here in this case he tells about the straight current wire into the board
that is for the circular current loop
here in this case he tells about the straight current wire into the board
2pi*r is correct because he is using mks system of units. If you use the absolute Gauss's system, you have the line integral equal to 4*pi/c * I. In Gauss's system, it would be just 2*r.
yes jessica w as x becomes 0