Accenture 9th August Coding Questions | Accenture Actual Questions
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amazing solution for 1st question
1st and 2nd questions are leetcode problems.Good explanation.
Yes, Accenture has started asking leetcode questions now
@@harshitdixit9285 is it oncampus or offcampus
May i know about the level of difficulty of questions? i found first question. but i didnt encounter the rest?
What is the leetcode question number
@@RAKESH-wt8ee202(Happy number) and 319(Bulb switcher)
Instead of pseudocodes what they are asking?
Please reply sir !
sir you are doing a great job.
keep continue sir
the first question came in my exam, however they did not give the condition for ith round..
Ohh achaaa
So agar ek bhi question nhi hua toh bhi select hote kya
Bro were the coding questions same for everyone?
i think for 1 question we can write solution as
// Online C++ compiler to run C++ program online
#include
using namespace std;
int solve(int n)
{
vectorans(n,0);
int i=0,j=1;
while(i
Just take the square root of n. You will get the desired answer.
Thank you sir, please upload more videos ❤
easiest solution for happy number
def isHappy(self, num: int) -> bool:
count = 0
if num == 1:
return True
while(num != 1):
sum = 0
for i in str(num):
sum += int(i) * int(i)
num = sum
count += 1
if num == 1:
return True
break
if count > num:
return False
break
Workable code.. U may try..
public class Main {
public static void main(String[] args) {
int n = 19; // 1, 7, 10, 13, 19, 100
int sum = 0;
while (n > 0) {
int rem = n % 10;
sum += rem * rem;
n = n / 10;
}
while (sum != 1 && sum != 4) {
int tempSum = 0;
while (sum > 0) {
int rem = sum % 10;
tempSum += rem * rem;
sum = sum / 10;
}
sum = tempSum;
}
if (sum == 1) {
System.out.print("Happy number");
} else {
System.out.print("Not happy number");
}
}
}
The algorithm using set is not correct , It's squaring the number itself rather than of squaring its digits
The Correct Algorithm is (In Java)->
Set usedIntegers = new HashSet();
while (true) {
// Find the sum of squares
int sum = 0;
while (n != 0) {
sum += Math.pow(n % 10, 2.0);
n = n / 10;
}
// If sum is 1, return true
if (sum == 1) return true;
// Else, the new number is the current sum
n = sum;
// Check if we have already encountered that number
if (usedIntegers.contains(n))
return false;
usedIntegers.add(n);
}
What do you mean by pseudocode removed 100 percent?
There is no pseudo code in the exam now
@@ganeshbagal072
Instead of pseudocodes what they are asking?
Please reply
@@ganeshbagal072 can you please share the coding qns that were asked
@@aeroabrar_31I have attend yesterday exam..
There was no pseudocodes..
@@ganeshbagal072 what do you mean by round number, can you elaborate the problem statement?
very good explanation
17:30 I have one more method to solve this question. We can run an outer loop with flag = true. Then We run another loop to add squares of every digit and we can validate whether the sum is less than 10 if yes break the outer loop with flag - false. Then check whether num is happy or not
I tried answer for 1st question after 4 months of coding gap.
import java.util.Scanner;
public class Main
{
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int number = sc.nextInt();
boolean result = false;
for(int i=0; i
Thank you🙏❤
Sir do we have syllogism and data suffiency in Accenture syallabus
yes
@@mayankbisht674 hii bro if you have written Accenture exam can u tell me how many questions are asked from datasuffiency and in verbal ability what are the questions they asked
@@abc-ym4zs I've got my exam tommorow
class Solution {
public:
bool solve(int n)
{
if(n==1)
{
return true;
}
if(n>1&&n0)
{
int rem=n%10;
res+=rem*rem;
n=n/10;
}
return solve(res);
}
bool isHappy(int n) {
return solve(n);
}
};
It would be of great help if you can mention algo or pseudocode in words
This question are for which role kindly write full form
ASE ROLE
Is 19^2 and 1^2 + 9^2 same?
No
no
Now in upcoming exam of Accenture there will be no pusedo code
Why so?
Yes . Atleast in on campus
today i have attended . pseudo codes , network ,ms office questions were there
Hey can you tell me how difficult are the questions from Network Security and Cloud?
@@ragavarthini2377
Tomorrow I will be having my exam , can we connect?@@ragavarthini2377