Feynman's Technique DESTROYS this Tough Integral

[@mathnerd5647]

Tremendous video!!!

[@drpkmath12345]

Thanks a lot my friend haha👍👍👍

[@MrGLA-zs8xt]

Fantastic video professor

[@drpkmath12345]

Thanks a lot my friend for your support👍👍👍

[@domedebali632]

Great video prof.

[@drpkmath12345]

Thanks a lot my friend👍👍👍

[@okoyoso]

Would it also work if you changed the paramater x into tx inside the original tangent integral instead of doing a substitution first?

[@drpkmath12345]

Yup my friend! Thanks for sharing👍👍👍

[@okoyoso]

@@drpkmath12345Wait I think you get a x^2 csc(tx) integral if you do that. I think the substitution might be necessary to get a nicer derivative wrt t

[@Min-cv7nt]

I like Feynman trick

[@drpkmath12345]

Same here my friend haha👍👍👍

[@humester]

Too much pulled out of the hat. Unless you already know all this, it explains nothing.

[@drpkmath12345]

If you dont know about it, you better just learn instead of giving some attitudes. I clearly said I used Feynmans Technique on the title. Normal people would try learning something they dont know, not merely complain about not knowing about it.

[@humester]

@@drpkmath12345 Sorry! Did not mean to offend you. I was merely disappointed in that I was expecting you to explain the technique as you went along so that I might learn and understand.

[@iqtrainer]

@@humesterFeynman trick is to introduce a new parameter, get derivative of it using the parameter, and integrate it in easier terms like Dr PK did

[@okoyoso]

You can motivate the tangent substitution as a way to get rid of the trig functions. You still get an arctan, but that’s not bad because its derivative is an algebraic function.
The main idea behind the Feynman technique is “what if I could differentiate just part of the integrand to simplify the integrand and then integrate the answer to get my result?” Introducing a new parameter t accomplishes this.
The rest is just standard techniques.