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I'm very thankful for the Cardano's method tutorial! I was struggling to understand it but this video really cleared that up for me!
x^3 = 6 + xx^3 - x - 6 = 0x = 2
x^3 = 6 + xx^3 - x = 6x (x^2 - 1) = 6x (x+1)(x-1) = 6(x-1) x (x+1) = 6 --> 3 consecutive numbers6 can be decomposed onto 2 * 3 and also to 1 * 2 * 3 triviallyx = 2 is a valid solution
If this was on the MIT entrance exam, I would not be gettimg into MIT.
I can see recursion here so let's define recursive sequence and calculate the limit
2
I'm very thankful for the Cardano's method tutorial! I was struggling to understand it but this video really cleared that up for me!
x^3 = 6 + x
x^3 - x - 6 = 0
x = 2
x^3 = 6 + x
x^3 - x = 6
x (x^2 - 1) = 6
x (x+1)(x-1) = 6
(x-1) x (x+1) = 6 --> 3 consecutive numbers
6 can be decomposed onto 2 * 3 and also to 1 * 2 * 3 trivially
x = 2 is a valid solution
If this was on the MIT entrance exam, I would not be gettimg into MIT.
I can see recursion here
so let's define recursive sequence and calculate the limit
2