How Does an Aperture Stop Influence Third Order Lens Aberrations? A Tutorial using Excel

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  • Опубліковано 27 жов 2024

КОМЕНТАРІ • 4

  • @yadongwang8629
    @yadongwang8629 Рік тому +4

    I cannot recommend highly enough of this channel, and this optical design contents. I found its a very good complimentary with the Pencil of Rays and OpticalRealm for geometric optics and lens study.

    • @stephenremillard1
      @stephenremillard1  Рік тому +1

      Thank you for the recommendation. I am a mere a novice by comparison to the others.
      In addition, I would like to recommend www.youtube.com/@DesignOpticsFast

  • @stephenremillard1
    @stephenremillard1  Рік тому +2

    Typo in the slide at 6:29. The stop shifted coma has A (the marginal ray invariant), not Abar (the chief ray invariant) in the denominator. The correct expression is S_II*=(Abar*/A)S_I. The slide in the video shows S_II*=(Abar*/Abar)S_I, which is an error. The spreadsheet calculation is fine. It was just a typo in this PowerPoint slide.

  • @yadongwang8629
    @yadongwang8629 Рік тому

    Hello Stephen,
    Last night I was constructing my excel table and comparing with your sheet. I notice that for both stop (front and back) sheets, the Lagrange Invariants for the lens (front and back) are different slightly. I recall this quantity represents the conservation of (information/energy) in the optical system which should remain unchanged moving through the system. I refer to your Petzval curvature video the single lens has identical Lagrange invariants...
    currently, my invariants are the same for with and without stop. My doublet sheet is not ready, so I cannot say my results...The presence of the stop I think should be the factor that causes the gaining/lossing info during the ray propagation? Although, my results are very close to yours compared to the ZEMAX benchmark.
    Have a nice day! Waiting for your Astigma and Distortion videos!!