Area of part of a circle / form 2
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- Опубліковано 9 жов 2024
- Hi! this video explains how to calculate the area of part of a circle. You will find, how to calculate:
1. Area of a sector.
2. Area of a triangle
3.Area of a segment
4. Area between two intersecting circles.
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Thanks alot I was tought this today bt I didn't understand well bt you helped me
Am glad it helped! Please share with friends and classmates 🙏
Thanks alot you're the best
Thank you 🙏
❤❤ awesome iam getting iam going to practice it over and over again until my get get blown
That's the spirit!👍👍
Teacher is it a must you times by 2 in size of an angle
Hello! We times by 2 since angle APB is 2 times theta. Please let me know if this helped
Thank you so much this concept had been a problem to me
You're welcome 🙏
Thanks
Anytime 🙏
Wow thanks alot
Teacher in question a how did u get 7.4721 in the calculator plz guide me
Hi, please press on your calculator the following:
2 x √5 + 3.
How do you get area of unshaded region
Hi, that would involve getting the areas of the two sectors of the circles subtending reflex angles, add to the area of the kite joining the circles, then finally subtract the area of the shaded region as we obtained in the video. Please let me know if this response helped 🙏
@@KevinOcholaI’m Abit confused. Can you please do a short video explaining how to get unshaded region
Okay, let me organise
@@KevinOcholathank you so much I’ll be sure to watch it when you post
@@KevinOcholahey, can you post the video tomorrow?
It was helpful thanks 🙏 teacher.
You are welcome 🙏
Rda
Teacher how did u get 53•13 I don't get it plz
Hi! Sine inverse of 0.8=53.13
Remember Sine theta=4/5=0.8
But my calculator tells 0•01396
I think it's the setting of the calculator. Reset it from rad mode to deg. Press mode in your calculator repeatedly until you see deg and rad. Press the number under the deg and it shall av been reset.
Please let me know if it went through.
Okey thanks alot
hello sir haven't understand the question c
You just do the shaded part and do more qns then you will understand