Cosine solution to Simple Harmonic Motion

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  • Опубліковано 26 жов 2024

КОМЕНТАРІ • 40

  • @jingyiwang5113
    @jingyiwang5113 Рік тому +2

    You have offerred a crystal-clear explanation about the cosine solution to the simple harmonic motion. I am really grateful for your help! Thanks!

  • @remowspread
    @remowspread 3 роки тому +2

    Thank you Dr. Anderson!

    • @yoprofmatt
      @yoprofmatt  3 роки тому

      You're welcome. Thanks for watching.
      Cheers,
      Dr. A

  • @grantking4032
    @grantking4032 2 роки тому +1

    The -k/m(x) comes from the fact that the d^2x/dt^2 is equal to acceleration (a). Acceleration is equal to Force over Mass. a=F/m from the equation F=ma. Force is also equal to Negative spring constant multiplied by the distance. Now the a=F/m will look like a=-kx/m. because the k and x are multiplied together you can pull the x out and be left with -k/m(x). It took me a little bit to find where -k/m(x) came from. I am sure there is a paid version of this video somewhere that actually covers it, but if like me, you need to understand where formulas came from, you were probably lost and felt like you were missing out on some crucial information.
    Thanks,
    Grant

    • @yoprofmatt
      @yoprofmatt  2 роки тому

      Thanks Grant, I'm always looking to improve these lessons, so I appreciate your feedback.
      Cheers,
      Dr. A

    • @grantking4032
      @grantking4032 2 роки тому

      @@yoprofmatt i didnt expect a reply, holy cow. I appreciate you taking the time to read replies and respond. I am not sure if I was subbed before but I will check right after this.
      Thanks!!!

  • @TMHC_
    @TMHC_ Місяць тому

    Thank you sir for this detailed explanation

  • @aku7598
    @aku7598 3 роки тому +2

    Wish all videos related to "waves and oscillation" in single video.

  • @matthew_bang
    @matthew_bang 4 роки тому +7

    Wow great professor. Makes my UC physics professor an absolute joke

    • @yoprofmatt
      @yoprofmatt  4 роки тому +1

      Matthew,
      Dang, that's cold.
      But thanks for the comment, and keep up with the physics!
      You might also like my new website: www.universityphysics.education
      Cheers,
      Dr. A

  • @umarzanginamuazu7876
    @umarzanginamuazu7876 3 роки тому

    I really like ur turtoruals

  • @mickl3176
    @mickl3176 6 років тому +4

    Hi professor Anderson,
    Is there any way possible I can receive a set of full lecture for physics 3(optics)253? Please let me know.

  • @the_eternal_student
    @the_eternal_student Рік тому

    Why does nothing happen to Amplitude in the derivatives?; constants are supposed to drop in differentiation.

  • @TheKingDavid7
    @TheKingDavid7 Рік тому

    Professor, what type of marker do you use? I want one lol

  • @tvd5002
    @tvd5002 Рік тому

    Dao động điều hoà
    Tổng hợp dao động
    Sóng
    Điện xoay chiều
    Mạch dao động

  • @dennisrayrosas3175
    @dennisrayrosas3175 3 роки тому

    Now i know why i am confuse where did the formula came from hehe, i need to study calculus

  • @valkyrie9349
    @valkyrie9349 3 роки тому

    May i know whether u r writing straight or opposite from ur side?

    • @samanthas9742
      @samanthas9742 3 роки тому

      i think he writes straight and then flips the video maybe

  • @cutawayuniverse6396
    @cutawayuniverse6396 Рік тому

    What's k in the equation

  • @RicardoHernandez-nd5pp
    @RicardoHernandez-nd5pp 4 роки тому

    Thanks!

    • @yoprofmatt
      @yoprofmatt  4 роки тому

      Ricardo Hernandez,
      You're very welcome. Glad you're enjoying the videos.
      You might also like my new site: www.universityphysics.education
      Cheers,
      Dr. A

  • @mahesan2881
    @mahesan2881 3 роки тому +2

    Hold on!!! How are you writing like that????

    • @_inky_
      @_inky_ 2 роки тому

      He's prob writing on a mirror or some sort or reflective surface

    • @SalhStudios
      @SalhStudios 2 роки тому

      @@_inky_ he is writing in regular direction may be he has flipped the video

  • @kohilnoureddine9772
    @kohilnoureddine9772 3 роки тому

    Thanks a lot

  • @royalgaming3469
    @royalgaming3469 3 роки тому +1

    Why we take natural omega outside at 2:38 please explain anyone

    • @JOE-sy6gy
      @JOE-sy6gy 2 роки тому +2

      In A cos(wt+¢) first we differentiat it totally so we get -A sin(wt+¢) then we differentiat wt+¢. Since ¢ is constant and wt will become w×1 which is w , we can make it -Aw sin(wt+¢)

    • @bhaswatimedhi6673
      @bhaswatimedhi6673 2 роки тому

      @@JOE-sy6gy why is t = 1 ???

    • @JOE-sy6gy
      @JOE-sy6gy 2 роки тому +1

      @@bhaswatimedhi6673 its because of differentiation. The equation of differentiation of X^n =n×X^n-1
      X is a variable
      Here x is t. w is a constant.
      Power of t is 1 (t^1 = t)
      1×t^1-1=t^0=1(here t becomes 1)
      Add w after that cause it is a constant
      If it was t^2 then t will become 2t^2-1=2t

  • @amazingman8842
    @amazingman8842 2 роки тому

    Sala chutiya youtube, kal exam hai aur mera net slow lekin video quality 1080p pe set hogaya aur video load hi nai hora. Aur sath me bas 100mb bacha hai.

    • @yoprofmatt
      @yoprofmatt  2 роки тому +1

      Good luck on your exam.
      Cheers,
      Dr. A

  • @saptarshimukherjeebmch2884
    @saptarshimukherjeebmch2884 7 років тому

    sir,is timetravel possible through blackhole.....please explain me..

  • @saptarshimukherjeebmch2884
    @saptarshimukherjeebmch2884 7 років тому

    sir,plese make video on blackhole...everything about it..please sir,i want to know more about it......

  • @saptarshimukherjeebmch2884
    @saptarshimukherjeebmch2884 7 років тому +1

    what is -zone of no return->>>?

    • @Tridebeshs
      @Tridebeshs 5 років тому

      Zone of no return is the event horizon where the gravity becomes so strong that you can't come back from that point

    • @carultch
      @carultch 4 роки тому

      In this context, that means yielding. When you deform a ductile material to exceed a limit called its yield point, it will permanently deform. It will still support the load, but when you remove the load, it will not return to its original size/shape. It is only in the elastic zone of loading, between zero and the yield point, that a ductile material will return to its original size/shape, after you remove the mechanical load.
      A brittle material by contrast will not have a yield point. Instead, it ruptures immediately at the end of its limit of reversible loading.