Propositional Logic Truth Trees (and, or, not)

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  • Опубліковано 1 лис 2024

КОМЕНТАРІ • 9

  • @T-The-K
    @T-The-K 2 роки тому +1

    This one took me a bit longer to fully grasp, a lot of rewinding but i figured out everything (hopefully) so looking forward to the excercises!

  • @QuocDatPhung
    @QuocDatPhung 3 роки тому +4

    This is amazing!

  • @flirkvslife2385
    @flirkvslife2385 Рік тому +1

    I don’t understand why we’re branching out from ~R, and also, why did we put P Q instead of P R in the branch? On top of that, I also don’t get why Q branches into P AND R!!

  • @lucarius4465
    @lucarius4465 2 роки тому

    In our class we call the NCD and the NDD 'The Morgan'. I quite prefer that name over this spaghetti alternative xD

  • @salmanizzadin
    @salmanizzadin 6 місяців тому

    📝

  • @stephaniew7501
    @stephaniew7501 2 роки тому

    Where is the solution video?

  • @paulcarello6390
    @paulcarello6390 Рік тому

    1) (P ∨ Q) ∧ (P ∨ R) ⇔ (P ∨ Q) ∧ ~(~P ∧ ~R) ... De Morgans
    ∴ (P ∨ Q) and ~(~P ∧ ~R) ... ∧ deconstruction
    2) (~P ∧ ~R)
    From 1 and 2
    ~(~P ∧ ~R) is TRUE and (~P ∧ ~R) is TRUE ... this is a contradiction
    ∴ 1 and 2 are NOT consistent.