+2 Maths Onam Exam | Chapter 5 | Continuity And Differentiability Part 1 | Oneshot | ExamWinner +2

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Gear up for your Plus Two Maths Onam Exam with our focused session on Chapter 5: Continuity and Differentiability (Part 1)! 📐 This comprehensive review will cover essential concepts such as limits, continuous functions, and the basics of differentiation. Perfect for quick revision, this session is designed to clarify key ideas and boost your confidence before the exam. Don’t miss out on mastering these fundamental topics for success! 🌟📚
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[@haridevt1136]

13:58 Allen sir rocked students shocked 👀

[@mathewjoseph1276]

Enikk maathramano batchil padipuunath kurach manasilaakunnthum ath kazhinj yt class full manasilaakan kaanandathum😅😢

[@sreelekshmims5494]

Enikkum angane thanneya😅 batch il fees koduth keriyitt youtube class kaanum😂

[@Nived.S.Anand777]

​@@sreelekshmims5494sathyam😂

[@кяѕниєи]

Sathyam, pyq use full ahn

[@Nived.S.Anand777]

@@кяѕниєи actually ath kanan mathram aan subscription eduthirikkane😂

[@alveenamaria4130]

Truee.. batchil padippikeneth maths mikaythum manasilakanilaah ytil edukkumba manasilakenend

[@aaliyafathimaaswad9b014]

Cos(tan(e^2x+3)) . sec^2(e^2x+3) . e^2x+3 . 2
Thank you sir 💛👍🔥🔥🔥🙏🙏
Super class❤❤full clear ❤❤🔥🔥🔥🔥🔥🔥🔥

[@krishnaunnikrishnan2730]

Sir always very thankful for your efforts ❤❤❤
By the way the ans is : 2*Cos(tan(e^2x+3))*Sec²(e^2x+3)*e^2x+3

[@rejanibiju8308]

Class starts at 2:44

[@kuttapan4070]

13:59😵 14:20🙀 22:15💀 24:22☠️ 24:26 ⚰️30:35🪦

[@asimahamed._]

Bro is cooked

[@rexxxxxxxxxxxxxo]

30:35

[@PoornimaTA-ue5bm]

What thha😭

[@kuttapan4070]

​@@rexxxxxxxxxxxxxo👍🏻

[@footballepics9234]

We got Alex sir saying the p word before gta

[@Aryan....x]

Tnku allen sireyh 🙂🫶🏼💖
Ans ; 2cos(tane^2x+3).sec²(e^2x+3).e^2x+3

[@Jaycejacob-t4i]

Yes good class ❤

[@AdithyanSanthosh-d3i]

13:58 Bro Said " P"word 💀

[@abhiiiiiiiiee]

brain rott💀

[@AnanyaAbhinav]

dy/dx=cos[tan(e^(2x+3))]*sec²(e^(2x+3)*2[e^(2x+3)]
Thankyou Allen Sir🎉❤ for your great effort❤🎉
Thankyou Exam winner family🎉❤

[@Clever976]

3:19 continuity 46:05 differentiability 🙂👍🏻

[@_allaboutus_431]

Cos(tan(e^2x+3))sec²(e^2x+3)(e^2x+3)×2. Sirr cls valare help full aayirunnu.... Bakki topics nu katta waiting aqnuu❤️🥰

[@HibaSajil-mu9wy]

An:2 cos (tan e^2x+3).sec^²(e^2x+3)e^2x+3

[@arvlog07]

2cos(tan(e^2x+3))sec^2(e^2x+3)(e^2x+3)
Useful class ❤❤

[@ananyashivadas7811]

dy/dx=cos[tan(e^(2x+3))]*sec²(e^(2x+3)*2[e^(2x+3)]
Thankyou Allen sir.....🎉❤Super class🎉❤

[@ansanaansar6455]

Ans:cos(tan(e^(2x+3))×sec2(e^(2x+3))×e^(2x+3) ×2
THANKYOU SIR FOR YOU EFFORT❤️

[@__.Karthiii.____]

Etho koodiyan sathanam adichitta thonunnu class edukkam vanne😂😂

[@Rev_Editz720]

ans; 2cos(tane^2x+3).sec²(e^2x+3).e^2x+3
thanks for this wonderful class sir

[@messisiiu5000]

Ans) 2cos(tan^2x+3).sec²(e^2x+3).e^2x+3.
❤
One of the best class ❤

[@mr_benzene786]

2cos(tane^2x+3).sec²(e^2x+3).e^2x+3
Thanks allen sir💥

[@kamaluddinkamaluddin6455]

Thankyou sir❤️❤️❤️❤️❤️👍🏻👍🏻🔥
Ans: 2cos(tan(e^2x+3))(sec^2+3))(e^2x+3)

[@AnshirAp]

2cos( tane^2x+3.sec^2(e^2x+3).e^2x+3
Thankyou allen sir❤❤

[@athuul__]

13:59 💀 😭 omg

[@Ddfffhhhhibbji]

😂

[@muhammedamilamil174]

😏🙄

[@prettygurl9670]

Allen sireeyy thnkuuh so much.....class nannayi manassilaay💗💗💗🤩
Ans:2cos(tan e^2x+3)•sec²(e^2x+3)•e^2x+3👩🏻‍🦯

[@sameeraaami2843]

Cos(tan(e^2x+3).sec^2(e^2x+3).e^2x+3
Good class😍😍

[@Musthafa-o3u]

Answer:2Cos(tane^2x+3) * sec^2(e^ 2x+3)*e^2x+3❤❤❤🎉🎉🎉 Adipoli class 💪💪❤️❤️❤️💪

[@adithyans556]

2cos(tan^2x+3).sec²(e^2x+3).e^2x+3 - ans.

[@sarangsr]

Thankyou sir ❤
Ans:2cos(tan(e^(2x+3)))sec^2(e^(2x+3))2e^(2x+3)

[@sairasakkariya9516]

Answer: 2 cos (tan e^2x+3) sec²(e^2x+3) × e^2x+3
Thank u Allen sir ❤🙌

[@nithinnithi3001]

Sir poly ❤
2cos(tan e^2x+3)sec^2(e^2x-3)(e^2x+3)

[@siddhharth__2007]

Ans is 2cos (tan e^2x+3).sec^2 (e^ 2x+3).e^2x+3

[@AdilBijoy-ep5ej]

Alen sir power❤🔥
Answer:-
2cos(tan e^2x+3).sec²(e^2x+3).e^2x+3

[@sreeleghanarayanan4875]

2cos(tan(e^2x+3)*sec^2(e^2x+3*e^2x+3 is the answer
Thank you soo much for your effort sirr 🎉
Very useful class❤🎉

[@chandanac1405]

Ans:2cos(tan^2x+3).sec^2(e^2x+3).e^2x+3
Thankuu sirr

[@arrowyt5265]

Ans: 2Cos(tan e^2x+3).sec² (e^2x+3).e^2x+3

[@Notmebutyou1]

Ans=cos(tan(e^2x+3)).sec^2(e^2x+3).e^2x+3
❤️Thanku exam winner❤️

[@brindat.b2761]

Ans: 2cos(tane^2x+3).sec²(e^2x+3).e^2x+3🖤
Thank you sir ❤

[@huefa4351]

Cos(tan(e^2x+3).sec^2(e^2x+3).e^2x+3.2
Everything crystal clear ❤

[@nihalpp3622]

2cos(tane^2x+3).sec²(e^2x+3).e^2x+3

[@priyaah____123]

2Cos(tan e^2x+3) Sec²(e^2x+3) e^2x+3
Thank you sir💖for such a nice class

[@anisharajeev4289]

Answer =2.Cos[tan (e^2x+3)].Sec^ (e ^ 2 x+3).e ^2x+3

[@MariyammaShahanaz]

Cos(tane^2x+3) sec^2
(e^2x+3) e^2x+3

[@nehajiffy]

Cos (tan(e^2x+3)). Sec²(e^2x+3). e^2x+3.2+0

[@Suryaaa-oq1dq]

2 cos(tan( e^2x+3))(sec^2(e^2x+3)) (e^2x+3)
Crystal clear tnk u Allen sir ❤

[@Jaycejacob-t4i]

Yes class is super ❤

[@Irfanirfu.lm10]

Ans)2cos(tane^2x+3).sec²(e^2x+3).e^2x+3

[@RafeekRafee-jm1kb]

Ans:-Cos(tan(e^2x+3))*sec²(e^2x+3)*e^2x+3*2+0 thank you so much sir for this great class !!😊

[@btswaterbottleofficial6692]

2cos (tan e^2x+3).sec²(e^2x+3).e^2x+3 is the answer. Thankuu examwinner for the double dhamakka seriess🎉❤❤

[@Jaycejacob-t4i]

Thankyou sir ❤❤😊
Ans =2cos(tan^2x+3).sec²(e^2x+3).e^2x+3

[@sreekanthvk1071]

2cos(tan(e^2x+3).sec^2(e^2x+3).e^2x+3 ❤ class full on power sir powli😊😊😊😊😊😊❤❤❤❤❤❤❤❤

[@AlanAlanabhilash]

2cos(tane^2x+3)*sec²(e^2x+3)*e^2x+3 ❤❤❤❤❤❤❤

[@ShiraShineKottarathil12032]

Ans) dy/dx = 2cos (tan (e^2x+3)) sec² (e^ 2x+3) e^ 2x+3
Thank you so much Sir🔥❤
Baakki portions nale mrning eppozhelm live il edkamo Sir? 💖

[@Kevinmoolan]

dy/dx =
2cos(tan(e^2x+3))×sec^2(e^2x+3)×e^2x+3
Thank youh Allen sireeh

[@harikumarp5867]

Cos(tan (e^2x+3)).sec^2(e^2x+3).e^2x+3.2
Thank youu sir ❤❤❤

[@devikadileep9877]

Ans:2Cos (tan e^2x+3)* sec^2(e^2x+3)*e^2x+3
Adipowoli class , thankyou for valuable class❤❤

[@Jasnasalam-zf4ey]

2cos(tane^2x+3).sec²(e^2x+3).e^2x+3
Thankyuuh sirrr for yourr valuable classess🥺🖤🖤

[@RafeekRafee-jm1kb]

Cos(tan(e^2x+3))*sec²(e^2x+3)*e^2x+3*2+0 thank you so much sir 🥹

[@sindhupg5319]

dy/dx=
Cos(tan(e^2x+3))•sec²(e^2x+3)•(e^2x+3)•2

[@fathimafathimack]

Nice class ❤

[@HadhiFadhi-lp4jr]

Ans:2Cos(tan(e^2x+3)).sec²(e^2x+3).e^2x+3
Tnquu sir 🤍

[@JessySiby-ty7yh]

5:22

[@ajinprakash-w1z]

2cos(tan e^2x+3))sec^2(e^2x+3)(e^2x+3)

[@rejilarejila3771]

Thankyou sir❤
Answer:dy/dx =2 cos(tan e^2x+3).sec²(e^2x+3).e^2x+3❤

[@Mayflower_22]

y' = cos(tan(e^(2x) + 3)) * (sec^2(e^(2x) + 3)) * (2e^(2x))
Thanku Allen sir❤️✨

[@AnjiAnji-i3v]

dy/dx=2cos(tan(e^x+3)).sec^2(e^2x+3).e^2x+3

[@Adx_cutzz]

Nice class♥️♥️♥️
Ans:2cos(Tan^2x+3).sec²(e^2x+3).e^2x+3

[@keertheeshv3047]

Ans; 2cos(tan(e^(2x+3))).sec²(e^(2x+3).e^(2x+3)
Thanks for giving your best sir❤❤❤

[@rajipradeep2938]

Ans : 2 cos (tan(e^2x+3)).sec^2(e^2x+3).e^(2x+3)
Thank you sir ❤

[@fathifathima-n7c]

Ans=2cos(tan^2x+3).sec^2(e^2x+3).e^2x+3
Seen class thanne❤❤

[@epiczoro-111]

Ans:cos ( tan(e ^ (2x + 3)) * sec(2) * (e ^ (2x + 3)) * e ^ (2x + 3) * 2 Thanks

[@sgcreation3552]

Ans :- 2Cos (tane^2x+3). Sec² (e^2x+3). e^ 2x+3
Thank you sir ❤🎉

[@aswathir.s1258]

dy/dx=cos(tan( e^2x+3)).sec^2(e^2x+3).e^2x+3

[@shaazzbilcopz6410]

Ans:dy/dx=cos(tan(e^2x+3)).sec^2(e^2x+3).e^2x+3×2 , thankyou sirrr❤

[@epiczoro-111]

Ans:cos ( tan(e ^ (2x + 3)) * sec(2) * (e ^ (2x + 3)) * e ^ (2x + 3) * 2

[@Ronoman.]

❤ nice class
Ans: 2.e^2x+3.sec²(e^2x+3).cos(tan(e^2x+3)❤❤

[@DevikaBose_4427]

Ans: dy/dx= 2 cos (tan (e^2x+3)).sec^2(e^2x+3).e^2x+3
Super class.... Thank you sir..,..❤❤❤
Examwinner ❤❤❤

[@AjayAjay-ry2bi]

ANSWER Cos(tan(e^2x-3))×sec2(e^2x+3)×e^2x+3
Thank you sir for the valuable class ❤️❤️
Don't fear Exam Winner is hear🔥🔥🔥🔥

[@NihalEk-jn9mf]

2cos(tane^2x+3).sec^2(e^2x+3).e^2x+3
❤❤❤ Adipoli siree

[@raziteach895]

Answer : dy/dx = 2cos(tan(e^2x+3)).sec^2(e^2x+3).e^2x+3

[@madhurima.p4095]

Ans:2 cos(tan e^2x+3)*sec^2(e^2x+3)*e^2x+3 ✨✨✨✨❤️nice class❤️

[@annacasmir7]

Answer:2cos(tan(e^2x+3))*sec(e^2x+3)*e^2x+3
Adipolii clz ayirun sir❤

[@rxan-9136]

ans - 2cos(tan(e^2x+3)).sec²(e^2x+3).e^2x+3

[@zees...3323]

Ans:2cos(tan(e^2x+3)).sec^2(e^2x+3).e^2x+3
Bigg salute for your effort sir💗🫂

[@BLACKCAT-bi3bb]

13:58 😅 14:21 💀

[@sarangsr]

2cos(tan(e^(2x+3)))sec^2(e^(2x+3))2e^(2x+3)
Sir ithil e yude powerinu braces kodukkande? Like I did?

[@RIO-jw5nx]

2cos(tane^2x+3).sec²(e^2x+3).e^2x+3 is the ans

[@shibuvlogs2901]

Ans=2cos(Tan e^2x+3) . Sec^2(e^2x+3). e^2x+3

[@fidharidha9909]

Its 2cos(tan e^2x+3).sec²(e^2x+3).e^2x+3

[@asal8746]

Ans: 2e^(2x) .sec²(e^2x+3).cos(tan(e^2x+3)
❤❤❤❤

[@Musthafa-o3u]

Adipoli class ❤❤

[@RaseenaAnas...]

Thankyou Allen sir... For this amazing class❤

[@muhammedirfan5850]

Set clss🤍
2cos(tane^2x+3).sec²(e^2x+3).e^2x+3

[@epiczoro-111]

Ans: cos ( tan(e ^ (2x + 3)) * sec(2) * (e ^ (2x + 3)) * e ^ (2x + 3) * 2 Thankyou Allen sir✨

[@liyalinta]

Thank you sir❤

[@premant7840]

Thanku sir❤

[@mubeerkp7906]

Answer : 2cos(tane^2x+3).sec^2(e^2x+3).e^2x+3
Thank youhh sirr💓🫶🏻

[@Musthafa-o3u]

Answer:=2Cos(Tan e^2x+3)* Sec ^2 (e^2x+3)* e^2x3

[@Liv4f]

Class starts at 13:59 Thank me later 😍😍

[@Rabeeh777]

😂

[@liyalinta]

Ans: 2e^(2x+3).cos(tan(e^(2x+3)).sec^2(e^(2x+3))

[@RafeekRafee-jm1kb]

Cos(tan(e^2x+3))*sec²(e^2x+3)*e^2x+3*2+0