PROJECTION OF SOLIDS SOLVED PROBLEM 2 IN HINDI IN ENGINEERING DRAWING

[@amankumhar987]

Harekrishna Harekrishna Harekrishna Harekrishna Harekrishna Harekrishna Harekrishna Harekrishna Harekrishna Harekrishna Harekrishna Harekrishna Harekrishna Harekrishna Harekrishna

[@Sanadenzel]

Ram ram ram ram ram ram ram ram ram ram ram ram ram ram ram ram ram

[@Singh.537]

Jay shree ram

[@galaxymusicalworld8519]

Om sai ram 🙏

[@Gurun3110]

15 times Hare ram🙏

[@vedantgupta8332]

Radhe radhe, kare krishana ✨🔱❤

[@anshuljyoti4421]

appreciate your efforts sir

[@madhurimabanerjee52]

THANK YOU SIR , YOU ARE A SAVIOUR FOR THIS SUBJECT. MY CONCEPTS WERE SO BAD PREVIOUSLY BUT AFTER WATCHING YOUR VIDEOS, I CAN DO THE PROBLEMS NOW.

[@TIKLESACADEMY]

Thanks for watching

[@karanthakur11]

0)Approach to qustion 2:33
1) Types of bases - 4:02 (Hexagonal pyramid)
!¡ slant phase on HP =RH Side ¡!
/#/Diff b/w slant edge & slant phase/#/
!¡ VP - up & HP - down ¡!
2) TS of base - 10:12
TS of solid - 10:33 ( with little new rules )
Tilled solid -13:03
TV/FV - 17:35
AIP - 25:00

[@hajun8740]

👍🏻👍🏻👍🏻

[@missadventures3883]

there is no doubt that this channel is an elixir for students like me who are in dire need of such wonderful and beautiful channel and teacher like you but, my teacher does not accept auxillary plane method and when you said in previous video that you'll solve it by normal method and then do it again by auxillary plane method it's really disheartening

[@AdnanAli78601]

Hi sir , i love the way you teach ..
You make things interesting and easy ...

[@manishtrivedi3546]

Excellent 👍 video sir

[@TIKLESACADEMY]

Thanks for watching.

[@karanthakur11]

Q)A hexagonal pyramid
side of base 30mm
and height 55mm lies
on one of its slant face
(triangular face) on
HP and the edge of
base lying on HP
makes an angle of 45
degree with the VP
Draw its projection.

[@harshvardhanshinde5578]

Maine aise teacher kabhi nahi dekhe wonderful absulutely sir...

[@BTCMEAbrar]

U the best 👍👍

[@Death-ps9tu]

Thank u so much sir
Because of you I've taken a liking to this subject..
I really appreciate your efforts
Thank you!

[@nachiketsuryawanshi9911]

sir tumhi dev manus aahat ....
kt vachavli❤

[@shanucheeta8644]

Mind blowing

[@yogeshanfat6278]

Thanks sir ji ❤🙏🏻

[@chaurasiarailways3437]

Nice sir

[@TIKLESACADEMY]

Thanks for watching

[@Chavdaradha27]

Best lecture in EGD subject
Thank you sir..

[@yourfeeling9703]

Which university 🤔

[@engineeringyoutubechannel6084]

Way of explanation is best sir

[@TIKLESACADEMY]

Thanks for watching

[@Ajinkya_Chirde_07]

best explanation sir👍

[@adityarajsinghrathor]

Dhanyawad Guruji 🙏🙏🙏🙏

[@Mkguptafun]

Very nice video sir 🙏🙏

[@mrinalpatil4823]

Shree shivay namastubhyam ❤

[@PalJiProduction]

Sir you are best teacher of Engineering Drawing

[@sudeepsharma9053]

Very nice sir 👍

[@karanpatnayak4690]

Itti mehnat👏👏👏👏👏

[@28amitpal65]

Nic vidoe it's really help in study and u mack easy to under stand us really appreciate your videos sir 👍

[@TIKLESACADEMY]

Thanks for watching

[@aamirmir007]

Nice explanation

[@rushi_1023]

Thank you soo much sir 💝😘

[@amanpetwal9760]

You is really great sir ❣️

[@Varma_Vlogs18]

Can u please explain 1 or 2 problems in normal method

[@humairatabassum6236]

amazing 🎉

[@worldofelectronics5602]

thank u very much sir 😍😍😍😍😍😍😍😍🥰🥰🥰🥰

[@MADHUKUMARI-rh6ss]

Nice video

[@TIKLESACADEMY]

Thanks for watching

[@RAJATHAKUR123]

Sir bhut achha padhate ho aap thanks 😊

[@rohitpanwar9306]

Q: 3 A hexagonal pyramid, side of base 25 mm and axis 50 mm long, as one of its triangular faces in VP and the edge of base contained by that face inclined at an angle of 30° to HP. Draw its projections.

[@deveshtembheker1315]

Dhanyawaad Guru....❤

[@marthigirlff9694]

Chalo suru karte hai ;

[@ayushtrack6152]

Nice explanation

[@TIKLESACADEMY]

Thanks for watching

[@gaurangsakpal5739]

Thank you very much sir!

[@_RRR396]

Thanks a lot guru jee 👏👏👏👏👏👏👏👏👏👏

[@osamaansari6036]

Aag laga diye guru jiii 😅

[@banvariahirwar15]

Thankyou sir 🙏🏼🙏🏼🙏🏼🙏🏼🙏🏼

[@wilsonsequeira542]

Very nice

[@avadhootsonavane5619]

Thank you sir

[@vishalworkeatpolice743]

Nice

[@TIKLESACADEMY]

Thanks for watching

[@adhirajjarwal3186]

Sir apne kaha tha ki koi bhi dark line dark ko intersect nhi karenge, dark line dotted ki ya fir dotted line dark ko intersect karenge to hm 10:00 pr hexagon draw krte samay inner side me dark draw ki, Interaction of dark line hua he na waha par, pls explain.

[@dashinglover9629]

Bcoz vo outer region hai. Par lagta hai bhaut der ho gyi btane me😂😂😂😂

[@mayanksahu6385]

@@dashinglover9629 no problem boy

[@apravatiseema6675]

Hello sir .I think the true shape of base should be above xy line because it is resting on its face on hp.

[@KatanaBoy0]

Resting on hp means below xy line and resting on vp is above xy line

[@lakshy_09]

❤️❤️❤️❤️❤️

[@lakshy_09]

👍👍👍👍

[@kartikeygupta4075]

THANKYOU VERY MUCH SIRJI...

[@chandraguptamaurya5507]

Truly liife saver

[@parthtiwari2753]

Who are watching this lec before one day of exam 😅

[@bazilayousuf7081]

A right regular hexagonal prism side of base 20 mm and 55 mm long lies on one of it's rectangular faces on hp and it's axis inclined at 45 to the vp.. Sir is question mai true shape of base kahan banega xy k upar ya neeche

[@sahityajaimaapremi1076]

neeche

[@sparshgupta7314]

lies on HP, so humme HP mein, ie. neeche XY ke banana hai. upar banana hoga agar side is in or resting on VP.

[@parthingale394]

Thank you so much sir

[@truth3741]

Thank you Sir ❤️❤️❤️

[@MK_inamdar]

LOL - lots of love ❤️

[@RishabhChikhalikar]

1 million time hare ram🙏

[@theunscripted643]

Ty sir ❤

[@thecritiquer9407]

❤❤❤

[@सुमंतराय]

Thank u

[@gautambhaskar4160]

Aap to jaan ho sir....charan kahan hai aapke

[@thestrenge]

❤️

[@222chaitaliramanwad7]

Tq sir

[@TIKLESACADEMY]

Thanks for watching

[@yashwantladiya1489]

Legend watch this video 2x before exam 😅😅😅

[@SandeshKokate-o3t]

😊

[@preambagga2527]

Awesome lecture sir, sir can u pls reply for currrent sem2 is to conducted for that i want projection of solids so which particular videos should i refer as there are so many videos are 3.yrs old in playlist quite confuse pls reply sir 🙏🏻🙏🏻

[@shashwatsrivastava9784]

Sir
Aap bole ki axis ko line dotted line dotted Karke bnana hai par aap yahan poora dark use kiye at 14:07 please explain sir.

[@TIKLESACADEMY]

Because axis ke samne slant edge OC aaya hai, aur true shape of base ko niche se dekhne par, pahale OC edge dikhega, aur wo overlap karte hue dark banega. Dark OC ke piche axis OP Hai.

[@RohitKumar-bf9ix]

Tnx

[@TIKLESACADEMY]

Thanks for watching

[@tarundiwan7887]

Jai shree ram

[@me_vip_0007]

Today is my exam and I am here .

[@duadabhaskar4366]

Bidwatwancha Nrupatwancha Naivatulya Kadachana; raja pujyate rajye bidwan sarbatra pujyate.

[@eagle_records2511]

Thanks sir monday ko exam hai pusa mechanical walo ka

[@TIKLESACADEMY]

Best of luck for the Exam.

[@prathameshpradhan9422]

thankk youu sirr

[@harasiskaur5153]

Kya auxiliary plane and normal method se same ans milta hai

[@chittimurihimajarakhi2208]

Sir plz explain this projection of solid sum in the next video....
A triangular prism base 40mm side and height 65mm is resting on hp.One of its rectangular faces with the axis parallel to the VP. Draw its projections..

[@SaniyaSarkar-li7ew]

19:52 imp
30:40 imp

[@therisingclassicals_shrist6678]

Sir.esmai humne beta angle kyu nahi nikala

[@VTGAMING07]

Is auxiliary plane method correct for mumbai University exam?

[@TIKLESACADEMY]

Yes definitely but before the exam please ask your College Lecturer...

[@VTGAMING07]

@@TIKLESACADEMY ok sir thanks a lot

[@Faisal_Chauhan]

Projection joh last waale ke liya leta ha woh direct line exetend kardena ka nah 90degree karke waisa kuch nhi karna hota ha nah?

[@ritesh27raj]

Aag kaminga tabhi toh kll kahinga na mere jaaan 😂😂😂😂😂😂

[@MohemmadAfzalD]

Can you explain Corner method please

[@ranguravikumar2666]

I think Front view also compresses after inclining base edge 45 degrees to vp... Is it right sir... Please reply me sir...

[@sonamgupta4292]

Sir Beta angle nhi liye ???

[@sanyamsinghvirat2110]

sir mere college me normal plane se draw karwata hai, ek question normal plane se bhi banaeye ..please ....13 dec ko exam hai

[@TIKLESACADEMY]

Solid me Normal plane se draw karne ka Same wahi technique hai jaise Projection of Plane me tha....
koi difference nahi hai
Best of luck for the Exam 👍

[@sanyamsinghvirat2110]

Ok thank you sir....per ek question normal plane se...

[@ugangadhar4019]

Sir agar question mr parallel to hp diya hai tho true shape kaha draw karna hai ,uper ya niche?

[@pritmajmudar1647]

Sir line projection ka video upload kijiye

[@TIKLESACADEMY]

I already uploaded six videos on projection of straight line please study all of them

[@funfeast621]

In earlier video you said slant face means upper one fig.
The figure you draw is for slant edge

[@harshinirahul9986]

Clear my douts

[@naramnikitha1087]

Can plz sir explain the prblms in normal method..

[@gauravmaurya45]

Sir is question me beta angle kyo nahi find out kiya gaya jabki vo edge to fv me reduce hai n .
Sir please clear my this doubt🙏🙏🙏

[@bhagirathipatra8984]

Projection of solid mein given data likhna hai kya?

[@SomNath-fy2bp]

Sir ise ek bar drawing book me correct bana ke dikha do (please sir)

[@TIKLESACADEMY]

Drawing book me bhi ye approximately aisa hi banega.... Jo humne draw karaake diya hai

[@siddinshah6001]

sir can u pls draw it in normal method

[@SomNath-fy2bp]

Sir copy me auxiliary plane me 'c'vali line 'd'vali line se pehle aa rahi hai aur board pe 'd' vali pehle

[@TIKLESACADEMY]

Do one thing.....aapne jo banaaye uska image hume send karo what's up pe 9370325341 Hum check karnenge

[@ayhamkhan77]

Same !

[@manojmarandi2632]

Sir questions description m likha kijyega plzz

[@TIKLESACADEMY]

Yes off course.....Anyway Thanks for watching.

[@sscreation779]

Sir ND bhat book mein se problem Batao
draw karke please Sir hamko college mein kuch bhi nahi samajhata

[@komalgite7965]

Sir...aapne vo angle kitna liya...in tv 1 stage...jisse hexagonal bnaya hai...

[@charanteju6061]

120

[@nitinadhangle573]

Sir in some questions, axis inclination is not given...means we have to find inclination....How to solve this...?

[@rs2120]

Sir ajj graphics paper tha maine projection cube ki 1stage and 2 stage draw ki hai .....Out of 13 how I will get for 2 stages of cube

[@nikhilsood6126]

Type kya hai iski...... Inclined to both?

[@TIKLESACADEMY]

Yes definitely

[@aloksingh4798]

How to identify outer point