Good question. First, the splitting definitely confirms the placement of the red CH2. If it was connected to the O, the splitting pattern would be different for it, for the black H, for the methyl groups, and also for the CH2 of the ethyl. Second, the hydrogens of the red CH2 are 3 bonds away from both oxygen atoms. The hydrogens of the blue CH2 group, directly attached to the oxygen, are 2 bonds away from one O but 4 bonds (too far) away from the other oxygen. Therefore it is only being effectively split by one O and therefore not as deshielded.
Thank you for this awesome video. I was able to do the second one by myself and you explained everything so nicely! Thanks!!!
Great job! I'm so proud of you - these are HARD problems!!! You're doing great!!!!!!!
Good question. First, the splitting definitely confirms the placement of the red CH2. If it was connected to the O, the splitting pattern would be different for it, for the black H, for the methyl groups, and also for the CH2 of the ethyl. Second, the hydrogens of the red CH2 are 3 bonds away from both oxygen atoms. The hydrogens of the blue CH2 group, directly attached to the oxygen, are 2 bonds away from one O but 4 bonds (too far) away from the other oxygen. Therefore it is only being effectively split by one O and therefore not as deshielded.
Thanks for your efforts. I just have one question shouldn't the red CH2 by connected to O atom because it is the most deshielded part of the spectrum?
These were pretty tricky, and great practice!
Thanks for the lessons
I have an exam in 3 hours and I totally knew nothing about these nmrs,
But now I learned them
Tyyyyyyyyy💙🤝🏻❤️
I know it's been a while, but how did that exam go?
Brooooooooooooooooo If you were my university professor I could be a scientist😭😭😭😂
I wish all my professors were like her back when I was in college...