Sir if we take 2 as t.. So limit will become t to 1/t .. And then feynmann technique i.e di/dt.... It gives same answer... I thought that was the only way bcz i did it by that way only...
@sukhjotsingh799. Even aap tan inverse ko bhi t maan ke Bana sakte ho but thoda lengthy hai ,for more information join my telegram channel t.me/vasisthamaths Waha maine ek rough page share kiya hai isi problem ka
Sir for the 2nd question, i got π²/12√3. I substituted tan inverse x to be t. And then via using property of f(a+b-x), where my limit were in tan inverse and then the sum was π/2, then where i converted to cot, and added the eqns, and got the ans... Pls tell me where have i gone wrong
Is tarah se bhi wahi result aayega. Just join the telegram link I am sending the solution by your way but this become lengthy however good try. t.me/vasisthamaths
Outstanding sir 👍🙏
Sir ..direct property apply karo ..and then take l.c.m and get answer ..very simple problems
I thought like creating sinx + cox in bottom then apply half angle and making tanx forms
Will i get answer by this approach
Sir if we take 2 as t.. So limit will become t to 1/t .. And then feynmann technique i.e di/dt.... It gives same answer... I thought that was the only way bcz i did it by that way only...
@sukhjotsingh799. Even aap tan inverse ko bhi t maan ke Bana sakte ho but thoda lengthy hai ,for more information join my telegram channel t.me/vasisthamaths
Waha maine ek rough page share kiya hai isi problem ka
Sir for the 2nd question, i got π²/12√3. I substituted tan inverse x to be t. And then via using property of f(a+b-x), where my limit were in tan inverse and then the sum was π/2, then where i converted to cot, and added the eqns, and got the ans... Pls tell me where have i gone wrong
Is tarah se bhi wahi result aayega. Just join the telegram link I am sending the solution by your way but this become lengthy however good try.
t.me/vasisthamaths