does the hinge force have to be at an angle i thought that the verticle compomnent of tension would be gravity and thus the horizontal would be the F normal
I'm not totally sure what we can definitively say about the direction of the hinge force; it definitely needs a horizontal component, but the vertical component may be positive, negative, or zero depending on the setup I believe.
why is it concave down and not linear? isnt the angular acceleration represented by the slope of a angular veloctity time graph (hence would be linear if acceleration is increasing)
It will be concave down because the angular acceleration (slope of angular velocity) is decreasing. The torque is maximum at the start, and zero at the end, so the graph needs to start steep and flatten out
Yeah, torque decreases. Motion time graphs, for linear motion and angular quantities, mimics acceleration of objects essentially if you translate it to all graph types (position, velocity, acceleration). But because the angle between the lever arm and the force, i.e. those combined to make the torque, decreases, the torque decreases, meaning angular accerlation is decreasing and approaching a constant speed. This is why it starts to level out and it why the kinetic energy is a max at the bottom of the path (when its vertical) because this is where the velocity peaks and it constant (which is why it starts to slope down and approach horizontal.
@@eyan4437 Yeah, torque decreases. Motion time graphs, for linear motion and angular quantities, mimics acceleration of objects essentially if you translate it to all graph types (position, velocity, acceleration). But because the angle between the lever arm and the force, i.e. those combined to make the torque, decreases, the torque decreases, meaning angular accerlation is decreasing and approaching a constant speed. This is why it starts to level out and it why the kinetic energy is a max at the bottom of the path (when its vertical) because this is where the velocity peaks and it constant (which is why it starts to slope down and approach horizontal.
is it bad if i didn’t start it at 0 and then did a straight line down after the concave down part? it says before it hits the wall but i included it anyway
Thank you for these videos!
I got every single question on this wrong or incomplete 😭😭 i didn’t even know about the hinge force before this
does the hinge force have to be at an angle i thought that the verticle compomnent of tension would be gravity and thus the horizontal would be the F normal
I'm not totally sure what we can definitively say about the direction of the hinge force; it definitely needs a horizontal component, but the vertical component may be positive, negative, or zero depending on the setup I believe.
@@FosterWisusik thank you i hope its not something that points would be taken off for since its very confusing on what it could be
why is it concave down and not linear? isnt the angular acceleration represented by the slope of a angular veloctity time graph (hence would be linear if acceleration is increasing)
yea and i thought constant acceleration was all that physics 1 covered anyway bc no calculus
It will be concave down because the angular acceleration (slope of angular velocity) is decreasing. The torque is maximum at the start, and zero at the end, so the graph needs to start steep and flatten out
Yeah, torque decreases. Motion time graphs, for linear motion and angular quantities, mimics acceleration of objects essentially if you translate it to all graph types (position, velocity, acceleration). But because the angle between the lever arm and the force, i.e. those combined to make the torque, decreases, the torque decreases, meaning angular accerlation is decreasing and approaching a constant speed. This is why it starts to level out and it why the kinetic energy is a max at the bottom of the path (when its vertical) because this is where the velocity peaks and it constant (which is why it starts to slope down and approach horizontal.
@@eyan4437 Yeah, torque decreases. Motion time graphs, for linear motion and angular quantities, mimics acceleration of objects essentially if you translate it to all graph types (position, velocity, acceleration). But because the angle between the lever arm and the force, i.e. those combined to make the torque, decreases, the torque decreases, meaning angular accerlation is decreasing and approaching a constant speed. This is why it starts to level out and it why the kinetic energy is a max at the bottom of the path (when its vertical) because this is where the velocity peaks and it constant (which is why it starts to slope down and approach horizontal.
is it bad if i didn’t start it at 0 and then did a straight line down after the concave down part? it says before it hits the wall but i included it anyway