Energy Method

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  • Опубліковано 29 лис 2024

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  • @redhotminipepper1
    @redhotminipepper1 4 роки тому +8

    great pronounciation on the 'integraal' Dr Peyam!
    Groeten uit NL

  • @quietstorm1519
    @quietstorm1519 4 місяці тому

    I was wondering about the potential energy at 11:31, because from the limited physics I was taught, PE = mgh. However, since we are working with periodical functions, PE = 1/2k(∆x)^2 (k ≥ 0), which lines up perfectly what with is shown (1/2c^2*(U_x)^2).
    Anyways, great video as always!

  • @piyushchandra4758
    @piyushchandra4758 4 роки тому +14

    Feynman in his famous "Feynman Lectures" called Parseval's identity for Fourier series as "Energy Theorem". Energy of a wave is average square of its amplitude. This implies average of square of a function is sum total of squares of coefficients of the Fourier series of the given function. This video is like a very elementary introduction.

    • @drpeyam
      @drpeyam  4 роки тому +2

      Wow, I never made the connection, thank you!!!

    • @shambosaha9727
      @shambosaha9727 4 роки тому

      YEAH!!

  • @hocineslamene9135
    @hocineslamene9135 4 роки тому +1

    Simplified and very useful for physics students. Your pronunciation " Integraal " in Dutch is very funny, try to pronunciate it in french " L'intégrale ". greetings from Algeria

    • @nournote
      @nournote 4 роки тому +2

      Dutch, not German

    • @hocineslamene9135
      @hocineslamene9135 4 роки тому +1

      @@nournote OOOOPS, it's my fault. Thank you Sir.

  • @hidalgohernandezmauricio5728
    @hidalgohernandezmauricio5728 11 місяців тому

    OMG love his energy!!

  • @adityaujjwalmain5943
    @adityaujjwalmain5943 4 роки тому +2

    Great as always!

  • @souvikbhunia3669
    @souvikbhunia3669 4 роки тому +1

    He never disappoint to anyone.

  • @Л.С.Мото
    @Л.С.Мото 4 роки тому +5

    Hello Dr. Peyam
    I'm no mathematician, nor do I work in a field where math is needed. I'm just an ethusiast. Nothing more, nothing less. But please tell me, why do mathematicians tend to be hostile towards physicists or engineers? I mean, they just use math to explain things, or make things happen.

    • @drpeyam
      @drpeyam  4 роки тому +12

      I don’t think they’re really hostile, just some friendly banter

    • @dramwertz4833
      @dramwertz4833 4 роки тому +1

      Right here Right now so im not old enough to br sure but i believe its mostly because of strange matgs they use. E.g. with the engineers ofc it makes sense to approximate and add random constant because then you can get away with a quite right solution but as someone who likes math it just hurts sometimes

    • @RalphDratman
      @RalphDratman 4 роки тому +4

      You didn't ask me, of course, but I have never been aware of mathematicians being hostile toward physicists or engineers! Maybe mathematicians are upset because physicists and engineers use mathematics informally. I am not a mathematician, but to some extent I agree with that. Physicists, particularly, are not usually too concerned with all the details of a particular mathematical manipulation. They quite often do not take time to get definitions straight and so forth. But that would not make me "hostile" to physicists!

    • @Л.С.Мото
      @Л.С.Мото 4 роки тому

      @@RalphDratman and Dr. Peyam
      Maybe hostile was a wrong word to use on my part. However, I have been watching flammable maths, and he tends to make a lot of remarks and jokes about other fields. As a mathematician, he does really seem to attack engineers, and that to a point, where I don't even know if those are still jokes, or his real opinion. In the comments of various math videos, I see a lot of accusations towards engineers, most popular being them round pi and e to 3. I watched many engineers lectures, and they have never done that. Yes, they rather just apply math, and throw in some extra numbers or constants usually to make sure its safe what they are making - but I find it hard to discredit their use of math.

    • @RalphDratman
      @RalphDratman 4 роки тому

      @@Л.С.Мото Thanks for your reply. I have not seen flammable maths yet. Is there a particular video I could watch to get an example of his digs at engineers?

  • @michaelzumpano7318
    @michaelzumpano7318 4 роки тому

    Beautifully explained!

  • @اميمةخروبي
    @اميمةخروبي 11 місяців тому

    Please sir, what is the interperitation of E(t), and how to use E(t) to prove the unicité of the solution of pde

  • @murielfang755
    @murielfang755 3 роки тому

    Energy method is so elegant.

    • @drpeyam
      @drpeyam  3 роки тому +1

      My favorite method!!

    • @drpeyam
      @drpeyam  3 роки тому +1

      Thanks for watching my playlist btw, I love your comments!!

  • @aryammlg6833
    @aryammlg6833 4 роки тому

    Hello Dr.Peyam
    Thank u very much for your videos. I've been watching your PDE playlist and so far it's been soo helpful and crystal clear.
    in your last video, u demonstrated D'alembert formula and derived it and since u solved it generally the answer in the formula is unique.
    I was wondering if we could use the same D'alambert formula in the last video and replace phi and psi functions with 0, as they are the conditions of this problem and show that the answer u=0 is unique. is that a correct method of showing that? or is there sth missing? I'd really appreciate it if u could answer

    • @drpeyam
      @drpeyam  4 роки тому

      Thank you! And sadly no, D’Alembert is for the whole real line, but here we’re focusing on [0,l]

  • @AlexandreGurchumelia
    @AlexandreGurchumelia 4 роки тому

    Both are kinetic together, it's a free field so it has no potential. If you add V(u) in the Hamiltonian that would be a potential energy.

  • @samuelmedlock849
    @samuelmedlock849 8 місяців тому

    At 8:07, how are you able to do this operation on the heat equation when it has u_{tx} and not u_{xt}?

    • @drpeyam
      @drpeyam  8 місяців тому

      utx = uxt by clairaut

  • @nimbaneedison4904
    @nimbaneedison4904 3 роки тому

    How can we apply the energy method for a damped wave equation

  • @RYO-wd2cp
    @RYO-wd2cp 4 роки тому

    We appreciate the energy method!

  • @hitchedtothestitch
    @hitchedtothestitch 3 роки тому

    Thank you so much! Your explanations are fantastic, 10/10!!!!

  • @aunglwin3458
    @aunglwin3458 4 роки тому

    Thanks u very much sir. I want to learn strong maximum principal for harmonic function.

    • @drpeyam
      @drpeyam  4 роки тому

      Maximum Principle ua-cam.com/video/PMjzGEPkQt8/v-deo.html

  • @nirorit
    @nirorit 4 роки тому

    Awesome. As always

  • @yashvindersingh832
    @yashvindersingh832 5 років тому

    Thanks for the video. Can you please also do a video on Green's Function and provide some intuition ( like how it is related to electric potentials)?

    • @drpeyam
      @drpeyam  5 років тому

      Unfortunately I don’t know much about Green’s functions

    • @shambosaha9727
      @shambosaha9727 4 роки тому

      @@drpeyam Come on, Dr Peyam, whom are you trying to fool?

  • @sandorszabo2470
    @sandorszabo2470 4 роки тому

    You 2 tee 😊 Nice derivation.

  • @nomoremathhere
    @nomoremathhere 4 роки тому +1

    I want an energy drink

  • @정대영-l1e
    @정대영-l1e 4 роки тому

    Neat and beautiful!

  • @dgrandlapinblanc
    @dgrandlapinblanc 4 роки тому

    Thank you very much. Come back for me.

  • @manfredwitzany2233
    @manfredwitzany2233 4 роки тому

    In Physics we directly use energy and moventum conservation to solve PDE easily. It is intersting that it is possible to use these techniques from the back side.

  • @rodrigo_p2821
    @rodrigo_p2821 4 роки тому

    Hello!!!

  • @RalphDratman
    @RalphDratman 4 роки тому

    Haven't taken physics in 30 years???? That cannot be true! You last took physics when you were 3 years old?

    • @drpeyam
      @drpeyam  4 роки тому

      13 :)

    • @RalphDratman
      @RalphDratman 4 роки тому +2

      ​@@drpeyam 13 years makes a lot more sense! Sorry, I heard you wrong.
      For my part, I have not taken a physics course in 50 years (Berkeley 1970). Yet I like to suppose I still remember most of what I learned up at Birge Hall, next to the Campanile.
      Except to be honest, I spent most of my time learning how to program the old IBM 1620 computer in the 2nd sub-basement underneath Birge. That opened up a career in computers for me, and so my practical education, if not my credentialing, was accomplished.
      Regardless, I think you got the potential and kinetic energies right. Assuming U(x,t) represents the displacement (say in the z direction) away from the equilibrium (unplucked) position of a point x between 0 and L on a tensioned string at time t, then Uxx(x,t) represents the force at the point x of the string due to the curviness of the string at x, given by the 2nd space derivative at that point. The stretched string experiences a force that is trying to get it back to a straight line at each point, trying to make the 2nd space derivative zero. Then Utt(x,t) represents the acceleration (2nd time derivative) of a point x on the string at time t. Since force = mass times acceleration, and assuming m=1, you get your original PDE. (I think.)

    • @drpeyam
      @drpeyam  4 роки тому

      OMG, Cal!!! I did my undergrad and grad there 😍

    • @RalphDratman
      @RalphDratman 4 роки тому

      @@drpeyam I know you did, and now you are at Irvine, is that right?

    • @drpeyam
      @drpeyam  4 роки тому

      Correct 🙂