Excellent explanation, this is what the difference between video course and study material, video course is something like spoon feeding and study material is something we have to imagine. Really a great job.
I will definitely make a mistake in this question in examination hall but when u analyse this question closely it's like a surprise under a surprise, thanks for decoding different layers of a question...
Sir Visually we can't say zero force on Member GC because external Load is acting along Link GC. Although it is not acting at Point G but the Load is acting along Link GC . Please Clear it , I think we can't get it Visually.
At joint c, the force P will be equalised by component of forces in FC qnd CH in y direction. While considering joint G, you can't consider forces acting on joint C( Obviously method of joint applies for a single joint at a time.) We move to point G for simplicity or else it will be hectic for us to ultimately come to a solution that GC is a zero force member because while considering joint C, there are a large number of unknown forces. So, it makes difficult to visualise. ➡ The force at G should be equal to force at C. So,we can intuitively understand it to be a zero force member.
Excellent explanation, thanks a lot sir you cleared my whole concept in precise way also you taught us The proper thinking process. Even very great teachers with huge experience fail to explain in such logical way, they just give rules on how to find ZFM without telling how they arrived at it.
Just a doubt sir... FG FC HG HC are also zero force members from F and H point respectively as they are from same point F and H and no external forces respectively right ?
Hello sir...I have one doubt from the question bank...In machine design bolt and riveted joint design section...In question number 10 tearing force is taken per pitch length but crushing and shearing strength is taken for all the rivets...Sir can you please help me to get rid of this confusion?
What about the horizontal component of reaction force at E. F(DE) = R(E)cos45 It will balance the force F(DE). SO, F(DE) not equal to zero. PLEASE CLEAR MY DOUBT.
![Lp. Сердце Вселенной #60 РОЖДЕНИЕ ЛОЛОЛОШКИ [Финал] • Майнкрафт](http://i.ytimg.com/vi/YoR0pAV9FVQ/mqdefault.jpg)
Sir whenever you are taking a question, you are seeing the question in all aspects, that was very helpful,
Thank you
Very easy question but a question that needs close examination. Great explanation sir
Damn!! THIS channel deserves millions of subscribers
Sir ive never seen zero force members concept explained so brilliantly.
this was such a brilliant question and explained well.
Yes all basics and mistake cover by this questions..😊
Excellent explanation, this is what the difference between video course and study material, video course is something like spoon feeding and study material is something we have to imagine. Really a great job.
I will definitely make a mistake in this question in examination hall but when u analyse this question closely it's like a surprise under a surprise, thanks for decoding different layers of a question...
I was always confused in this concept u just made it look so easy 👍🏻
Explanation is very interesting and great sir
Thankyou ❤️
superb way of solving and analysing the given problem. thankyou for explaining things so clearly and clearing all of my doubts
Absolutely crystal clear explanation sir!
Thank you, nice way of teaching even below-average people could understand it in a better way. Is there any free video tutorials for Mechanics basics
Sir Visually we can't say zero force on Member GC because external Load is acting along Link GC. Although it is not acting at Point G but the Load is acting along Link GC . Please Clear it , I think we can't get it Visually.
At joint c, the force P will be equalised by component of forces in FC qnd CH in y direction.
While considering joint G, you can't consider forces acting on joint C( Obviously method of joint applies for a single joint at a time.)
We move to point G for simplicity or else it will be hectic for us to ultimately come to a solution that GC is a zero force member because while considering joint C, there are a large number of unknown forces. So, it makes difficult to visualise.
➡ The force at G should be equal to force at C. So,we can intuitively understand it to be a zero force member.
Thanks to both of you .
But at joint c there is a external load is greater than 0 so summation fy becomes Tgc + p .so GC is not a zero force member. Right or not??
Excellent explanation, thanks a lot sir you cleared my whole concept in precise way also you taught us The proper thinking process. Even very great teachers with huge experience fail to explain in such logical way, they just give rules on how to find ZFM without telling how they arrived at it.
thanku so much... i always eagerly waiting for ur concept vedios....#sir pls cover some concept on tom .....
Wow I was waiting for this
In the example at beginning if an external to force acting at point B then BD is a zero force member or not??
Bc & BD bhi zero hoga na ????
GC directly carrying the force P, so how GC become zero force member
Thank you so much sir you really explain very easily ❤️🙏🏻🙏🏻🙏🏻🙏🏻
Thank you sir
For teaching a easy ways to understand zero member force concept
Sir Force P and GC also Colinear , then why the other forces are not Zero at point C
💙💙💙
Wonderful explanation sir🤗
Really nice teaching thank you so much sir
What a tricky Q! 😂😂 especially the DE one
Video is helpful, thank you so much
great explanation brother
great explanation. thank you.
8.26 ...sir E point per €X=0 & €Y=0
Equation lagaya to ..DE member bhi zero force member hona chahiye na ???
Very nice and clearly explained sir.tq
Just a doubt sir... FG FC HG HC are also zero force members from F and H point respectively as they are from same point F and H and no external forces respectively right ?
Hello sir...I have one doubt from the question bank...In machine design bolt and riveted joint design section...In question number 10 tearing force is taken per pitch length but crushing and shearing strength is taken for all the rivets...Sir can you please help me to get rid of this confusion?
can anyone plz... tell me that ...in the first question what if the load at the point B , would it be also zero force member??
No if load is apply, then it will not zero force memeber.
Simply apply sine rule for joint connecting 3 members
SIR here AB and BC will also be zero force members?
actually i asked the same question , got no reply. I saw your question , then i thought it must be coz someone asked
Thanks to explore such concept.it enhance knowledge.#physicswithswapnil
hello sir discuss reaction forces and how to find it in trusses
Does the IES conventional previous years paper help in GATE preparation to get a good rank?
What about the horizontal component of reaction force at E. F(DE) = R(E)cos45
It will balance the force F(DE).
SO, F(DE) not equal to zero.
PLEASE CLEAR MY DOUBT.
No bro R(E)cos45= F(DE)+ F(HE)cos45
And F(HE)sin45=R(E)sin45
Hence F(HE)=R(E) and F(DE)=0
Horizontal Component at E is F(DE) - HE(cos45) = - R(E)cos45, here HE(cos45) = R(E)cos45. So F(DE) = 0
@@KrishnaYadav-ox7zz thanks a lot...it saved my hours..your comment really helped me..😊
Anjali Bhushan never mind dear😊
aren't AB and BC zero force members? Anyone?
a lot of thanks
Sir please conduct a session on pure substance
Sir member AB nad BC also zero kindly check once...by collinear concept @joint c
Sir entire structure analysis ka lecture lagayiye
Sir...ji....awesome
Pls give solution for inventory control problem in set-1 me2020 paper
Best video so far.
Sir kabhi hindi mai bhi bola karo... Badi kripya hogi