U.V.L.- SFD & BMD(Uniformily varying load on a simply supported beam)

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  • Опубліковано 1 гру 2024

КОМЕНТАРІ • 24

  • @sagnikchakraborty1264
    @sagnikchakraborty1264 4 роки тому +4

    Nicely explained video sir

  • @nileshrajput7461
    @nileshrajput7461 3 роки тому +1

    Nicely explained sir
    One suggestion
    U should both the cases in thumbnail of the video

  • @keshawpatel4856
    @keshawpatel4856 8 місяців тому +1

    Excellent sir

  • @rohanbharti1169
    @rohanbharti1169 4 роки тому +2

    much neeeded video on uvl..

  • @Horrorwallah_1
    @Horrorwallah_1 4 роки тому +2

    Good explanation

  • @saikatmishra7240
    @saikatmishra7240 Рік тому +1

    Sir,at the point B ,wl/3 is positive according to value but why taken it negative or downward direction in the diagram?

    • @civiluptodate1580
      @civiluptodate1580  Рік тому

      If we cut any section in between the length of beam then shear force to the left of that section will be positive upwards and S.F. to the right of that section will be positive downwards. [Sign convention]

    • @saikatmishra7240
      @saikatmishra7240 Рік тому

      @@civiluptodate1580 sir plz tell Bending Moment sign convention

  • @shivendrasinghchauhan7860
    @shivendrasinghchauhan7860 4 роки тому +2

    Great bro

  • @sagnikchakraborty1264
    @sagnikchakraborty1264 4 роки тому +2

    Thanks Chauhan sir for uploading we need videos frequently

  • @CivilsPlant
    @CivilsPlant 2 місяці тому

    Wow. Perfect.

  • @SurgingDiplomat
    @SurgingDiplomat Рік тому +1

    Last me uvl w load ordinate at left end k case me
    BMD diagram right hand side me wrong hai.. SFD ki slope decreasing hai to BMD ki bhi decreasing honi chaiye... But but apki increasing hai

    • @civiluptodate1580
      @civiluptodate1580  Рік тому

      d/dx of M = V.
      It means slope of BMD is equal to shear force.
      From left to right in SFD, value of SF goes on decreasing till zero, therefore slope of BMD goes on decreasing.
      When SF becomes zero (d/dx of M = V), BM will be constant at that point and Slope of BMD will be straight line at that point.
      Then SF goes on increasing in negative direction, therefore slope of BMD goes on increasing.
      Therefore, slope of BMD first decreasing then increasing.

  • @do.you.
    @do.you. 3 роки тому +2

    What if the load is increasing from 1 to 2 or something,not from 0 ?

  • @Murkong-c2q
    @Murkong-c2q 3 роки тому +1

    woaahhh thankyou so muchhh

  • @arabindasadhukhan547
    @arabindasadhukhan547 3 роки тому +1

    Thanks a lot thanks a lot and again thanks a lot

  • @Harshraj-un2el
    @Harshraj-un2el 3 роки тому +1

    Thank you sir.

  • @yokeshbhalamuruhan7047
    @yokeshbhalamuruhan7047 3 роки тому +1

    💯💯

  • @SHIVAM-bm3ys
    @SHIVAM-bm3ys 3 роки тому +1

    Reaction glt nikale ho ji

    • @civiluptodate1580
      @civiluptodate1580  3 роки тому

      Reactions for triangular loading are correct.
      U please check again.

  • @A.Duke003
    @A.Duke003 3 роки тому +2

    You made it too hard! It coul be simply described.