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Numeric Nest
Pakistan
Приєднався 2 гру 2023
Welcome to my UA-cam channel " Numeric Nest ", where we demystify complex mathematical concepts with clarity and enthusiasm! Join us for engaging tutorials, problem-solving sessions, and insightful explorations into the world of numbers. Whether you're a student seeking assistance or a math enthusiast looking for a deeper understanding, our channel is your go-to destination for mathematical enlightenment.
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#Mathematics
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Don't forget to like, share, and subscribe for more math Olympiad tips and tricks. Happy problem-solving!
Thank you🌹
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#calculus
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#Geometry
#11thclassmath
#12thclassmath
#ics
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Don't forget to like, share, and subscribe for more math Olympiad tips and tricks. Happy problem-solving!
Thank you🌹
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Miss you have got it wrong! X^3+Y^3=(x+y).(X^2-x.y+y^2)
What about a=0 and b=22?
Yes but in our question it is given that a and b belongs to positive integer
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*=read as square root ^=read as to the power As per question 4^(sinx)^2+4^(cos x)^2=3.*2 Let us explain 4^(cosx)^2=4^(1-sinx^2) =(4^1)/(4^sinx^2)=4/(4^sinx^2) Suppose 4^sinx^2=Y So the given question can be written as below Y+(4/y)=3.*2 (Y^2+4)/y=3.*2 Y^2+4=3.*2.y Y^2- 3.*2y+4=0 Here a=1, b=-3.*2, c=4 Putting the formula (-b± *(b^2-4ac)/2a, we shall get Y=-(-3.*2)±*{(3.*2)^2-4.1.4)}/2.1 Y=3.*2±*{(18-16)}/2 Y={3.*2±*2}/2 Y=*2{(3±1)}/2 Y=(*2.4)/2 and( *2.2)/2 Y=2.*2 and *2 Y=(*2)^3 and (*2)^1 According to the 'suppose' Y=4^(sinx^2), {4=(*2)^4} Y=*2^(4sinx^2) Now put the value of Y *2(4sinx^2)=(*2)^3 4 sinx^2=3 Sinx^2=3/4 Sinx=±(*3/2) Sinx =sin60 X=60 degree Again (*2)^4sinx^2=(*2)^1 4sinx^2=1 Sinx^2=1/4 Sinx=±1/2 Sinx =sin30 X=30 degree (N:B: There may be another pair of answers for negative values )
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The mathematics is fine. Its how you write"x" and use x for multiplication that are problems. Explanations should be clear and concise. One cant use x as a variable and use x for multiplication!!Think of the people trying to follow your reasoning.
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(30/12)(7x)^2(5)^2 = (30/12)7){49x^2 ➖ 25}=24x^2 (30/12)^24 (36/100)^(x) ➖ (1) = (36/100){x^2 ➖ 1}= 0 +0 ➖ =1 =(36/100).( 20/12) (5^4/3^4)4^6.(5^12^2/3^2^2)2^23^2 ( 1^11^1/3^1^2)^1^13^2 (1^1)^3^2 23 (x ➖ 3x+2). (6^6/10^10) (3^2^3^2/2^52^5)( 1^13^1/1^12^1) 32 (x ➖ 3x+2).
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Couldn't figure out to use the degree indicator with 30, but did for 60. Oy.
Thanks for your contribution, I wonder if you could help me solve a problem It would be a great help 4(x^x+1)+4x^x=5x^¼ Find (x+2)^x Thankyou
Okay Soon....
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i think x^3 + y^3 = (x+y)(x^2-xy+y^2)
It should have been (x+y)…! And -xy in the 2nd paranthesis.
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