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Graduate tutorial
Приєднався 18 вер 2019
Why is the Fourier transform so important?
This video will help to know the importance of Fourier transform in signal processing.
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Відео
Why do we calculate Impulse response of a system?
Переглядів 66Рік тому
This tutorial will help to understand why we always calculate the impulse response of a system.
Resistance Temperature Detector (RTD) principle and working
Переглядів 6904 роки тому
Resistance Temperature Detector (RTD) principle and working
Principle, Operation and Gauge Factor Calculation of Strain Gauge
Переглядів 18 тис.4 роки тому
Principle, Operation and Gauge Factor Calculation of Strain Gauge
Types of Transducers (Electronic Measurement and Instrumentation)
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Types of Transducers (Electronic Measurement and Instrumentation)
Simulation of transmitter and receiver for 16-QAM (MATLAB Experiment)
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Simulation of transmitter and receiver for 16-QAM (MATLAB Experiment)
Simulation of transmitter and receiver for QPSK (MATLAB Experiment)
Переглядів 7 тис.4 роки тому
Simulation of transmitter and receiver for QPSK (MATLAB Experiment)
Decimation in Time (DIT) FFT radix-2 method example problem
Переглядів 5554 роки тому
Decimation in Time (DIT) FFT radix-2 method example problem
Matrix method for DFT( Discrete Fourier Transform) calculation
Переглядів 2014 роки тому
Matrix method for DFT( Discrete Fourier Transform) calculation
Decimation in Time (DIT) FFT algorithm radix-2 method
Переглядів 7304 роки тому
Decimation in Time (DIT) FFT algorithm radix-2 method
Difference between DTFT and DFT (Discrete fourier transform)
Переглядів 25 тис.5 років тому
Difference between DTFT and DFT (Discrete fourier transform)
THANK YOU. Best video ever to understand this topic, I am shocked by how good you are
helpful! thanks !
thank god you are here !!!
put some captions pls, hard to understand anything with this audio
In This video....❌ In This Tutorial.....❌ In This lecture.....❌ In This Video Tutorial Lecture ✅ 👍🏻
Drho/Ds=DR and Drho/Ds=Drho how
Very compact and precise. Thank you for the clear explanation of the topic.
EXCELLENT!
WTF, you are the best person I have seen who talks about the difference between these two shits. Thank you so much.
Thank-you sir
Length of the sequence is N=3
So amplitude vs time, to amplitude vs frequency where it is easier to understand. 👍
To the point and detailed video. Thanks alot I was searching for this for a long time!
What is 'w' equal to in DTFT sir? Is it w=2π/N or w=2π/T?? In DFT it is w=2πkn/N......
Amazing
the way you are explaining the topic is superb sir
very good
well done..many thx
Super sir
🖤🖤
Hello could you please give us the pdf or ppt file in the description box
clc; clear; clear var; %% N=3e5; alpha16qam=[-3 -1 1 3]; Es_N0_dB =[0:20]; ipHat=zeros(1,N); %% for ii=1:length(Es_N0_dB) ip=randsrc(1,N,alpha16qam)+j*randsrc(1,N,alpha16qam); s=(1/sqrt(10))*ip; n=1/sqrt(2)*[randn(1,N)+j*randn(1,N)]; y=s+10^(-Es_N0_dB(ii)/20)*n; y_re=real(y); y_im=imag(y); ipHat_re(find(y_re< -2/sqrt(10)))=-3; ipHat_re(find(y_re> 2/sqrt(10)))=3; ipHat_re(find(y_re>-2/sqrt(10) & y_re<=0))=-1; ipHat_re(find(y_re>0 & y_re<=2/sqrt(10)))=1; ipHat_im(find(y_im< -2/sqrt(10)))=-3; ipHat_im(find(y_im> 2/sqrt(10)))=3; ipHat_im(find(y_im> -2/sqrt(10) & y_im<=0))=-1; ipHat_im(find(y_im> 0 & y_im<=2/sqrt(10)))=1; ipHat = ipHat_re + j*ipHat_im; nErr(ii)=size(find([ip- ipHat]),2); end %% simBer=nErr/N; theoryBer=3/2*erfc(sqrt(0.1*(10.^(Es_N0_dB/10)))); figure semilogy(Es_N0_dB,theoryBer,'b.-','LineWidth',1); hold on semilogy(Es_N0_dB,simBer,'mx-','LineWidth',1); axis([0 20 1e-5 1]) grid on
Thanks
Well, the calculation is wrong
Sir, the calculation is correct. The range of n is from 0 to 2 only, that's why there are only three terms in K=0 calculation.
*PLZ HELP*. Given a pressure of 2kpa, nominal resistance of 120 ohm, diameter of strain gauge 0.1mm, a GF of 2. What will be the change in resistance value of the strain gauge?....in short I wanta formula to calculate the change in resistance of strain gauge for a given INPUT PRESSURE
could you attach link of the code and experiment
thankuu sir
Thank you. You made the difficult topic so easy to understand!
can you provide the code in a pdf form
Thanks alot for this presentation, but there is a small mistake done. X(0)=Sum(from 0 to 3) of (1/3)= 4*(1/3)= 4/3, cz the number of terms is 4. Thank you!!!
Thank you for your comment. Sir, the calculation is correct. The range of n is from 0 to 2 only, that's why there are only three terms in K=0 calculation.
Great informational video . Sir audio level is low. One more point i have to add is that digital processor works on discrete values .Thus we convert dtft to dft.
Thank you for sharing !!
well done
not audible.
Sir voice is not audible
thank you sir
Thanks for good explanation
very good explanation keep it up i am feeling lucky