Grantstrong
Grantstrong
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Відео

If the wide-flange beam is subjected to a shear of V=20 kN, determine the shear stress - 7-1
Переглядів 554 години тому
7-1. If the wide-flange beam is subjected to a shear of V=20 kN, determine the shear stress on the web at A. Indicate the shear stress components on a volume element located at this point. All problems from Mechanics of Materials Eleventh Edition by Russell C. Hibbeler.
The wood beam has a rectangular cross section in the proportion shown - 6-93
Переглядів 677 годин тому
6-93. The wood beam has a rectangular cross section in the proportion shown. Determine its required dimension b if the allowable bending stress is σallow=10 MPa. All problems from Mechanics of Materials Eleventh Edition by Russell C. Hibbeler.
If w=5 kip/ft, determine the absolute maximum bending stress in the beam - 6-81
Переглядів 519 годин тому
6-81. If w=5 kip/ft, determine the absolute maximum bending stress in the beam. All problems from Mechanics of Materials Eleventh Edition by Russell C. Hibbeler.
Determine the largest intensity of distributed load w that the beam can support - 6-80
Переглядів 5912 годин тому
*6-80. Determine the largest intensity of distributed load w that the beam can support so that the bending stress does not exceed σmax=22 ksi. All problems from Mechanics of Materials Eleventh Edition by Russell C. Hibbeler.
An adventurous archaeologist crosses between two rock cliffs by slowly going hand over hand - 5 .60
Переглядів 7414 годин тому
5.60 •• An adventurous archaeologist crosses between two rock cliffs by slowly going hand over hand along a rope stretched between the cliffs. He stops to rest at the middle of the rope (Fig. P5.60). The rope will break if the tension in it exceeds 2.50×104 N, and our hero’s mass is 90.0 kg. (a) If the angle θ is 10.0°, what is the tension in the rope? (b) What is the smallest value θ can have ...
Boxes A and B are in contact on a horizontal, frictionless surface - 4.23
Переглядів 1,9 тис.4 місяці тому
4.23 •• Boxes A and B are in contact on a horizontal, frictionless surface (Fig. E4.23). Box A has mass 20.0 kg and box B has mass 5.0 kg. A horizontal force of 250 N is exerted on box A. What is the magnitude of the force that box A exerts on box Problem from University Physics with Modern Physics
If M=10 kip⋅ft, determine the resultant force this moment exerts on the top and bottom - 6-51
Переглядів 8785 місяців тому
6-51. If M=10 kip⋅ft, determine the resultant force this moment exerts on the top and bottom boards of the beam. All problems from Mechanics of Materials Eleventh Edition by Russell C. Hibbeler.
If M=10 kip⋅ft, determine the maximum bending stress in the beam - 6-50
Переглядів 1,2 тис.5 місяців тому
6-50. If M=10 kip⋅ft, determine the maximum bending stress in the beam. Sketch a three-dimensional view of the stress distribution acting over the cross section. All problems from Mechanics of Materials Eleventh Edition by Russell C. Hibbeler.
The assembly is made of A-36 steel. Determine the angle of twist at C - 5-55
Переглядів 4896 місяців тому
5-55. The assembly is made of A-36 steel and consists of a solid rod 20 mm in diameter fixed to the inside of a tube using a rigid disk at B. Determine the angle of twist at C. The tube has an outer diameter of 40 mm and wall thickness of 5 mm. All problems from Mechanics of Materials Eleventh Edition by Russell C. Hibbeler.
The assembly is made of A-36 steel. Determine the angle of twist at D - 5-54
Переглядів 6666 місяців тому
5-54. The assembly is made of A-36 steel and consists of a solid rod 20 mm in diameter fixed to the inside of a tube using a rigid disk at B. Determine the angle of twist at D. The tube has an outer diameter of 40 mm and wall thickness of 5 mm. All problems from Mechanics of Materials Eleventh Edition by Russell C. Hibbeler.
If the tube is subjected to a uniform distributed torque of t = 1.2 kN⋅m/m - 5-24
Переглядів 3616 місяців тому
*5-24. If the tube is subjected to a uniform distributed torque of t0 = 1.2 kN⋅m/m, determine the shear stress developed at point C. The inner radius is 20 mm and the outer radius is 30 mm. All problems from Mechanics of Materials Eleventh Edition by Russell C. Hibbeler.
The solid shaft is fixed to the support at C and subjected to the torsional loadings - 5-9
Переглядів 1 тис.6 місяців тому
5-9. The solid shaft is fixed to the support at C and subjected to the torsional loadings. Determine the shear stress at points A and B, and sketch the shear stress on volume elements located at these points. All problems from Mechanics of Materials Eleventh Edition by Russell C. Hibbeler.
A machinist is using a wrench to loosen a nut. The wrench is 25.0 cm long - 10.7
Переглядів 3976 місяців тому
10.7 • A machinist is using a wrench to loosen a nut. The wrench is 25.0 cm long, and he exerts a 17.0 N force at the end of the handle at 37° with the handle (Fig. E10.7). (a) What torque does the machinist exert about the center of the nut? (b) What is the maximum torque he could exert with a force of this magnitude, and how should the force be oriented? Problem from University Physics with M...
Three forces are applied to a wheel of radius 0.350 m, as shown in Fig. E10.4 - 10.4
Переглядів 1 тис.6 місяців тому
10.4 • Three forces are applied to a wheel of radius 0.350 m, as shown in Fig. E10.4. One force is perpendicular to the rim, one is tangent to it, and the other one makes a 40.0° angle with the radius. What is the net torque on the wheel due to these three forces for an axis perpendicular to the wheel and passing through its center? Problem from University Physics with Modern Physics
A thin, light string is wrapped around the outer rim of a uniform hollow cylinder of mass - 10.29
Переглядів 5086 місяців тому
A thin, light string is wrapped around the outer rim of a uniform hollow cylinder of mass - 10.29
A 15.0 kg stone slides down a snow-covered hill, leaving point A at a speed of 10.0 m/s - 7.45
Переглядів 1,3 тис.6 місяців тому
A 15.0 kg stone slides down a snow-covered hill, leaving point A at a speed of 10.0 m/s - 7.45
A block with mass 0.50 kg is forced against a horizontal spring of negligible mass - 7.9
Переглядів 7896 місяців тому
A block with mass 0.50 kg is forced against a horizontal spring of negligible mass - 7.9
A small rock with mass 0.20 kg is released from rest at point A, which is at the top edge - 7.9
Переглядів 1,2 тис.6 місяців тому
A small rock with mass 0.20 kg is released from rest at point A, which is at the top edge - 7.9
Initially the 6.00 kg block is moving downward and the 8.00 kg block is moving to the right - 6-81
Переглядів 1,4 тис.8 місяців тому
Initially the 6.00 kg block is moving downward and the 8.00 kg block is moving to the right - 6-81
A 5.00 kg block is moving at υ0=6.00 m/s along a frictionless, horizontal surface - 6-79
Переглядів 1 тис.8 місяців тому
A 5.00 kg block is moving at υ0=6.00 m/s along a frictionless, horizontal surface - 6-79
Determine the largest intensity of distributed load w0 that the beam can support - 6-82
Переглядів 2,2 тис.8 місяців тому
Determine the largest intensity of distributed load w0 that the beam can support - 6-82
The man has a mass of 78 kg and stands motionless at the end of the diving board - 6-71
Переглядів 1,1 тис.8 місяців тому
The man has a mass of 78 kg and stands motionless at the end of the diving board - 6-71
The beam is subjected to a moment of M=40 kN⋅m. Determine the bending stress - 6-62
Переглядів 1,4 тис.8 місяців тому
The beam is subjected to a moment of M=40 kN⋅m. Determine the bending stress - 6-62
Determine the absolute maximum shear stress developed in the shaft - 5-13
Переглядів 1,1 тис.8 місяців тому
Determine the absolute maximum shear stress developed in the shaft - 5-13
Determine the maximum shear stress developed in regions CD and DE of the shaft - 5-12
Переглядів 3298 місяців тому
Determine the maximum shear stress developed in regions CD and DE of the shaft - 5-12
The copper pipe has an outer diameter of 40 mm and an inner diameter of 37 mm - 5-4
Переглядів 2 тис.8 місяців тому
The copper pipe has an outer diameter of 40 mm and an inner diameter of 37 mm - 5-4
The 0.5-kg ball strikes the rough ground and rebounds with the velocities shown - F15-1
Переглядів 1,5 тис.8 місяців тому
The 0.5-kg ball strikes the rough ground and rebounds with the velocities shown - F15-1
A 2.5-kg block is given an initial velocity of 3 m/s up a 45° smooth slope - 15-2
Переглядів 2718 місяців тому
A 2.5-kg block is given an initial velocity of 3 m/s up a 45° smooth slope - 15-2
The composite beam is made of steel (A) bonded to brass (B) and has the cross section shown - 6-120
Переглядів 2,2 тис.8 місяців тому
The composite beam is made of steel (A) bonded to brass (B) and has the cross section shown - 6-120

КОМЕНТАРІ

  • @calpec5803
    @calpec5803 День тому

    Can i use the Vq/It formula in this question instead of Mc/I

  • @qipick8889
    @qipick8889 3 дні тому

    save my life

  • @Yeparoonies
    @Yeparoonies 3 дні тому

    when me and @evanchadeayne5970 got a statics final at 8am, its currently 5:38am and we are learning this for the first time

  • @evanchadeayne5970
    @evanchadeayne5970 3 дні тому

    I think im in love...

  • @unamedchannel4267
    @unamedchannel4267 3 дні тому

    thanks man

  • @snowy6156
    @snowy6156 4 дні тому

    Ok. I'm right. Dang people out on the internet scaring me with answers like 0.024

  • @aslsztanrkulu8763
    @aslsztanrkulu8763 5 днів тому

    thx brother

  • @jacksonerickson3713
    @jacksonerickson3713 6 днів тому

    You're the goat

  • @feryhartawan4625
    @feryhartawan4625 6 днів тому

    arighato

    • @calcgang
      @calcgang 5 днів тому

      ありがとございます!

  • @pobchamp
    @pobchamp 6 днів тому

    whats up calculus gang

  • @markhutchinson11
    @markhutchinson11 7 днів тому

    Thanks for the video!

  • @gabyrod9755
    @gabyrod9755 8 днів тому

    New Mexico gang!!! Rep that zia symbol :D

  • @amandagunter618
    @amandagunter618 10 днів тому

    Absolute lifesaver 🙌

  • @danielt.6338
    @danielt.6338 12 днів тому

    Think you made a mistake - the number two can't be factored out of x^2(2-rootx), at least not until after you integrate.

    • @ItsJustOrganizedKhaos
      @ItsJustOrganizedKhaos 11 днів тому

      actually you can remove it since its a constant being mutplied to x^2rootx. :)

  • @HidayatHashmi-w7x
    @HidayatHashmi-w7x 13 днів тому

    Form Pakistan thank you sir g

  • @JasonHong
    @JasonHong 13 днів тому

    thank you so much for these videos!

  • @petrosNguse
    @petrosNguse 13 днів тому

    Thanks this help me.

  • @dejoylee775
    @dejoylee775 14 днів тому

    WHY DID I NOW JUST FIND YOU OMG

  • @hahano499
    @hahano499 14 днів тому

    ily calc gang

  • @cheeselord8153
    @cheeselord8153 15 днів тому

    you are crazy underrated, i wouldve actually failed this class if it wasnt for you

  • @ryanliang3604
    @ryanliang3604 17 днів тому

    thanks bro #calcgang

  • @brucewellalejandria599
    @brucewellalejandria599 19 днів тому

    isn't the y bar is used to get the Iy and not the Ix??

  • @sadiaashraf3907
    @sadiaashraf3907 20 днів тому

    Why not use I_p =pi*r^4 / 4? Isn't that the formula from section 5.9 shear stress in beams with circular cross sections? I noticed you used divided by 2 instead of 4.

  • @corrinnesnyder
    @corrinnesnyder 20 днів тому

    I love you, thank you

  • @amandagunter618
    @amandagunter618 21 день тому

    This was super helpful. I sometimes have a difficult time relating all of the different equations. Thank you!!

  • @slommymeat333
    @slommymeat333 22 дні тому

    the start had me dying, thank you sir

  • @daveyo3654
    @daveyo3654 24 дні тому

    Thank you man your videos have always been very helpful

  • @PabloFlexscobar222
    @PabloFlexscobar222 24 дні тому

    Thank you bro!

  • @philiptetherow71
    @philiptetherow71 26 днів тому

    I love that you found the glare on the board and marked that out. Awesome to see the consideration.

  • @sunRay04
    @sunRay04 26 днів тому

    Why is your shirt green?

  • @sealz4948
    @sealz4948 29 днів тому

    2:25 how did you know it was 90

  • @Luna-tz6yl
    @Luna-tz6yl Місяць тому

    Good morrow sir, I can finally acquire the work performed by a force field! as my faculty professor instructed! I am in your debt sir. Very well

  • @AmirAlimohammadi-u1f
    @AmirAlimohammadi-u1f Місяць тому

    Sorry From which book is this question???

    • @calcgang
      @calcgang 29 днів тому

      Check the description

  • @OrgasmicCrouton
    @OrgasmicCrouton Місяць тому

    god bless you

  • @quarantinedgoose5396
    @quarantinedgoose5396 Місяць тому

    god bless bro

  • @amitattafe
    @amitattafe Місяць тому

    Thanks

  • @ctaney2254
    @ctaney2254 Місяць тому

    What up CALC GANG. Thanks! Really helped for my midterm

  • @harlanabdullah4690
    @harlanabdullah4690 Місяць тому

    thank u bro

  • @Luna-tz6yl
    @Luna-tz6yl Місяць тому

    Thank you for your hard work!🍄🥑🍓

  • @denier_of_paulythiesm
    @denier_of_paulythiesm Місяць тому

    Thanks man. I was trying to solve it by method of sections... Really helpful! Also that outline you drew on the board around the reflecting lights to adjust the camera angle is such a big brain move. XD

  • @henryguy2677
    @henryguy2677 Місяць тому

    Thanks a lot! You really helped me understand this one!

  • @TheWinterRaven
    @TheWinterRaven Місяць тому

    could u learn to do lighting

  • @gtliam
    @gtliam Місяць тому

    Great work, thank you!

  • @numa7215
    @numa7215 Місяць тому

    Please do 6.67 6.80 6.98 and 6.108 from statics 15e?

  • @Gr8Wizard713
    @Gr8Wizard713 Місяць тому

    shouldn't the final units be m^2 for area

  • @williambonilla4608
    @williambonilla4608 Місяць тому

    Thanks, this clarified a lot with regards to which radius to use. Also, your thumbnails are hilarious!

  • @lilzip5443
    @lilzip5443 Місяць тому

    Its not confusing anymore!!

  • @thomasmcguigan5626
    @thomasmcguigan5626 Місяць тому

    When calculating the moment for the x > 8 part, why is the distributed load included? I was under the impression that when you isolate a section of th beam, anything not within those limits doesn't factor in to the equation. I see that it is the correct answer according to the textbook, but I don't understand.

  • @awesomedawsonstudios
    @awesomedawsonstudios Місяць тому

    thank you! Saved me so much time

  • @kenitopaul6652
    @kenitopaul6652 Місяць тому

    shouldn't the last part in the final equation be + 1/2(0.05)(vc)^2? or is it because it's energy that we don't care about direction