Відео

Glad it was helpful!

Here, the limit is 0 to 1. We need two gauss points. So, we need to divide 0 to 1 into three equal parts to get two gauss points (shown at 9.07 minutes in the video). So, points (1/3) & (2/3) divide limit into three equal parts and hence two gauss points are obtained.

Here, the limit is 0 to 1. We need two gauss points. So, we need to divide 0 to 1 into three equal parts to get two gauss points (shown at 9.07 minutes in the video). So, points (1/3) & (2/3) divide limit into three equal parts and hence two gauss points are obtained.

@@shubhamvdeshmukh7625 Ohk....Thank You So Much Sir🙏😊

How did we understand that we need 2 gauss points?

Good Luck!

The ode for this problem is a 2nd-order, linear, non-homogenous ODE with constant coefficients. For a non-homogenous ODE, you can use the method of undetermined coefficients (MUC) or method of variational parameters (MVP). Since the we have constant coefficients for this one, MUC is applicable. The forcing function here is just a constant, -1, so your steady state solution is of the form yss = k. k = -1 for this problem. The total solution is composed of the homogenous solution and the non-homogenous solution (y = -1). For the homogenous solution, you just equate the sum of y and its derivatives to zero and substitute y=e^(at) in the ODE and solve for a.

same doubt i had as well

You can choose any point for the collocation. What matters is that those collocation points satisfy the governing differential equation, which you do by substituting those points into the ODE.

Here, the limit is 0 to 1. We need two gauss points. So, we need to divide 0 to 1 into three equal parts to get two gauss points (shown at 9.07 minutes in the video). So, points (1/3) & (2/3) divide limit into three equal parts and hence two gauss points are obtained.

Thank You Sir!

Tnank You.

Thank You so much.

Thank You so much 😊😊

Thanks Aman Bhai!

Thanks Vikrant!