MATH MADE EASY WITH LAUREL
MATH MADE EASY WITH LAUREL
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Integration by Partial Fractions - Part 4
This video explains how to do integration by partial fractions when there are repeated quadratic factors. An example is shown.
Переглядів: 62

Відео

Integration by Partial Fractions Part 3
Переглядів 325 місяців тому
This video explains how to integrate a rational function by breaking it down into partial fractions when the factors in the denominator are quadratic. Two examples are shown to illustrate the technique.
Integration by Partial Fractions Part 2
Переглядів 5611 місяців тому
This video explains how to use integration by partial fractions to integrate rational functions with repeated linear factors in the denominator. Two examples are shown.
Integration by Partial Fractions Part 1
Переглядів 6311 місяців тому
This video explains how to do integration by partial fractions. It shows with examples how to deconstruct a rational function which cannot be integrated into the sum of simpler fractions, which can be integrated using the basic log pattern of integration. This video covers rational functions having non-repeated linear factors.
Using Excel for Descriptive Statistics
Переглядів 38Рік тому
This video explains the specific functions in Excel to find various measures of central tendency (mean, median, and mode) as well as measures of dispersion (range, variance, and standard deviation). Examples are shown.
Measures of Dispersion - Range, Variance, and Standard Deviation
Переглядів 2,5 тис.Рік тому
This video explains how to calculate the range, variance, and standard deviation on a set of data. Examples are shown.
Measures of Central Tendency - Mean, Median, and Mode
Переглядів 286Рік тому
This video defines the three measures of central tendency - the mean, median and mode. Definitions are given for a set of data, a frequency distribution, and grouped data. Examples of each are shown.
Baye's Theorem
Переглядів 115Рік тому
This video explains Baye's Theorem of probability. The theorem allows a person to find conditional probability when the reverse conditional probability is known. Examples are shown.
Multiplication Rule of Probability with Dependent Events (Conditional Probability)
Переглядів 165Рік тому
This video explains how to use the multiplication rule of probability with dependent events. It is also known as conditional probability. Numerous examples are given.
Multiplication Rule of Probability
Переглядів 118Рік тому
This video explains the multiplication rule of probability for independent events. It shows various examples.
Addition Rule of Probability with Venn Diagrams
Переглядів 436Рік тому
This video provides examples of the addition rule in probability and uses Venn diagrams to organize the probabilities. Examples with events that are mutually exclusive and events that are not mutually exclusive are included.
Probability Rules
Переглядів 170Рік тому
This video discusses the various rules of probability including the complement rule and the addition rule. Examples are illustrated.
Probability Using Counting Rules
Переглядів 924Рік тому
This video show various solutions of probability problems using the counting rules for combinations and permutations. Examples include probabilities of winning a lottery, having a certain combination on a lock, choosing certain cards, and friends sitting together.
Probability vs Odds
Переглядів 1692 роки тому
This video explains the difference between probability of an event happening and the odds of an event happening. It also explains how to change probability to odds and odds to probability. Various examples are given.
Introduction to Probability
Переглядів 1182 роки тому
This video introduces and defines probability. It shows a number of typical examples.
More Venn Diagrams
Переглядів 392 роки тому
More Venn Diagrams
Venn Diagrams
Переглядів 592 роки тому
Venn Diagrams
Counting Rules
Переглядів 782 роки тому
Counting Rules
Permutations in a Circle
Переглядів 1112 роки тому
Permutations in a Circle
Permutations with Repeated Symbols
Переглядів 1042 роки тому
Permutations with Repeated Symbols
More Permutations and Combinations
Переглядів 1152 роки тому
More Permutations and Combinations
Permutations and Combinations
Переглядів 1302 роки тому
Permutations and Combinations
Factorials
Переглядів 1072 роки тому
Factorials
Order of Operations
Переглядів 1762 роки тому
Order of Operations
Changing Concentrations
Переглядів 2483 роки тому
Changing Concentrations
Specific Gravity and Assay and Changing Concentrations
Переглядів 1,2 тис.3 роки тому
Specific Gravity and Assay and Changing Concentrations
Normality
Переглядів 1153 роки тому
Normality
Molarity
Переглядів 903 роки тому
Molarity
Percent Solutions
Переглядів 1223 роки тому
Percent Solutions
Serial Dilutions
Переглядів 873 роки тому
Serial Dilutions

КОМЕНТАРІ

  • @wilmesllc
    @wilmesllc 11 днів тому

    Love this! Thank you so much this really helped me calculate for an OSHA issue

    • @laurel500
      @laurel500 11 днів тому

      Glad to hear it was helpful.

  • @sanjaygur7261
    @sanjaygur7261 16 днів тому

    Your explanation method very nice . Can you make video for angular offset alignment reverse dial.

  • @iqbalfamily2870
    @iqbalfamily2870 Місяць тому

    thanks, that is very easy method and explained very well😇

    • @laurel500
      @laurel500 Місяць тому

      Thank you for your positive feedback.

  • @ledickin69
    @ledickin69 Місяць тому

    Gold. Thank you

  • @JuanGabrielOyolaCardona
    @JuanGabrielOyolaCardona Місяць тому

    Thanks for sharing 😀👍 greetings from Colombia.

    • @laurel500
      @laurel500 Місяць тому

      Hola - mucho gusto!

  • @prasadrao9432
    @prasadrao9432 Місяць тому

    Madam 🙏, your teaching is very good and helps for application to many areas in day to day life, for example trading. If possible please make a video relating to trade market.

  • @AlethaWeyulu
    @AlethaWeyulu Місяць тому

    Goodday Ma'am were you not supposed to expand 6:19 that out and then integrate and when I used substitution rule I got (x^2 -5)^3 × du/2x

    • @mathmadeeasywithlaurel9353
      @mathmadeeasywithlaurel9353 Місяць тому

      When you are integrating power functions that have a positive integer as an exponent, you certainly may choose to expand before integrating. However if you have fractional or negative exponents, it will be impossible to expand so you will need to learn to integrate using the general power rule. And when you use that rule the du factor must be in the function to be integrated before you can integrate but it will not appear in the integral (the function after you integrate). In order to understand this it might be helpful if you start with the integral and differentiate it to see what I mean. I hope this helps.

  • @AlethaWeyulu
    @AlethaWeyulu Місяць тому

    Good day Ma'am I don't really understand 11:16 when you integrated and left out (2x-3)

    • @mathmadeeasywithlaurel9353
      @mathmadeeasywithlaurel9353 Місяць тому

      If you start with the answer F(x) and find the derivative of that function, the (2x-3) factor will appear in the derivative. Notice however that it wasn't in F(x). It appears when you differentiate because of the chain rule. Therefore when you do the reverse operation and find the antiderivative of f(x), the (2x-3) factor must be there because it is the du factor, but it will not appear in the integral. I hope this makes sense.

  • @amandafranklin1354
    @amandafranklin1354 Місяць тому

    Awesome explanation! I'm starting my 2nd yr Millwright block on Monday and wanted a quick overview before starting shop classes. Thanks heaps!

    • @laurel500
      @laurel500 Місяць тому

      You’re welcome!

  • @cristalglass-painchaud7464
    @cristalglass-painchaud7464 2 місяці тому

    Thanks so much for this. Awesome stuff

  • @TntdigitalmediaCa
    @TntdigitalmediaCa 3 місяці тому

    Great video!

  • @PBloss
    @PBloss 3 місяці тому

    Legend

  • @thetreesmith
    @thetreesmith 3 місяці тому

    ma'am, please make videos for as long as possible. i am in 9th grade homeschool and i want to be an inventor/tradesman/handyman and i am currently watching your trades videos. your videos are a lot of help, using real world scenarios for the trades really helps me retain the info I'm learning into my brain. I hope THE CHRIST blesses you and your family, i wish you well.

    • @mathmadeeasywithlaurel9353
      @mathmadeeasywithlaurel9353 3 місяці тому

      I am very happy to hear that found my videos and are learning about how math is applied to so many trades. Thank you for your kind words. Good luck in your studies and your future career!

  • @droneeyes5989
    @droneeyes5989 3 місяці тому

    Thanks pls does the diameter means the diameter of the coupling?

  • @amilcarmayen5198
    @amilcarmayen5198 6 місяців тому

    I am a machinist apprentice and this video saved my life. Thanks for this great video!

    • @laurel500
      @laurel500 6 місяців тому

      I am glad that you found it helpful. Thanks for the feedback.

  • @bulenttas2684
    @bulenttas2684 7 місяців тому

    Hi Laurel, Thank you for the lecturing. I confused a lot with f(y) function. I checked with exremly detail and understand it. Both function has an inverse so you can exchange x and y in a function. f inverse (x) = y and compose with f function both side and got the result. It was very confusing for me. You assume us have all the background may be. I love functions but created a big confussion. Finaly I am convinced myself how to get it.

  • @suvendusharma5638
    @suvendusharma5638 8 місяців тому

    Extremely nice explanation, thank you miss

  • @AnjumSaeed-v5r
    @AnjumSaeed-v5r 10 місяців тому

    very nice

  • @petermay9214
    @petermay9214 Рік тому

    Hello top lady , What a brilliant video!!!. I am trying to learn about this as I have Exactly this problem to resolve with a job I am doing In my work shop . It’s an old winch handle with a tapper in as I have to make a new shaft to fit it . Thanks to your so clear video I am now able to work out the tapper required. I will subscribe to all your videos as I love the way you teach . How I wish you were in England!!. Have a Really Happy Christmas and thank you Pete

    • @laurel500
      @laurel500 Рік тому

      Thank you for you kind words. I am glad you found the video helpful.

  • @cariboux2
    @cariboux2 Рік тому

    Thanks. Very helpful.

  • @gracestaples2723
    @gracestaples2723 Рік тому

    Thanks, that helped

  • @gracestaples2723
    @gracestaples2723 Рік тому

    You make it look so easy!

  • @gracestaples2723
    @gracestaples2723 Рік тому

    Very helpful

  • @dpmike32819
    @dpmike32819 Рік тому

    Thank you

  • @dpmike32819
    @dpmike32819 Рік тому

    Nice explanation

  • @yvettrisehos1458
    @yvettrisehos1458 Рік тому

    Cant ready her the instructor on her videos.

  • @joseavila8752
    @joseavila8752 Рік тому

    I stands for Intensity

  • @Jerry-jk3mp
    @Jerry-jk3mp Рік тому

    This vid really helped me, thank you

  • @joelnamabwaza3896
    @joelnamabwaza3896 Рік тому

    Great work mamie

  • @joelnamabwaza3896
    @joelnamabwaza3896 Рік тому

    Thank you madam

  • @EnzoBenzo-kl
    @EnzoBenzo-kl Рік тому

    Thank you!! I’ll be back

  • @65case
    @65case Рік тому

    Great video, I've watched a bunch of your video, I especially like the machinist ones. I was wondering if there's a formula for projectile drop in relation to velocity.

    • @mathmadeeasywithlaurel9353
      @mathmadeeasywithlaurel9353 Рік тому

      Thank you for your kind feedback. I am not totally sure what formula you are asking for. If you want the formula for velocity of an object with constant acceleration, the formula is v = at + v0 where v is velocity at time t, a is the acceleration, and v0 is the initial velocity. If the object is being dropped or thrown straight up, the acceleration on that object is acceleration due to gravity, which is -9.81 m/s^2. So for an object that is dropped (not thrown or launched) the formula for velocity is v = -9.81t because a = -9.81 and v0=0. I hope this helps.

  • @richardb7726
    @richardb7726 Рік тому

    Thanks for this, explained clearly. Helped very much

    • @laurel500
      @laurel500 Рік тому

      Glad to hear it was helpful.

    • @richardb7726
      @richardb7726 Рік тому

      @@laurel500 thank you. It all came together with the decision tree. Great videos, followed you for a while. Nice to have things explained in language and a style ‘non mathematicians’ can easily understand

    • @mathmadeeasywithlaurel9353
      @mathmadeeasywithlaurel9353 Рік тому

      @@richardb7726 That is awesome to hear. I try to make math understandable and accessible to everyone.

  • @felicitymabuza1280
    @felicitymabuza1280 Рік тому

    ✨finally found the best explanation thank you ❤️

  • @eliascastillo1641
    @eliascastillo1641 Рік тому

    Is there a formula to figure out bolt diameter with just chord length?

    • @mathmadeeasywithlaurel9353
      @mathmadeeasywithlaurel9353 Рік тому

      You can still use the formula given in the example. But when you know the chord length and not the diameter, you will know the "x" in the formula (1/2 of the chord length), which is the numerator, and you will be finding the radius of the circle, which Is the denominator in the formula. If this doesn't make sense let me know and I can give you an actual formula for the radius or diameter.

    • @eliascastillo1641
      @eliascastillo1641 Рік тому

      Yes this makes sense. Thank you so much this is gonna help me out tremendously.😊

  • @badgaming7128
    @badgaming7128 Рік тому

    Why is v2 1? In the last equation

  • @artlitmusic
    @artlitmusic Рік тому

    I'm 53, and was never very good at math. Currently in college (!) and math is one of the courses I need to pass in order to graduate. I don't know how I found your channel right when I needed it, but to say I'm thankful is an understatement. The way you teach is so clear and understandable. Thank you so much for helping people like me overcome the fear of learning math!!🤗

  • @rohitpandit8724
    @rohitpandit8724 2 роки тому

    really amazing explanation🙂

  • @snigwithasword1284
    @snigwithasword1284 2 роки тому

    Short and sweet, thanks!

  • @Wurdfurd
    @Wurdfurd 2 роки тому

    Great explanation! Definitely easier to understand than my Panglobal text. Thanks!

  • @haylakesbrewery8550
    @haylakesbrewery8550 2 роки тому

    Thank you so much for being so smart and sharing your knowledge you are awesome wonderful person. You have helped me so much thank you

    • @laurel500
      @laurel500 2 роки тому

      You are welcome. I am glad my videos were helpful.

  • @euniceilboudo5679
    @euniceilboudo5679 2 роки тому

    thank you for this video. you're doing a great job keep going!

    • @laurel500
      @laurel500 2 роки тому

      You’re welcome. Thank you for your kind words.

  • @alihaque01
    @alihaque01 2 роки тому

    Thank you so much for the service.

  • @savedbygrace7145
    @savedbygrace7145 2 роки тому

    That’s awesomely explained. Thank you professor

  • @billchiasson2019
    @billchiasson2019 2 роки тому

    Well done! I have a better understanding of the use of Venn diagrams, thanks!

  • @jovelletulfo3602
    @jovelletulfo3602 2 роки тому

    Is it possible to convert face and rim indicator readings to reverse alignment indicator readings or vice versa? If possible how?

    • @mathmadeeasywithlaurel9353
      @mathmadeeasywithlaurel9353 2 роки тому

      Can you clarify what you mean by reverse alignment indicator readings? Are the indicators mounted on the moveable shaft instead of the fixed? Or are the readings zeroed opposite to what I did?

  • @billchiasson2019
    @billchiasson2019 2 роки тому

    Well done thank you!

  • @haylakesbrewery8550
    @haylakesbrewery8550 2 роки тому

    Thank you so much for all your videos you have helped me so much you are wonderful teacher

    • @laurel500
      @laurel500 2 роки тому

      You are welcome! Thank you for your kind words.

  • @tatu919
    @tatu919 2 роки тому

    D= 2r sin(180÷5) D= distance . R= radius . D = 2r sin(180÷5) This formula can be solved for any holes pattern on a circle?? Calculator : 2×4.00 ×(180÷5)sin= 4.7022.

    • @mathmadeeasywithlaurel9353
      @mathmadeeasywithlaurel9353 2 роки тому

      Yes it does work providing you replace the 5 with the number of holes on the bolt circle. In other words, D = 2r sin(180/#) where # represents the number of holes.

  • @billchiasson2019
    @billchiasson2019 2 роки тому

    Just used this formula for a three hole pattern! Turned out perfect thanks!