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Lewis structure example, Everyday Molecules Edition 1: H2O, O2, CO2, N2
𝗟𝗘𝗔𝗥𝗡𝗜𝗡𝗚 𝗢𝗕𝗝𝗘𝗖𝗧𝗜𝗩𝗘𝗦
♥ Draw Lewis structures of molecules.
♥ Assign formal charges to atoms in molecules.
💡 𝗥𝗘𝗠𝗘𝗠𝗕𝗘𝗥
♥ The number of valence electrons corresponds to the last digit in the group number on a periodic table.
♥ Each atom, especially C, N, O, and F, in a molecule has an 𝗼𝗰𝘁𝗲𝘁, a total of 8 electrons, counting all the electrons attached to the atom. Do not split bonds. Splitting bonds is for calculating formal charge.
♥ Hydrogen takes a duet, a total of 2 electrons, rather than an octet. This means that H cannot be a central atom and can only have a single-bond, neither double- nor triple-bond.
♥ Minimize formal charge, i.e. get the formal charge as close to zero as possible.
𝗡𝗢𝗧𝗘
The 𝗯𝗼𝗻𝗱 𝗼𝗿𝗱𝗲𝗿 (mentioned in 6:45) refers to the type of bond between atoms, i.e. single-, double-, or triple-bond.
The organization of the bonds and lone pairs here do not look quite right. That is okay! Lewis structures are flat, two-dimensional representations of molecules. The valence shell electron-pair repulsion (VSEPR) model, not in this video, improves Lewis structures by representing molecules as three-dimensional objects.
Original content © 2024 Jung-Lynn Jonathan Yang
Переглядів: 64

Відео

Unimolecular nucleophilic substitution (SN1), overview
Переглядів 252 місяці тому
TRANSCRIPT There are two elementary steps in the SN1 reaction mechanism. The first step is the departure of the leaving group (LG). The leaving group takes the two bonding electrons as a lone pair and detaches from the carbon atom. The loss of electron from carbon confers a positive charge in the carbocation intermediate. In the second step, a lone pair from a nucleophile (Nu) forms a bond to t...
Differentiate (sin θ)ᶜᵒˢ ᶿ and (𝑥 + sec 𝑥)⁴ᐟˣ
Переглядів 1734 місяці тому
𝗤𝗨𝗘𝗦𝗧𝗜𝗢𝗡 Differentiate 0:03 𝑟(θ) = (sin θ)ᶜᵒˢ ᶿ 2:40 𝑦(𝑥) = (𝑥 sec 𝑥)⁴ᐟˣ 𝗪𝗢𝗥𝗞𝗙𝗟𝗢𝗪 When a variable appears in both the base as well as the exponent, use 𝗹𝗼𝗴𝗮𝗿𝗶𝘁𝗵𝗺𝗶𝗰 𝗱𝗶𝗳𝗳𝗲𝗿𝗲𝗻𝘁𝗶𝗮𝘁𝗶𝗼𝗻. Take the natural log of the entire equation to bring down the exponent. Differentiate by the Product Rule or Quotient Rule. A summary of the steps is as follows: ① Take the natural logarithm (ln) of both sides of the...
Differentiate (𝑥² + 1)(7𝑥 − 6)⁵(𝑥 − 3) / [ (cos(𝑥) + 2) eᵉᕽ ]
Переглядів 934 місяці тому
𝗤𝗨𝗘𝗦𝗧𝗜𝗢𝗡 Differentiate (𝑥² 1)(7𝑥 − 6)⁵(𝑥 − 3) / [ (cos(𝑥) 2) eᵉᕽ ] 𝗪𝗢𝗥𝗞𝗙𝗟𝗢𝗪 Although we can differentiate a huge product or quotient by the Product Rule or Quotient Rule, doing so is tough because there are so many factors to keep organized. Instead, we use the technique of 𝗹𝗼𝗴𝗮𝗿𝗶𝘁𝗵𝗺𝗶𝗰 𝗱𝗶𝗳𝗳𝗲𝗿𝗲𝗻𝘁𝗶𝗮𝘁𝗶𝗼𝗻: 0:10 ① Take the natural logarithm (ln) of both sides of the equation. 0:13 ② Separate factors...
Chain Rule examples
Переглядів 1504 місяці тому
𝗤𝗨𝗘𝗦𝗧𝗜𝗢𝗡 Differentiate these functions. (0:01) 𝑦(𝑥) = eˣ² (0:23) 𝑔(𝜃) = sec(sin(tan √𝜃³)) (1:36) 𝑓(𝘵) = 5/(cos(eᵗ²⁻⁷ᵗ⁺¹))² It is not necessary to simplify the derivative. 𝗪𝗢𝗥𝗞𝗙𝗟𝗢𝗪 A composite function is a function with one or more functions nested inside. The Chain Rule tells us to differentiate composite functions, starting from the outermost function and working inward. Keep any arguments of...
Differentiate these logarithmic functions
Переглядів 705 місяців тому
𝗤𝗨𝗘𝗦𝗧𝗜𝗢𝗡 Differentiate these functions. (0:03) 𝑟(𝜃) = log₁₀ 𝜃 (0:25) 𝑔(𝑥) = log₂ ( 𝑥 (𝑥 1) (𝑥 2)³ ) (2:22) 𝑦(𝑢) = log₍ᵤ₊₁₎ 𝑢 It is not necessary to simplify the derivative. 𝗪𝗢𝗥𝗞𝗙𝗟𝗢𝗪 Memorize the derivative rules for a general logarithm (base-𝑎) and the natural logarithm (ln) in order to differentiate logarithmic functions. Also, memorize the 𝗽𝗿𝗼𝗽𝗲𝗿𝘁𝗶𝗲𝘀 𝗼𝗳 𝗹𝗼𝗴𝗮𝗿𝗶𝘁𝗵𝗺𝘀 and the 𝗰𝗵𝗮𝗻𝗴𝗲 𝗼𝗳 𝗯𝗮𝘀𝗲 formu...
Find 𝑐 › 0 for crit pt in 𝑟(𝑡) = (𝗅𝗇(𝑐𝑡² − 2𝑐𝑡 + 2𝑐))²
Переглядів 826 місяців тому
𝗤𝗨𝗘𝗦𝗧𝗜𝗢𝗡 Find the value of the constant 𝑐 › 0 such that there are critical points at 𝑡 = 0, 1, 2 in the function 𝑟(𝑡) = (𝗅𝗇(𝑐𝑡² − 2𝑐𝑡 2𝑐))². 𝗪𝗢𝗥𝗞𝗙𝗟𝗢𝗪 At a 𝗰𝗿𝗶𝘁𝗶𝗰𝗮𝗹 𝗽𝗼𝗶𝗻𝘁, the first derivative is equal to zero. Differentiate 𝑟(𝑡) by Chain Rule; set 𝑟′(𝑡) equal to 0 at 𝑡 = 0, 1, 2; and solve for 𝑐. Often, the question tells/implies us to solve for 𝑥-values, here we have 𝑡-values, that makes the f...
Find 𝑎 for crit pt in 𝑔(𝑥) = 𝑥𝚎ᵃˣ at 𝑥 = 1/3
Переглядів 596 місяців тому
𝗤𝗨𝗘𝗦𝗧𝗜𝗢𝗡 Find the value of the real constant 𝑎 such that the function 𝑔(𝑥) = 𝑥𝚎ᵃˣ has a critical point at 𝑥 = 1/3. 𝗪𝗢𝗥𝗞𝗙𝗟𝗢𝗪 At a 𝗰𝗿𝗶𝘁𝗶𝗰𝗮𝗹 𝗽𝗼𝗶𝗻𝘁, the first derivative is equal to zero. Differentiate 𝑔(𝑥) by Product Rule; substitute 𝑥 = 1/3 into 𝑔′(𝑥); set 𝑔′(1/3) to zero; and solve for 𝑎. Often, the question tells/implies us to solve for 𝑥-values that makes the first derivative equal to zero in ...
Global/relative min/max of 𝑓(𝑥) = 𝑥¹ᐟ³ + 𝑥²/6 in −8 ≤ 𝑥 ≤ 1
Переглядів 676 місяців тому
𝗤𝗨𝗘𝗦𝗧𝗜𝗢𝗡 Identify the absolute (global) extrema and relative (local) extrema of the function, 𝑓(𝑥) = 𝑥¹ᐟ³ 𝑥²/6 within the interval −8 ≤ 𝑥 ≤ 1. Are you wondering what is happening at 𝑓(0)? It is a continuous point on the graph that has a vertical tangent line. The vertical tangent line makes the derivative undefined, i.e. a singular point, but, in this case, is not a minimum or maximum. Therefor...
Singular Point (Work-in-Progress)
Переглядів 219 місяців тому
January 1, 2024 "Singular Point" pictorial summary by Jung-Lynn Jonathan Yang. Work-in-progress.
Second Derivative Test (Work-in-Progress)
Переглядів 799 місяців тому
January 1, 2024 "Second Derivative Test" pictorial summary by Jung-Lynn Jonathan Yang. Work-in-progress.
Second Derivative Test Fails (Work-in-Progress)
Переглядів 659 місяців тому
January 1, 2024 "Second Derivative Test Fails" pictorial summary by Jung-Lynn Jonathan Yang. Work-in-progress.
Inflection Point (Work-in-Progress)
Переглядів 169 місяців тому
January 1, 2024 "Inflection Point" pictorial summary by Jung-Lynn Jonathan Yang. Work-in-progress.
First Derivative Test (Work-in-Progress)
Переглядів 219 місяців тому
First Derivative Test (Work-in-Progress)
Critical Point (Work-in-Progress)
Переглядів 109 місяців тому
Critical Point (Work-in-Progress)
呷蝦咪 T&T Supermarket (大統華) Mooncake Review
Переглядів 283Рік тому
呷蝦咪 T&T Supermarket (大統華) Mooncake Review
Factoring [Example] [Algebraic limits]
Переглядів 2,7 тис.Рік тому
Factoring [Example] [Algebraic limits]
Combining techniques [Example] [Algebraic limits]
Переглядів 724Рік тому
Combining techniques [Example] [Algebraic limits]
Multiplying by the conjugate [Example] [Algebraic limits]
Переглядів 13 тис.Рік тому
Multiplying by the conjugate [Example] [Algebraic limits]
Combining fractions [Example] [Algebraic limits]
Переглядів 382Рік тому
Combining fractions [Example] [Algebraic limits]
加拿大國慶日活動 Canada Day Event
Переглядів 25Рік тому
加拿大國慶日活動 Canada Day Event
春熱花狂開 加拿大 Edmonton, Alberta 風景
Переглядів 53Рік тому
春熱花狂開 加拿大 Edmonton, Alberta 風景
Research Problem: Complex Numbers
Переглядів 53Рік тому
Research Problem: Complex Numbers

КОМЕНТАРІ

  • @emmanuelbossfx
    @emmanuelbossfx 3 місяці тому

    Wow i love this video please i need more even on physics and chemistry

  • @jan-willemreens9010
    @jan-willemreens9010 4 місяці тому

    Clear presentation on how to execute the Chain Rule correctly on given compositie functions ... best regards, gui

  • @NathanielSundayHaruna
    @NathanielSundayHaruna 4 місяці тому

    If Y=1/2√x

    • @DrYheartLab
      @DrYheartLab 4 місяці тому

      Sorry, I did not understand your question! Could you tell me more?

  • @NathanielSundayHaruna
    @NathanielSundayHaruna 4 місяці тому

    Good evening ask questions

  • @ИванВоронин-и2м
    @ИванВоронин-и2м 4 місяці тому

    ? Bernulli Lopital is faster!

    • @DrYheartLab
      @DrYheartLab 4 місяці тому

      In the first few lessons of Calculus I, we are told to solve limits algebraically and do not use l’Hôpital's Rule. Although, if the teacher does not specify which method to use, or not to use, then yes, use l’Hôpital's Rule because it is faster!

  • @victorpaesplinio2865
    @victorpaesplinio2865 5 місяців тому

    "Why don't use L'Hopital?", one may ask. Well, it depends on the purpose. Since you need to learn limits in order to learn derivatives in a standard calculus 1 course, you will face many 0/0 limits where you will be required to solve algebraically before being introduced to the concept of derivatives. Every year at my college I face myself trying to help new students to manipulate a limit where L'Hopital would solve in two lines, just because they are in the beginning of the course haha

    • @DrYheartLab
      @DrYheartLab 4 місяці тому

      This is exactly what I have to do for teaching calculus! It's neat that we use limits to evaluate derivatives and then use derivatives, in the form of l'Hôpital's Rule, to solve limits.

  • @MuhamadQadir-p2d
    @MuhamadQadir-p2d 5 місяців тому

    6^-1

    • @DrYheartLab
      @DrYheartLab 5 місяців тому

      That is the correct answer!

  • @glorymanheretosleep
    @glorymanheretosleep 6 місяців тому

    Do more of these examples with trig functions too.

  • @旅行者-r3z
    @旅行者-r3z 6 місяців тому

    meanwhile i'm just using l'hopital rule

    • @DrYheartLab
      @DrYheartLab 6 місяців тому

      Yes, use l’Hôpital's Rule if the question does not tell you not to use it! In the calculus courses I took and have to teach, we could only use algebraic techniques and were not allowed to use l’Hôpital's Rule in the unit about limits.

    • @Will-nf9gf
      @Will-nf9gf Місяць тому

      I think actually the conjugate is way faster because of the x - 7 cancellation but I like how l'hopital is more general so honestly me too

    • @DrYheartLab
      @DrYheartLab Місяць тому

      Neat! Multiplying by the conjugate may be faster because the root differentiates by the Chain Rule, which brings in more factors to deal with and makes l’Hôpital's Rule a bit complicated. Alternatively, we can try a mix of both methods! Start with multiplying by the conjugate, then as long as the indeterminate form is appropriate (±∞/±∞ or 0/0), use l’Hôpital's Rule. Whatever method you prefer, use the method that works fastest and most accurately for you and is also allowed by the exam instructions.

  • @omnamonarayan3523
    @omnamonarayan3523 6 місяців тому

    🎉hey 👋🏻☺️👋🏻😊😌🤗@

  • @surendrakverma555
    @surendrakverma555 6 місяців тому

    Good 👍

  • @surendrakverma555
    @surendrakverma555 6 місяців тому

    Good

  • @Ivy1286
    @Ivy1286 6 місяців тому

    Is this AP calculus level or easier?

    • @DrYheartLab
      @DrYheartLab 6 місяців тому

      Good question, I actually don't know! I think factoring to solve limits is typical of Advanced Placement (AP) calculus and definitely university/college calculus. According to page 40 of “AP Calculus Course and Exam Description” (apcentral.collegeboard.org/media/pdf/ap-calculus-ab-and-bc-course-and-exam-description.pdf), “[f]actoring and dividing common factors of rational functions” looks to me like this video is typical of what is on the AP curriculum.

  • @chethkeathmaths
    @chethkeathmaths 7 місяців тому

  • @chethkeathmaths
    @chethkeathmaths 7 місяців тому

    The best video

  • @pauselab5569
    @pauselab5569 7 місяців тому

    that is way to specific. no way anyone would prefer this over l'hopital which is both easier to use and more general.

    • @DrYheartLab
      @DrYheartLab 6 місяців тому

      There is a lot of annoying algebra! For some reason, I had to learn this as a student and is also in the curriculum I teach in multiple universities. L'Hôpital's Rule is easier and faster.

  • @elmeralvarado1236
    @elmeralvarado1236 7 місяців тому

    Why didn't you conjugate (x-7) with (x+7)?

    • @DrYheartLab
      @DrYheartLab 7 місяців тому

      Good question! When we multiply (x − 7) and (x + 7), we have the difference of squares x² − 49, which does not cancel much. Instead, if we target the awkward square root, then we can eliminate the square root as a difference of squares.

  • @xadxtya
    @xadxtya 7 місяців тому

    Wow I really liked that little flashcard for Conjugate

  • @alban6423
    @alban6423 7 місяців тому

    It is the literal definition of the derivative of f(x) = sqrt(x+2) at x = 7

    • @DrYheartLab
      @DrYheartLab 7 місяців тому

      Good call! It is! I think this is why calculus courses begin with limits because then we can extend limits to the limit definition of the derivative.

  • @bouazabachir4286
    @bouazabachir4286 7 місяців тому

    Thanks a lot professor I follow you from Algeria.

    • @DrYheartLab
      @DrYheartLab 7 місяців тому

      I am not officially a professor because I am unemployed. I do things that professors do, like teaching, supervising undergraduate/graduate research projects, and evaluating funding applications. Thank you for watching!

  • @pkfrozen7867
    @pkfrozen7867 7 місяців тому

    great video!

  • @zzzz-yw4zk
    @zzzz-yw4zk 7 місяців тому

    Couldnt u just do l'hopital?

    • @DrYheartLab
      @DrYheartLab 7 місяців тому

      Absolutely, l’Hôpital’s Rule is another way to solve this limit question! In fact, l’Hôpital’s Rule is applicable for limits of the form “0/0” (what we have here) and “±∞/±∞”. In the beginning lessons and midterm(s) in Calculus I, instructors tend to tell students to solve limits using algebraic methods rather than l’Hôpital’s Rule. However, if the question does not specify which method to use, l’Hôpital’s Rule can be an easier and faster method than algebra.

  • @shivx3295
    @shivx3295 7 місяців тому

    Did it orally by just rationalising

    • @DrYheartLab
      @DrYheartLab 7 місяців тому

      That is great to be able to solve this question mentally (by inspection)! Solving mentally is especially suitable on questions where it is not necessary to show calculation work, like multiple choice questions.

  • @MegumiKato418
    @MegumiKato418 7 місяців тому

    Thank you

  • @philippedelaveau528
    @philippedelaveau528 8 місяців тому

    But since the limit for 7 of numerator and denominator are both equal to zero, L”Hospital’s rule works very well.

    • @DrYheartLab
      @DrYheartLab 8 місяців тому

      You are right! L'Hôpital's Rule is perfect for indeterminate forms “0/0” (the situation here) and “±∞/±∞”. In the calculus courses I took and taught, we had to solve limits algebraically. On my midterm exam, the instruction specifically told us to not use L'Hôpital's Rule. It was not until later on in the course, about applications of derivatives, that we had the option of L'Hôpital's Rule.

    • @philippedelaveau528
      @philippedelaveau528 8 місяців тому

      Thank you. Sorry for the advance@@DrYheartLab

    • @DrYheartLab
      @DrYheartLab 8 місяців тому

      I am glad you brought up l’Hôpital’s Rule! If the question does not specify which technique to use, or not to use, l’Hôpital’s Rule is often a faster method than algebra.

  • @jan-willemreens9010
    @jan-willemreens9010 8 місяців тому

    ... Good day, Observing the expression of the limit ( SQRT(X + 2) - 3 ) / ( X - 7 ), I see the occasion to rewrite the denominator ( X - 7 ) as follows ... X - 7 = ( X + 2 ) - 9 , and treat ( X + 2 ) - 9 as a " Difference of 2 Squares " ... ( X + 2 ) - 9 = [ SQRT(X + 2) - 3 ] * [ SQRT(X + 2) + 3 ] ... now recognizing a common factor between numerator and denominator expression of [ SQRT(X + 2) - 3 ] ... which simplifies the original limit as .... LIM(X->7)[ 1 / ( SQRT(X + 2) + 3 ) ] = 1 / ( SQRT(9) + 3 ) = 1 / ( 3 + 3 ) = 1/6 ... solving this limit exercise by applying " Factoring the Denominator " ... thanking you DrY(black heart)Lab for your instructive presentation .... best regards, Jan-W

    • @DrYheartLab
      @DrYheartLab 8 місяців тому

      Amazing, @Jan-W, I could not have thought of your solution! Absolutely, write the “x − 7” as “(x + 2) − 9” and then factor as a difference of squares to cancel with the numerator. I am glad you brought up this alternative solution! 💡

    • @ximer3316
      @ximer3316 8 місяців тому

      Thats splendid. I would not be able to come up with that in 1000 years!!

    • @DrYheartLab
      @DrYheartLab 8 місяців тому

      Not to worry! There may be multiple ways to solve limits. Just use what works well and accurately for you.

  • @KY-bu5nr
    @KY-bu5nr Рік тому

    金風送爽 丹桂飄香 傳說吟唱 南北百味 揉方糰圓 歡喜香甜

  • @KY-bu5nr
    @KY-bu5nr Рік тому

    愛城冬夏季氣溫零上零下30 多度, 挺有趣的, 真想試試潑水成冰的把戲

  • @PortalisLeMur
    @PortalisLeMur Рік тому

    Needs museum gloves to open such a luxurious combo 😂😂😂😂😂 Thanks so much for such a detailed and informative review of mooncakes. Always so hard to know what to buy so you really help us save money and pick the variety that works for what we want to eat. And thanks for the warning about no meat!! What a tricky piece of labelling indeed!

  • @KY-bu5nr
    @KY-bu5nr Рік тому

    Every year hundreds luckily bought and thousands fortunately ate but only very few could tell so well.

  • @KY-bu5nr
    @KY-bu5nr Рік тому

    Outstanding pictures and interesting details about the art in these festival celebration. Wonderful job. 🎉🎉

  • @BekzatJumabekov-t2t
    @BekzatJumabekov-t2t Рік тому

    Good job 👌👍

  • @bharateeyudue
    @bharateeyudue Рік тому

    😅😅 very harsh subject to understand

    • @DrYheartLab
      @DrYheartLab Рік тому

      It can be quite an abstract topic! The usual example is the sodium-potassium pump. I included some uncommonly used examples to show that there are other ways to use ATP and also sources of energy other than ATP, like the ATP-binding cassette transporter, light-gated ion channel, and electron transport chain. Let me know if there is another method of presenting the subject that is more understandable!

  • @PortalisLeMur
    @PortalisLeMur Рік тому

    I loved this!! So witty AND informative! 🎉😂

  • @phobos1963
    @phobos1963 Рік тому

    Isn't that the definition of a Bronsted acid ?

    • @DrYheartLab
      @DrYheartLab Рік тому

      Glad you asked! Arrhenius acids are a subset of Brønsted-Lowry acids, which are a subset of Lewis acids, the most general category of acids in some university programs. All the acids in this video are Arrhenius acids and thus are also Brønsted-Lowry acids. The Arrhenius definition of acid is quite narrow about 1) hydrogen ion (H⁺, proton) and 2) in water. The idea of a free H⁺ floating in solution is not the best description because a free H⁺ is too unstable. The Brønsted-Lowry definition is broader; acids are H⁺ donors in water and also in other environments, such as the gas phase. Also, the Arrhenius definition does not say where the H⁺ goes. Brønsted-Lowry-type of reactions necessarily involve an acid-base pair of reactants. The H⁺ does not float around like in the video for the Arrhenius definition. According to Brønsted-Lowry, the HCl in water has to donate H⁺ to something. If there is no other H⁺ acceptor other than water, then water is the reactant that accepts H⁺ from HCl. The free H⁺ is too unstable, but H₃O⁺, a water molecule that accepted H⁺, has been observed.

  • @KY-bu5nr
    @KY-bu5nr Рік тому

    Thank you very much Dr. Y. I can see from your eyes and understand the theory in lab action.

  • @KY-bu5nr
    @KY-bu5nr Рік тому

    Thank you very much Dr. Y. This very new lab action video helps me to see the true meaning of the importance of the theory.

  • @KY-bu5nr
    @KY-bu5nr Рік тому

    Wonderful story about Edmonton

  • @KY-bu5nr
    @KY-bu5nr Рік тому

    Now I can understand. Thank you very much for your help Dr Y Lab

  • @KY-bu5nr
    @KY-bu5nr Рік тому

    A lot useful educational information and very interesting to watch over and over again