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Mathable - IITJEE
India
Приєднався 23 жов 2024
Gulshan Chauhan, IIT Guwahati
Ex-FIITJEE Maths Faculty for IITJEE
“To inspire people, don't show them your superpowers. Show them theirs". - Alexander Den Hejjer
Ex-FIITJEE Maths Faculty for IITJEE
“To inspire people, don't show them your superpowers. Show them theirs". - Alexander Den Hejjer
All Standard Parabolas || Tangent & Normal Equation in 1 line
#iitjee #parabola #education #jeemains #jeeadvanced #jee #teacher #teaching
Переглядів: 344
Відео
Easy solution of IITJEE 2021 (PYQ) - A square ABCD has all its vertices on the curve x^2y^2 = 1 #jee
Переглядів 613Місяць тому
Easy solution of IITJEE 2021 (PYQ) - A square ABCD has all its vertices on the curve x^2y^2 = 1 #jee
Binomial Theorem - 3 Methods to derive binomial Coefficients #education #binomial #iitjeemathematics
Переглядів 407Місяць тому
Telegram group : t.me/mathable_iitjee Teacher details: Gulshan Chauhan B.Tech , IIT Guwahati Ex FIITJEE Faculty. #iitjee #jeeadvanced #education #jeemains #teacher #teaching #iit #mathstricks #jeemains #teachers #teacher #teaching #jeeadvanced #jee #maths #education #iitjee #maths #binomial_theorem #algebra #tricks #tricks
IITJEE MAIN 2023 & 2022 asked similar question again #education #iit #jeeadvanced #jee #maths #math
Переглядів 357Місяць тому
IITJEE MAIN 2023 & 2022 asked similar question again The area of the bounded region enclosed by the curve y=3-|x-(1/2)|-|x 1| and the x-axis is (A) (9/4) (B) (45/16) (C) (27/8) (D) (63/16) find the area bounded by the curves y=|x−1| |x−2| and y=3 Full video : ua-cam.com/video/4IFtoTLlN0Q/v-deo.htmlsi=ghbqXq8CAZWirmMH Telegram group : t.me/mathable_iitjee Teacher details: Gulshan Chauhan B.Tech ...
5 Methods to master a Tricky Parabola Question - IITJEE Mathematics #education #iit
Переглядів 4652 місяці тому
Find the length of latus rectum and equation of the parabola whose focus is (0, 0) and the tangent at P(1,1) is 2x y =3 Teacher details: Gulshan Chauhan B.tech, IIT Guwahati Ex FIITJEE Faculty. Content verification : Dear Tushar Goel Sir #iitjee #jeemains #teachers #teacher #teaching #jeeadvanced #jee #maths #education #educational #exam #exams #iitjeemathematics
3 Methods to solve IITJEE Advanced 2017 PYQ - PNC (Permutations & Combinations) #education #maths
Переглядів 6042 місяці тому
Let S={1,2,3,……,9}. For k=1,2,……,5, let N k be the number of subsets of S, each containing five elements out of which exactly k are odd. Then N Teacher details: Gulshan Chauhan B.tech, IIT Guwahati Ex FIITJEE Faculty. Content verification : Dear Tushar Goel Sir #iitjee #jeeadvanced #education #jeemains #teacher #teaching #iit #mathstricks #jeemains #teachers #teacher #teaching #jeeadvanced #j...
Verbal solution of IITJEE (Adv) 2020 PYQ without using Pen/Paper - Functions
Переглядів 8892 місяці тому
Verbal solution of IITJEE (Adv) 2020 PYQ without using Pen/Paper - Functions
7 methods to Master a Parabola Question asked in IITJEE Maths Faculty demo
Переглядів 1,6 тис.2 місяці тому
7 methods to Master a Parabola Question asked in IITJEE Maths Faculty demo
Easy solution of a lengthy question- #IITJEE - Quadratic Rational Functions with Range R
Переглядів 5492 місяці тому
Easy solution of a lengthy question- #IITJEE - Quadratic Rational Functions with Range R
Easy solution of IITJEE (PYQ)- Trigonometry - umber of x∈[0,2π] for which |√(2〖sin〗^4 x+18〖cos〗^2 x)
Переглядів 1,2 тис.2 місяці тому
Easy solution of IITJEE (PYQ)- Trigonometry - umber of x∈[0,2π] for which |√(2〖sin〗^4 x 18〖cos〗^2 x)
Great work❤
Thanks Monika 😊
Badiya sir 🙌
Thanks Prachi 😊
Sir gali de kar padhai
thanks
@@aarush0403 always welcome 😊
Congratulations for the New channel! Keep growing.
Thank you 😊
Gulshan sir roxx🎉
Thanks Chandan 😊
🎉🎉
Thanks Prachi 😊
Great 👍
Thanks Pravesh 😊
Unmatchable techniques of teaching ✔️👌
Thank you 🙏😊
Good one❤
Thanks Shaurya 😊
Great!!
Thank you 😊
Maine kabhi nhi socha ese Aap to cream ho sir
Hahah... Thanks 😄
Very well explained sir…👌🏻👏
Thanks Prashant 😊
Mza aa gya guruji
Thank you 😊
Jadu solutions sir.⭐💥
Thanks Chandan 😊
Very useful and simple solution 🙇♂️
Thanks Britika 😊
Lucidly explained sir..👏
Thanks Sneha 😊
kafi sahi
Thanks Radhika 😊
great one, sir!
Thanks Subrat 😊
Omg....so beautiful ❤...never thought of that...
Thanks Shaurya 😊
Very useful and powerful technique sir, never thought of this, thank you gulshan sir
Thanks Aarush 😊❤️
Nicely explained😊
Thank you 😊
Very nice explanation sr
Thanks Aarush 😊
Great 👍
Thanks bhai
amazing content sir this shall help in high level jee adv problems plus first year college level questions too
Thanks Subrat ❤️😊
It was such a new thing to learn.. Well explained sir.. Thank you
Thank you Jc 😊
Thankyou sir
Always welcome 😊
2nd ka accha lga Hamne ye kabhi socha hi na...
Thanks
Wow, this is useful in physics too
Yes Aarush 😊
🎉
Very well explained sirjee 🎉
Thanks Prachi 😊
🫡
🎉👏👏
Scientist 🧬
Thanks Radhika 😊
Thanks sir for simplifying....it always used to confuse me
Always welcome Jatin 😊
❤
Great sir👏😲
Thanks Prashant 😊
Sir par agar option me 16 , 24 etc bhi hota toh fir ye method nhi laga sakte na , and sir fir uss case me koi aur method hai kya iss question ko solve karne ka
Sir please increase frequency of videos , and thankyou so much for these extra approachs you are really improving my mathematics marks!
Sure Medhansh 😊 you are always welcome 😊
Hmare sir ka jalwa h...koi nhi h takkar mein kyu pde ho chakkar mein😊🎉
Thanks Jatin ❤️😊
No East no West , Gulshan sir is the BEST.🤩🤩
Thanks Chandan 😊
Your explanations are engaging and easy to comprehend sir! 😇
Thank you 😊
Thankful to you ❤️
Thank you...I am glad 😊
Thanks sir i went by 1st method messed up after seeing solution i am amazed it can be solved easily like this thanks 🙏
You are always welcome Raghav 😊 I am glad it was useful for you 😊 keep up the good work 💯
Nice explanation of bucket graphs
Thanks Aarush 😊
u make things so simple!
Thank you Radhika 😊
Thank you for sharing such an amazing content sir..🫶🏻😇
Thanks Prashant 😊
The wizard of maths ❤ definitely uplifting the benchmarks for the teaching fraternity
Thanks Abhishek Sir🙏😊
Truly inspiring "to go beyond the limits" !!! Gulshan bhaiya the living legend🎉🎉
@@AbhishekDadhich-so7qs Thanks Abhishek 😊❤️
🎉🎉