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Simon Flynn
Приєднався 2 вер 2016
What I think good exam technique is in A level Chemistry and why
I’ve come to think that many good exam techniques/strategies are fundamentally about reducing the burden on our working memory. In a nutshell, I believe we can reduce the load on our working memory in A-level Chemistry by:
- Annotating the exam paper
- Writing our working out in full
- Doing the above automatically.
This (too) long video aims to explain and demonstrate what I mean
- Annotating the exam paper
- Writing our working out in full
- Doing the above automatically.
This (too) long video aims to explain and demonstrate what I mean
Переглядів: 321
Відео
Rate Equations Practical 7 Exam Question 2018 (AQA A level Chemistry)
Переглядів 5 тис.2 роки тому
A long exam question that features required practical 7.
Electrode Potentials Question 2018 (AQA A level Chemistry).
Переглядів 2,3 тис.2 роки тому
This talks through Q6 in 2018's Paper 1. I've tried to use this question to provide a slightly deeper understanding of electrochemical cells.
Reactions of Aqua Ions and Transition Metal Exam Question (AQA A level Chemistry)
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This video talks through Q4 of 2019's Paper 1 including a six mark question on isomerism in Transition Metals.
Buffers Calculations - Various Examples (AQA A Level Chemistry)
Переглядів 10 тис.2 роки тому
This video discusses briefly some key ideas regarding buffers before talking through a series of different example calculations.
Kw, Titration Curve, Buffers Exam Question (AQA A Level Chemistry)
Переглядів 2,3 тис.2 роки тому
Kw, Titration Curve, Buffers Exam Question (AQA A Level Chemistry)
Titration Calculation Exam Question (AQA A Level Chemistry)
Переглядів 15 тис.2 роки тому
Titration Calculation Exam Question (AQA A Level Chemistry)
Alkanes Part 1 - Fractional Distillation, Cracking and Combustion (AQA A level Chemistry)
Переглядів 5072 роки тому
Alkanes Part 2 - Chlorination of Alkanes (ua-cam.com/video/GW71K_MTtgg/v-deo.html) 3.3.2.1 Fractional distillation of crude oil Alkanes are saturated hydrocarbons. Petroleum is a mixture consisting mainly of alkane hydrocarbons that can be separated by fractional distillation. 3.3.2.2 Modification of alkanes by cracking Cracking involves breaking C-C bonds in alkanes. Thermal cracking takes pla...
Bonding Exam Question (AQA A Level Chemistry)
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Bonding Exam Question (AQA A Level Chemistry)
Enthalpy changes question (AQA A Level Chemistry)
Переглядів 13 тис.2 роки тому
Enthalpy changes question (AQA A Level Chemistry)
TOF Question (AQA A Level Chemistry)
Переглядів 14 тис.2 роки тому
TOF Question (AQA A Level Chemistry)
Rate Equations (AQA A level Chemistry)
Переглядів 1,6 тис.3 роки тому
3.1.9.1 Rate equations The rate of a chemical reaction is related to the concentration of reactants by a rate equation of the form: Rate = k[A]m [B]n where m and n are the orders of reaction with respect to reactants A and B and k is the rate constant. The orders m and n are restricted to the values 0, 1, and 2. The rate constant k varies with temperature as shown by the equation: k = Ae-Ea/RT ...
Sweet Chemistry
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A farewell to the Year 13s studying A level Chemistry this year (2021) From Mr Flynn, with huge apologies to the great Neil Diamond
Equilibrium constant Kc for homogeneous systems (AQA A level Chemistry)
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The equilibrium constant Kc is deduced from the equation for a reversible reaction. The concentration, in mol dm-3, of a species X involved in the expression for Kc is represented by [X] The value of the equilibrium constant is not affected either by changes in concentration or addition of a catalyst. Students should be able to: •• construct an expression for Kc for a homogeneous system in equi...
Chemical equilibria and Le Chatelier's principle (AQA A level Chemistry)
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Chemical equilibria and Le Chatelier's principle (AQA A level Chemistry)
Oxidation, reduction and redox equations (AQA A level Chemistry)
Переглядів 8243 роки тому
Oxidation, reduction and redox equations (AQA A level Chemistry)
Bond Enthalpies (AQA A level Chemistry)
Переглядів 2,7 тис.3 роки тому
Bond Enthalpies (AQA A level Chemistry)
Applications of Hess’s Law (AQA A level Chemistry)
Переглядів 1,1 тис.3 роки тому
Applications of Hess’s Law (AQA A level Chemistry)
Calorimetry (AQA A level Chemistry)
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Calorimetry (AQA A level Chemistry)
Enthalpy Change (AQA A level Chemistry)
Переглядів 9703 роки тому
Enthalpy Change (AQA A level Chemistry)
Chromatography (AQA A level Chemistry)
Переглядів 5 тис.3 роки тому
Chromatography (AQA A level Chemistry)
Amino Acids, proteins and DNA (AQA A level Chemistry)
Переглядів 7 тис.3 роки тому
Amino Acids, proteins and DNA (AQA A level Chemistry)
Y13 H NMR - Nuclear Magnetic Resonance (AQA A level Chemistry)
Переглядів 1,7 тис.3 роки тому
Y13 H NMR - Nuclear Magnetic Resonance (AQA A level Chemistry)
Study Smarter - Cornell Note-taking Method
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Study Smarter - Cornell Note-taking Method
Study Smarter - Six Learning Strategies
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Study Smarter - Six Learning Strategies
Hi, is there any reason you didn’t include the decimals whilst calculating the velocity?
hello! does lysine/aspartic acid from zwitterions then? because from my understanding it has to be neutral?
A zwitterion has to have no OVERALL charge. So each would have one NH2 group protonate and one COOH group deprotonated. Any further such groups would remain as they were.
@@simonflynn4515 thank you so much!
Best chemistry teacher unfortunately I only found your channel 2 days before my exam
For the question at 23:41 you used the moles of the acid and the salt, why didn't you divide them by the total volume to get their concentrations
I explained that the volumes cancel out (I’ve written it in blue). You can work out the concentrations here but you don’t need to with buffers. Either way, you get the same answer. Try it!
tysm!
Amazing video, it really helped me. Thank you :)
Glad to hear that!
Wow thank you so much im in year 10 and have my GCSEs next year and by watching these complicated questions broken down so simply is mesmerising and really helpful of you
You're very welcome!
Sir please could you do more videos on transition metals before june
We'll see!
What year paper is this and is it an AS paper ?
Yes, it's from an AS paper - I'm afraid I can't remember which one.
thank you! helped a lot
Glad it helped!
hi sir , when you drew the rate vs [A]^2 graph , why did you remove k?
I was drawing a proportional graph. k would be the gradient of this line.
Sir I had a q do we talk about the position of the equilibrium in reduction potentials form for both half equations?
If you change the conditions, you change the position of equilibrium. A question could concern that. However, I doubt of you’d be asked about the comparison between two half equations. However, I think it’s good for me to mention them when trying to explain things (hopefully). Does that answer your question?
That table that you have shown for the splitting and hydrogen is so easy to use compared to the data sheet all those R groups confuse me on the data sheet why is it so confusing
Because it can mean many different groups. I suppose to part of the challenge is to appreciate that what those different groups are doesn’t matter.
Why did you multiply the weight by avagadros constant, I read that on persons comment is that the Mr you calculated cos u only put the symbol kg. I'm so confused , I thought you could only multiply the number of moles by avagadros constant to find the total number of particles
I try to explain why in the video. Using the TOF equations, I am able to calculate the mass, in kg, of a single ion. But I have to work out the mass number, which is also the mass in grams of a mole of those ions. So I multiply by Avogadro's constant to work out the mass of a mole of ions in kg and then by a 1,000 to convert this into g. In this question, you're working in reverse to how you normally would. You typically start with a mass number e.g. Br-79 and then work out the mass of one [Br-79]+ ion by dividing 79 by 1,000 (to convert it to kg) and then by avogadro's constant. In this question, you have to go the other way. It would help me understand your question better if you said what you think I should have done.
Why not just use the Henderson-Hasselbalch equation?
It doesn't feature in AQA's specification.
धन्यवाद सर अमिनो आम्ले व प्रथिने यांचे छान स्पष्टीकरण दिलात
i love your channel keep it up
Thanks, will do!
How do you know whether something is a double bond or a triple bond or single
You’re either told or you can work it out from dot and cross or similar
Sir I just found your notes, their really useful! I'm finding useful as their mark scheme specific as well.
Glad you like them!
Wow this really helped me, i've been stuck on the 'bio' part of chem for so long now thank you so much!!!!
Glad it helped!
this helped so thx
What an amazing video 🎉
Thank you! 😁
Thank you:)
No problem 😊
Hello. Really helpful video. I just had one question as to why in the very last problem, when you added HCL, you took 'before' moles and not the 'after' ones to add to the moles of HCL
I'm not sure I did - I use the 'after' moles of 4.25 x 10^-3 weak acid and 3.75x10^-3 salt. Do you mind double-checking? Thanks.
Yes, actually you are right. My bad. Thanks again for the helpful video
Great video
Thanks!
Thank you! Please do more they're really useful 🙏
I'll do my best!
May you be rewarded for these videos, absolute life saver
Thanks!
Hello do u mind doing a video of life processes thankyou 😅
i have an acids , bases and buffers test tomorrow . its 2 am and u have saved my life honestly . : ))))
I hope it went well.
Thank you sir this really helped!
Glad it helped!
Nice video
Thanks
Hi sir your videos are great! Will you be doing more videos going through Year 13 Physical Chemistry?
Hopefully!
@@simonflynn4515Thanks! Your videos are useful and helping me prepare for my mocks
Good video dude
Appreciate it
Thank you for uploading and explaining your videos really well, it’s really helpful😊
Glad you like them!
29:16 Isn't the concentration of ch2clch2c00h = 0.019767.... as that is how much acid is remaining. I think you plugged the moles of the acid remaining into the ka eq but not its concentration?
I don't need to plug in the concentration of the acis remaining providing I also only plug in the moles of the salt. Concentration is moles / volume. As the volumes are the same for the acid and salt, they cancel out and I can just use moles. Say if I've misunderstood your query. Thanks.
Thank you so much ❤❤
You're welcome 😊
Thank you so much the video was helpful . God bless you
Glad it was helpful!
Thank you.
You're welcome!
Thank you so much This is really helpful
You're very welcome!
T hank you , this was useful
Glad it was helpful!
thank you
Thank you so much, you go into great detail on any related topics, very informative, much appreciated
Thank you - I'm glad it's helpful!
Thank you so much for these videos they’ve helped me more than you can imagine
I'm so glad! Thank you!
Hi sir, molecules containing polar bonds only vibrate/stretch/bend ?
All covalent bonds do but only polar bonds matter when it comes to the absorption of IR at A level.
Hi sir. For the last one, when calculating the concentrations after adding an extra 5cm3 of hcl. Would you include that volume in the total volume when calculating the new conc. I know it cancels but if you did wanna work it out would you add the 5cm3 to the total vol or is it negligible? Thanks.
You would add it. But the point is that it does cancel
@@simonflynn4515 thanks sir. Your video are useful. I will defo be sharing your channel with new year 12’s!
unless i'm doing something very wrong at 19:45 i think the mols of CH3COOH should be 9.25x10^-3 incase anyone doing calculations along with the video
You're right - I'm sorry about that.
Thank you so much for this. This is the only video where I’ve actually been able to draw them on my own by the end. You’re amazing!!
Thank you!
In the first question why did you use the concentrations of each substance in the final calculation but in the other questions you used moles in the final calculation. How are we meant to know when to use moles and when to use concentrations?
I used concentrations in the first two questions because this required either the same or fewer calculation. In the third, I explain why I don’t use concentrations - because the volumes cancel out. Providing your rearranged expression has the same number of [ ] above and below the fraction line (so the volumes cancel out), you can use moles or concentration. I’ve just don’t whichever is easier. I hope this helps.
@@simonflynn4515 howcome ka is in cm3 but the concentrations are in dm3 shouldnt they all be in the same units?
thank you! this was really helpful