Відео

Thanks a lot😄

@@engineerskaadda78 I don't know Hindi but I have got clear idea on concept 😅

@@k.tejareddy0272 that's something great to hear for me, u can check notes for complete information in english

Welcome dear ❤️

Thank you so much

@@Dr.SamirKumarSadhukhan-jw1wk didnt got yoir point sir , is this a new topic or something I missed in this topic?

BAE* is the new bidirectional heuristic search. See the paper "Bidirectional heuristic search using error estimate" And other referenced papers.

@@Dr.SamirKumarSadhukhan-jw1wk ok thnkx for the information ❤️

Yes sir , my goal is to explain the concept of SVD , not how to solve small equations. Thnkx for your valuable comment❤️

Ok so here i will explain you few steps u can try and also a example to be more specific , hope u understand- Step 1: Understand the Two Plausibility Cases Each plausibility case corresponds to a different subset or hypothesis in the frame of discernment. For each case, calculate the plausibility value based on the combination of the masses 𝑚1, 𝑚2, 𝑚3, 𝑚4 Step 2: Determine if the Cases Overlap If the two plausibility cases overlap (i.e., they pertain to subsets that are not mutually exclusive), combine the plausibility values by adding them. This is because their joint plausibility contributes to the overall belief in the union of these subsets. If the cases are disjoint (i.e., they pertain to subsets that have no common elements), handle them as separate hypotheses. You would then assign their masses separately and normalize afterward. Step 3: Normalize the Masses Add up all the resulting masses, including those from the two plausibility cases. Normalize by dividing each mass by the sum of the plausibilities to ensure the total mass equals 1. Example: Let’s say: 𝑚1(𝐴)=0.3 𝑚2(𝐴)=0.4 𝑚3(𝐵)=0.2 𝑚4(𝐶)=0.1 𝑚5 has two plausibility cases: Case 1: Plausibility for 𝐴∪𝐵= 0.6 Case 2: Plausibility for 𝐶 = 0.4 Steps: 1.Combine A∪B and 𝐶 if possible, or treat them as separate. 2.Calculate the total plausibility sum: Total Plausibility= 0.6+0.4=1.0 3.Normalize: 𝑚5(𝐴∪𝐵)=0.6/1.0=0.6 𝑚5(C)=0.4/1.0=0.4

@engineerskaadda78 Thankyou for the quick reply, it's very helpful 👍🏻

@@kratosss9981 its my pleasure dear❤️

Thnkx a lot❤️

Initially X1=[a b] ha , then A or B ka value find kar k , humlog bas value put kr diye waha pai

Thankss❤️

Thanks 🔥

Thank you 😄

Thanks a lot❤️

❤️❤️

Glad it helped u sir❤️

👍

Yes but for btech level , u won't get harder questions than this. That's y , only need to learn how much is required

❤️❤️

Thnkx❣️

Yess

Ok

Wlcm❤️

Thnku for the compliment ❣️ kindly share❤️

0+3b = 3b ok thats correct; but then see eqn 1 , waha likha ha -a+0b =0 , means -a = 0. Ok ! Then 0 +3b =3b (from matrix) so replace 0 with -a and 3b , 3b cancel out , so it becomes again -a + 0b = 0. Ok understood?

Sure will surely make

Ok thnkx for pointing out. Check after few hours , i will update it

Thnkxx❤️🙏

For minor project u can try basic projects like "text to speech conversion system", "speech to speech conversion system", "fraud detection", "recommendation system". And for little good projects u can try for "stock price predection system", "email spam filtering system", "basic chatbots", "creditcard fraud detection system".

Thats really nice to hear 😊 happy to help u

Thnku sir❤️

Glad u liked it❤️

Aisa to nhi ho sakta sir. Maybe kuch glti huyi ho aapse ya mujhse. But follow the process , process is important, process samjhna ha

​@@engineerskaadda7820.48 jis equation se lembda=2 k liye eigon vector nikla h vo equation m vo vector put krke dekio satisfy nhi ho rha h

Thnku❤️

😂😂good

Haa. Apne sare batchmastes k sath share kr dena❤️

@@engineerskaadda78 ofcourse bhai... Cryptography and data mining and warehouse pe banao Bhaiya

@@shubhamkumar9895 sab ek sath to nhi bana sakte. Dekhte ha jitna cover sakte ha

Thnku

❤️

Thnkx a lot dear❤️

Ok thnkx for suggestion, will improve !! Check other videos also of the playlist. This is a numerical , nothing much here to make u understand ,u should have strong mathematics dear , then it will be crystal clear.

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