Відео

thank you so much @rocky_star_9972❤‍🔥

thanks, means a lot❤🔥

your welcome bro😊😊means a lot

Do u set urdu keyboard? For this language should be like english so that issue will not occur

same for both

in microsoft word, write fdfd and then press alt+x to replace fdfd with ﷽ (Bismillah as complete Arabic phrase/verse) in ms word.

@@Efficientlearningworld Ok bro shukriya

cobbler koi khushi sa tu ni na bnta ya banna chahta😂bs cobbler tu cobbler hota. apny kabhi ni dekha ho ga kisi ko ka wo kahy mera bachpan sa sapna tha ka ma cobbler bnon. wo tu mjbori ma krty hain like pr agr ap cobbler ho aur ismh maharat rakhty aur apna kam achy sa kro aur zimedari sa karo tu semantics change ho kr work loyalth ma a jay ga ka ap apny profession ka sath loyal ho yani its not like ka bs jota sena its ka kam chota ho ya bara usko proper 100% best way ma krna dandi na mrna

thank you soo much friend, means a lottttt😊😊😊😊

thank you so much friend😇🥲really tbh means a lot, stay happy blessed

MAA SHAA ALLAH❤

Thanks Brother🙌

That's awesome to hear! I'm glad I could help you out.

Nope, it will not delete any imp file 📁. If it finds out any importsnt file then it will show you in the dialog box that cant delete this file. What you want Skip? or cancel ❌ Then you can click on skip or cancel, that will not delete any further file.😃care2

@@Efficientlearningworld ok sir. Yr app ka channel monitize hay ki nahi aap itnay salo say video dalke hard work kar rahe hay

🥺it's monetized bro.

To create a complete diamond pattern, you'll need to combine the four parts of your code into one coherent pattern. Here's how you can do it: The top half of the diamond (upper triangle). The bottom half of the diamond (lower triangle). Here's the code for a complete diamond pattern: #include <iostream> using namespace std; int main() { int n = 4; // You can change this to make a larger or smaller diamond int c; // Upper part of the diamond c = n; for(int j = 1; j <= n; j++) { for(int i = 1; i <= c; i++) cout << " "; for(int i = 1; i <= (2 * j - 1); i++) cout << "*"; cout << endl; c--; } // Lower part of the diamond c = 1; for(int j = n - 1; j >= 1; j--) { for(int i = 1; i <= c; i++) cout << " "; for(int i = 1; i <= (2 * j - 1); i++) cout << "*"; cout << endl; c++; } return 0; } Explanation: Upper Part: c = n; sets the initial number of spaces. The outer loop runs from 1 to n to create the upper half of the diamond. The first inner loop prints the spaces before the stars. The second inner loop prints the stars for each row. The number of stars follows the pattern 2 * j - 1 where j is the current row number. Lower Part: c = 1; sets the initial number of spaces. The outer loop runs from n - 1 down to 1 to create the lower half of the diamond. The first inner loop prints the spaces before the stars. The second inner loop prints the stars for each row. The number of stars follows the pattern 2 * j - 1 where j is the current row number. This code will print a symmetrical diamond pattern centered on the console. You can adjust the value of n to change the size of the diamond. Sorry for the late reply friend! I just saw your comment just now

Power can be negative in math but you can try it by your own end but if you want to make it intentional positive power than write it in abs() that will make it positive.

Thanks

barakALLAH❤

Did you write the same as in the video?, because mine one worked!

ThankU friend

😂😂

Same

I pushed code on github repository. The link is in the description.

😂begairtian ni mrni yehu