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Kasyanno EZMath
Приєднався 9 бер 2012
Kasyanno EZMath for all learners.The mission of this channel is to let learners know that math is easy and fascinating to learn only if the learner is driven or willing and eager to learn. This channel is geared towards enhancing your knowledge and skills in math. Let math redefine how you see the world from a new perspective. Any normal person has the capacity to learn and relearn or master math. Forget the past because you are now in control of your future. Having good math knowledge and skills will enhance your imagination and creativity and will boost your self-confidence and personal development - a good leverage in job promotions and career advancement. Get on your NEW SELF ready right now, and subscribing to my channel is the first step. Happy learning!
Solving Exponential Equation 8x=e^(2x)
In this video, you'll learn how to solve exponential equations by using the Lambert W Function.
Переглядів: 63
Відео
The Logarithmic Cancellation Formula
Переглядів 63Місяць тому
Here, you'll learn how to solve logarithmic equations by using the cancelation formula.
How to Solve Logarithmic Equation with Decimal Argument
Переглядів 87Місяць тому
How to Solve Logarithmic Equation with Decimal Argument
Find the equation of the circle with the given center and radius.
Переглядів 442 місяці тому
Find the equation of the circle with the given center and radius.
How to Solve Algebra Mixture Word Problem
Переглядів 513 місяці тому
How to Solve Algebra Mixture Word Problem
Twice the sum of 2 and square of the number equals 2 less than 8 times the number. Find the number.
Переглядів 6404 місяці тому
Twice the sum of 2 and square of the number equals 2 less than 8 times the number. Find the number.
Solving Exponential Equation @KasyannoEZMath
Переглядів 1044 місяці тому
Solving Exponential Equation @KasyannoEZMath
Exponential Expressions with Negative Base and/or Negative Exponents
Переглядів 1385 місяців тому
Exponential Expressions with Negative Base and/or Negative Exponents
How to Solve Exponential Equations with the Same Base
Переглядів 846 місяців тому
How to Solve Exponential Equations with the Same Base
Find the Present Age of Art (Algebra Word Problem) @KasyannoEZMath
Переглядів 6716 місяців тому
Find the Present Age of Art (Algebra Word Problem) @KasyannoEZMath
Quadratic Equation with Negative Exponents
Переглядів 1877 місяців тому
Quadratic Equation with Negative Exponents
Solving a Variable with Negative Exponent
Переглядів 19110 місяців тому
Solving a Variable with Negative Exponent
Simple Exponential Equation/solve and graph
Переглядів 35110 місяців тому
Simple Exponential Equation/solve and graph
i got the answer in like 2 seconds, but i didn’t show my work so im wrong lmfao
Why even bother teaching division? Just teach fractions. It would save anyone from the useless syntactic confusion that is represented in this video. Even better, the understanding that division is just multiplying by the reciprocal is obvious if you just go straight to fractions without bothering with that useless symbol that is not even used for that long.
What do you mean bother teaching division? Knowing the definition and use of division is so important in math? Why would you get rid of it? Sure it’s the same shit as a fraction, but that’s not the only time you introduce division in any application in math?
Why that last step? You already simplified it with 3 to the 21. Is it because 7 is a prime?
It's just another representation of 3²¹.
Tysm!u had helped me a lot. 😊
Ok, "my neural network" instinctively solved it within 4 seconds as 81 - 64 = 17 which is 9² - 4³, with m=2 and n=3, which is of course a hack not a real solution 😂 Man, I love your OLD long videos 😊
Thank you very much, and I'm very happy knowing that you love my old, long videos. Unfortunately, nowadays, most viewers prefer watching short over long videos since short videos started. In short videos, you don't have much time explaining about the content. But in long videos, you have all the time to explain every step of the solution, and that's what I prefer doing it. Have a wonderful day, Andy O! Best regards!
A beautiful problem ❤ I got carried away and in my wrong solution x was ½ 😂 But hey, in here 3:40 isn't it easier-to-follow to express 1 as 2⁰ ? Then it becomes: 2× = 2⁰ x = 0 ..pretty much what you were doing all this long, why did you have to bring that clunky LOG right in the end when it's very unnecessary ? 😉
The longer the video sometimes the more you learn. Instead of ending it with 2⁰ is 1, you'll learn logarithms.
@@KasyannoEZMath Sorry man, not in this video no I wouldn't 😁 If I hadn't known the Log stuff already I'd be somewhat puzzled. I mean in your other videos you explained LOGs really well and more than once but not in this one - which is fine because you explained brilliantly the rest.
Thanks for your time, Andy O! Have a good one!
@@KasyannoEZMath No, thank you! Your other videos taught me logarithms a year and a half ago 😉
Since we don't care about actually finding x, assign C to equal cbrt(x) Then it becomes: 1 + 1/C = 5 Solve for C: C = 1/4 Plug in 2nd expression: 1 - 1/(2*C) = 1 - 1/(2*1/4) = 1 - 2 = -1
1 - 1/(2/4) = 1 - 2 = -1 not 1/2
@@yousefhurani8822 Thank you, I corrected it.
Excellent!
Very good!
(log x)^2 =( log 4)^2 log x = +- log 4 = log 4, log (1/4) x = 4, 1/4
Very easy to follow thanks alot
You're very welcome.
O.k This could be done without assuming base also.
X=33
Please review your answer.
That is not final answer...the final answer should be *e^W(ln2)* instead of e^(-W(ln(0.5)))... You left it there, it's now driving me crazy 🐺😡
I would like to see your solution. The alternate form of the solution is: x= -w(-ln2)/ln2
Nice work
Thank you!
Only +
That bug is going to have math phobia!
I blew on it thinking it was on my screen 😅
@@ajdonovan5731 😂😂😂😂 same here
😢😢pehley tha. 😊😊😊 ab
Very good explanation!
Thanks!
this is what i was taught in school
It took way longer than the common way
we can use logarithms and sove easily.
Thanks buddy 😊
-3/2
You're awesome!!
I came up with a poem of my own for the cubic formula: x^3 + n*x = m x = cbrt(m/2 + sqrt(D)) + cbrt(m/2 - sqrt(D)) D = (m/2)^2 + (n/3)^3 When x is cubed and x times n, Are added and equal to m. The values of x, The goals of our quest, Here's how to calculate them. Cube roots to add, Square roots they had, Both of a term we'll call D. Square half of m, Cube third of n, Add together and see. Half of m, adds to the root, First with a sign of plus. Its little brother, Is just like the other, Except with a sign of minus. Cube rooting time, of both the brothers, Add up the roots with glee. We found our first x, But where is the next? I know there have to be three. With help from DeMoivre, Who's theorem, we love ya, There's cube roots all over the plane Yes, they're complex, But do not perplex, A new kind of numbers we gain.
Brilliant!
Idk, maybe cause i'm a sixth grader but I'll probably learn something from this.
Definitely! It's never too early to learn something that is advanced.
Revisiting this video after 1 year I solved it like this: Let t = 1/27 t^(2-x) = t^(-2) 2 - x = -2 x=4
You're awesome, Andy O!
@@KasyannoEZMath 🤭😊
Ok, this time I got off with a good start (actually doing the difficult bit) but got overexcited and bogged with LOGs. I'll re-visit this video in 1 year and hopefully then will solve it with ease :)
👍
Hey Kasyanno, I just re-watched it now 1 year afterwards, much to my surprise I solved it WITH EASE and in a completely different way to yours. All I had to do was "power up" both sides of this equation to the power of 1/5. So it became this: (x/5)^(x/5) = 5 ^(25/5) leading to x/5 = 5; x = 25 Thank you, man, your videos got me started. Just 1 years and 3 months ago Yоutu6е would show me your exponential equation challenges and I would scratch my head (in shame) asking myself "what is even LOG ? It's a high time for me to find out !!!"
You're awesome, Andy O! You're rediscovering and unleashing the boundless power of your brain. Good job!
Alright but what if we cant take a common out or if theres no x^2 term or x term?? Im askin this cuz the explanation is so good
That can't be done by factoring by grouping.
As other people pointed out, you made an error: the square root of x^2 is *only* equal to +3. You would have to take the inverse function of x^2, whose result is ±3.
Taking the square root of both sides of the equation will yield x= +/-3, not just the principal square root of 9. Taking the square root of both sides of the equation is the same as raising both sides of the equation to power 1/2. Don't get confused with the equation x²=9 which will give you + and - values.
Still doesnt give what x or y is but i guess that wasnt the question
Simple intrinsic math from there gcd of 20 out of 95 is 4 so 20x= 20x4=80 and remainder 5y=5x3=15.
Fabulous 🤩
I don’t see what people are saying in the comments, All the x values you solved are correct when plugged back into the original equation.
There is no need for math. Anything divided or times by 0 is 0. So to get 0, you put X as 0. Edit also you're incorrect cause the equation was not X minus 9 it's negative 9 times the second X.
This is wrong: x^2 -9 is a difference of squares which can be expanded into (x+3)(x-3) which produces the x’s of x=3 and x=-3. The square root function only provides positive outputs. [graph sqrt(x) on desmos]
I notice the same. ❤
The expanded form is generally the way to do it, but that's not the only way to solve the equation. Taking the square root on both sides of the equation or raising it to power 1/2 are the other ways to solve it. Taking the square root of the constant will get you positive and negative values, not just the principal value that is the positive value.
Which is why there's a ±
This makes no sense
It does, he just didnt explain the 1. step (the most important). The logic is 2^x + 2^x = 2^x+1 3^x + 3^x + 3^x = 3^x+1
@@lars8991 use brackets lol
Wrong x = 3/2
X=2/3
Don’t show Terrence Howard this haha
The way you draw your 4 is a warcrime anyway good luck stranger I won’t see you again hope your life is good.
drop the base! i like exponential ecuations
Very good!
You can also just do 50 percent of 20 which is clearly 10, and 30 percent of that which is clearly 3
Or you can just do it in your head like a smart person does.
So much harder than it needs to be. 30% of 50 is 15. 20% of 15 is 3.
Oh, and a lefty to boot!!! Me mum and grandmum the same
Yummy problem, a hot cocoa lover meself, danke to you!!
Thanks, Nancy! Have a wonderful day!
I don’t believe it has a solution, or at least needs more clarification around the quotient part.
The quotient indicates division, and the first number/ variable mentioned is the numerator, and the second mentioned is the denominator.
@@KasyannoEZMath so 7/x or x/7? Im a little stupid rn sry
@1gn30us, it's x/7.
@@KasyannoEZMath I threw away the Papier but I believe that would make it 7(3x/2)=x, witch i believe is unsolvable? I’d have too double check if I get time tmrw, end of school got a lot of work
@@KasyannoEZMath it would be 7(3x/2 - 2) = x then no? I believe that makes it unsolvable, if it were 7/x I think it would be x=3
what a dreadful problem
Not really. Practice solving is the key.
It is 1 o clock for me someone reply in like 7 hours and I’ll do it.
I don’t understand the step where you put parentheses around everything and then put a “ -1” outside. What were you doing in that step exactly?
Multiplying the whole equation by -1.
Conjugate and u-sub is the same result.