Kasyanno EZMath
Kasyanno EZMath
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Solving Exponential Equation 8x=e^(2x)
In this video, you'll learn how to solve exponential equations by using the Lambert W Function.
Переглядів: 63

Відео

The Logarithmic Cancellation Formula
Переглядів 63Місяць тому
Here, you'll learn how to solve logarithmic equations by using the cancelation formula.
How to Solve Logarithmic Equation with Decimal Argument
Переглядів 87Місяць тому
How to Solve Logarithmic Equation with Decimal Argument
Log Equation with Decimal Argument
Переглядів 63Місяць тому
Log Equation with Decimal Argument
Solving Logarithmic Equation
Переглядів 263Місяць тому
Solving Logarithmic Equation
Find the equation of the circle with the given center and radius.
Переглядів 442 місяці тому
Find the equation of the circle with the given center and radius.
Find the Real Values of X in 2 ways
Переглядів 813 місяці тому
Find the Real Values of X in 2 ways
Algebra Numbers Word Problem
Переглядів 383 місяці тому
Algebra Numbers Word Problem
How to Solve Algebra Mixture Word Problem
Переглядів 513 місяці тому
How to Solve Algebra Mixture Word Problem
How to Solve Algebra Work Problem
Переглядів 753 місяці тому
How to Solve Algebra Work Problem
Twice the sum of 2 and square of the number equals 2 less than 8 times the number. Find the number.
Переглядів 6404 місяці тому
Twice the sum of 2 and square of the number equals 2 less than 8 times the number. Find the number.
Solving Exponential Equation @KasyannoEZMath
Переглядів 1044 місяці тому
Solving Exponential Equation @KasyannoEZMath
Expand and Simplify
Переглядів 1295 місяців тому
Expand and Simplify
Simplifying Exponential Expression
Переглядів 945 місяців тому
Simplifying Exponential Expression
How to Simplify Radicals
Переглядів 7085 місяців тому
How to Simplify Radicals
Exponential Expressions with Negative Base and/or Negative Exponents
Переглядів 1385 місяців тому
Exponential Expressions with Negative Base and/or Negative Exponents
Solving Exponential Equation
Переглядів 4565 місяців тому
Solving Exponential Equation
How to Solve Exponential Equations with the Same Base
Переглядів 846 місяців тому
How to Solve Exponential Equations with the Same Base
How to Solve Complex Word Problem
Переглядів 1186 місяців тому
How to Solve Complex Word Problem
Find the Present Age of Art (Algebra Word Problem) @KasyannoEZMath
Переглядів 6716 місяців тому
Find the Present Age of Art (Algebra Word Problem) @KasyannoEZMath
Quadratic Equation with Negative Exponents
Переглядів 1877 місяців тому
Quadratic Equation with Negative Exponents
Calculus Word Problem Solving
Переглядів 1059 місяців тому
Calculus Word Problem Solving
Solving Exponential Equation
Переглядів 62510 місяців тому
Solving Exponential Equation
Solving a Variable with Negative Exponent
Переглядів 19110 місяців тому
Solving a Variable with Negative Exponent
Solving Exponential Equation
Переглядів 43810 місяців тому
Solving Exponential Equation
Olympiad Math Question
Переглядів 30510 місяців тому
Olympiad Math Question
Simple Exponential Equation/solve and graph
Переглядів 35110 місяців тому
Simple Exponential Equation/solve and graph
Olympiad Math Question
Переглядів 69910 місяців тому
Olympiad Math Question
How to Square Any Two-digit Number
Переглядів 56810 місяців тому
How to Square Any Two-digit Number
How to Simplify Complex Fractions
Переглядів 33810 місяців тому
How to Simplify Complex Fractions

КОМЕНТАРІ

  • @nickfox5457
    @nickfox5457 День тому

    i got the answer in like 2 seconds, but i didn’t show my work so im wrong lmfao

  • @godthatisfox
    @godthatisfox 3 дні тому

    Why even bother teaching division? Just teach fractions. It would save anyone from the useless syntactic confusion that is represented in this video. Even better, the understanding that division is just multiplying by the reciprocal is obvious if you just go straight to fractions without bothering with that useless symbol that is not even used for that long.

    • @henrymenendez7655
      @henrymenendez7655 3 дні тому

      What do you mean bother teaching division? Knowing the definition and use of division is so important in math? Why would you get rid of it? Sure it’s the same shit as a fraction, but that’s not the only time you introduce division in any application in math?

  • @internetmovieguy
    @internetmovieguy 4 дні тому

    Why that last step? You already simplified it with 3 to the 21. Is it because 7 is a prime?

    • @KasyannoEZMath
      @KasyannoEZMath 4 дні тому

      It's just another representation of 3²¹.

  • @KhuslenKhuslen-tm7oe
    @KhuslenKhuslen-tm7oe 5 днів тому

    Tysm!u had helped me a lot. 😊

  • @b213videoz
    @b213videoz 13 днів тому

    Ok, "my neural network" instinctively solved it within 4 seconds as 81 - 64 = 17 which is 9² - 4³, with m=2 and n=3, which is of course a hack not a real solution 😂 Man, I love your OLD long videos 😊

    • @KasyannoEZMath
      @KasyannoEZMath 13 днів тому

      Thank you very much, and I'm very happy knowing that you love my old, long videos. Unfortunately, nowadays, most viewers prefer watching short over long videos since short videos started. In short videos, you don't have much time explaining about the content. But in long videos, you have all the time to explain every step of the solution, and that's what I prefer doing it. Have a wonderful day, Andy O! Best regards!

  • @b213videoz
    @b213videoz 16 днів тому

    A beautiful problem ❤ I got carried away and in my wrong solution x was ½ 😂 But hey, in here 3:40 isn't it easier-to-follow to express 1 as 2⁰ ? Then it becomes: 2× = 2⁰ x = 0 ..pretty much what you were doing all this long, why did you have to bring that clunky LOG right in the end when it's very unnecessary ? 😉

    • @KasyannoEZMath
      @KasyannoEZMath 16 днів тому

      The longer the video sometimes the more you learn. Instead of ending it with 2⁰ is 1, you'll learn logarithms.

    • @b213videoz
      @b213videoz 16 днів тому

      @@KasyannoEZMath Sorry man, not in this video no I wouldn't 😁 If I hadn't known the Log stuff already I'd be somewhat puzzled. I mean in your other videos you explained LOGs really well and more than once but not in this one - which is fine because you explained brilliantly the rest.

    • @KasyannoEZMath
      @KasyannoEZMath 15 днів тому

      Thanks for your time, Andy O! Have a good one!

    • @b213videoz
      @b213videoz 14 днів тому

      @@KasyannoEZMath No, thank you! Your other videos taught me logarithms a year and a half ago 😉

  • @carultch
    @carultch 18 днів тому

    Since we don't care about actually finding x, assign C to equal cbrt(x) Then it becomes: 1 + 1/C = 5 Solve for C: C = 1/4 Plug in 2nd expression: 1 - 1/(2*C) = 1 - 1/(2*1/4) = 1 - 2 = -1

  • @cosmolbfu67
    @cosmolbfu67 24 дні тому

    (log x)^2 =( log 4)^2 log x = +- log 4 = log 4, log (1/4) x = 4, 1/4

  • @user-th2rs1ry2q
    @user-th2rs1ry2q 24 дні тому

    Very easy to follow thanks alot

  • @jagadiswarchakraborty295
    @jagadiswarchakraborty295 25 днів тому

    O.k This could be done without assuming base also.

  • @user-fl7vn3wz4o
    @user-fl7vn3wz4o Місяць тому

    X=33

  • @odio_stationofficial3420
    @odio_stationofficial3420 Місяць тому

    That is not final answer...the final answer should be *e^W(ln2)* instead of e^(-W(ln(0.5)))... You left it there, it's now driving me crazy 🐺😡

    • @KasyannoEZMath
      @KasyannoEZMath 21 день тому

      I would like to see your solution. The alternate form of the solution is: x= -w(-ln2)/ln2

  • @thevectorspaceofmath
    @thevectorspaceofmath Місяць тому

    Nice work

  • @CommonGrimeConsumer
    @CommonGrimeConsumer Місяць тому

    Only +

  • @andybogart2503
    @andybogart2503 Місяць тому

    That bug is going to have math phobia!

    • @ajdonovan5731
      @ajdonovan5731 Місяць тому

      I blew on it thinking it was on my screen 😅

    • @alexmulaku7530
      @alexmulaku7530 Місяць тому

      ​@@ajdonovan5731 😂😂😂😂 same here

  • @pendujatthjk5035
    @pendujatthjk5035 Місяць тому

    😢😢pehley tha. 😊😊😊 ab

  • @eduardomatos3777
    @eduardomatos3777 Місяць тому

    Very good explanation!

  • @edvardskalva
    @edvardskalva Місяць тому

    this is what i was taught in school

  • @pavelmoraguez1078
    @pavelmoraguez1078 Місяць тому

    It took way longer than the common way

  • @VijayBhaskarSingh
    @VijayBhaskarSingh Місяць тому

    we can use logarithms and sove easily.

  • @yt_ashu
    @yt_ashu 2 місяці тому

    Thanks buddy 😊

  • @omaradnan9289
    @omaradnan9289 2 місяці тому

    -3/2

  • @carultch
    @carultch 2 місяці тому

    I came up with a poem of my own for the cubic formula: x^3 + n*x = m x = cbrt(m/2 + sqrt(D)) + cbrt(m/2 - sqrt(D)) D = (m/2)^2 + (n/3)^3 When x is cubed and x times n, Are added and equal to m. The values of x, The goals of our quest, Here's how to calculate them. Cube roots to add, Square roots they had, Both of a term we'll call D. Square half of m, Cube third of n, Add together and see. Half of m, adds to the root, First with a sign of plus. Its little brother, Is just like the other, Except with a sign of minus. Cube rooting time, of both the brothers, Add up the roots with glee. We found our first x, But where is the next? I know there have to be three. With help from DeMoivre, Who's theorem, we love ya, There's cube roots all over the plane Yes, they're complex, But do not perplex, A new kind of numbers we gain.

  • @favillany
    @favillany 2 місяці тому

    Idk, maybe cause i'm a sixth grader but I'll probably learn something from this.

    • @KasyannoEZMath
      @KasyannoEZMath 2 місяці тому

      Definitely! It's never too early to learn something that is advanced.

  • @b213videoz
    @b213videoz 2 місяці тому

    Revisiting this video after 1 year I solved it like this: Let t = 1/27 t^(2-x) = t^(-2) 2 - x = -2 x=4

  • @b213videoz
    @b213videoz 2 місяці тому

    Ok, this time I got off with a good start (actually doing the difficult bit) but got overexcited and bogged with LOGs. I'll re-visit this video in 1 year and hopefully then will solve it with ease :)

  • @b213videoz
    @b213videoz 2 місяці тому

    Hey Kasyanno, I just re-watched it now 1 year afterwards, much to my surprise I solved it WITH EASE and in a completely different way to yours. All I had to do was "power up" both sides of this equation to the power of 1/5. So it became this: (x/5)^(x/5) = 5 ^(25/5) leading to x/5 = 5; x = 25 Thank you, man, your videos got me started. Just 1 years and 3 months ago Yоutu6е would show me your exponential equation challenges and I would scratch my head (in shame) asking myself "what is even LOG ? It's a high time for me to find out !!!"

    • @KasyannoEZMath
      @KasyannoEZMath 2 місяці тому

      You're awesome, Andy O! You're rediscovering and unleashing the boundless power of your brain. Good job!

  • @Mahathi2010
    @Mahathi2010 2 місяці тому

    Alright but what if we cant take a common out or if theres no x^2 term or x term?? Im askin this cuz the explanation is so good

    • @KasyannoEZMath
      @KasyannoEZMath 2 місяці тому

      That can't be done by factoring by grouping.

  • @destructorcreeper7797
    @destructorcreeper7797 2 місяці тому

    As other people pointed out, you made an error: the square root of x^2 is *only* equal to +3. You would have to take the inverse function of x^2, whose result is ±3.

    • @KasyannoEZMath
      @KasyannoEZMath 2 місяці тому

      Taking the square root of both sides of the equation will yield x= +/-3, not just the principal square root of 9. Taking the square root of both sides of the equation is the same as raising both sides of the equation to power 1/2. Don't get confused with the equation x²=9 which will give you + and - values.

  • @nightwing265
    @nightwing265 2 місяці тому

    Still doesnt give what x or y is but i guess that wasnt the question

    • @keaganlalonde3997
      @keaganlalonde3997 2 місяці тому

      Simple intrinsic math from there gcd of 20 out of 95 is 4 so 20x= 20x4=80 and remainder 5y=5x3=15.

  • @Player_is_I
    @Player_is_I 2 місяці тому

    Fabulous 🤩

  • @exy8423
    @exy8423 2 місяці тому

    I don’t see what people are saying in the comments, All the x values you solved are correct when plugged back into the original equation.

  • @godhatesgamers9843
    @godhatesgamers9843 2 місяці тому

    There is no need for math. Anything divided or times by 0 is 0. So to get 0, you put X as 0. Edit also you're incorrect cause the equation was not X minus 9 it's negative 9 times the second X.

  • @skvttlez1263
    @skvttlez1263 2 місяці тому

    This is wrong: x^2 -9 is a difference of squares which can be expanded into (x+3)(x-3) which produces the x’s of x=3 and x=-3. The square root function only provides positive outputs. [graph sqrt(x) on desmos]

    • @wieslawhead7319
      @wieslawhead7319 2 місяці тому

      I notice the same. ❤

    • @KasyannoEZMath
      @KasyannoEZMath 2 місяці тому

      The expanded form is generally the way to do it, but that's not the only way to solve the equation. Taking the square root on both sides of the equation or raising it to power 1/2 are the other ways to solve it. Taking the square root of the constant will get you positive and negative values, not just the principal value that is the positive value.

    • @Ykibmh
      @Ykibmh 2 місяці тому

      Which is why there's a ±

  • @isaac2260
    @isaac2260 2 місяці тому

    This makes no sense

    • @lars8991
      @lars8991 2 місяці тому

      It does, he just didnt explain the 1. step (the most important). The logic is 2^x + 2^x = 2^x+1 3^x + 3^x + 3^x = 3^x+1

    • @Shotgunz999
      @Shotgunz999 2 місяці тому

      ​@@lars8991 use brackets lol

  • @ziyadb2526
    @ziyadb2526 2 місяці тому

    Wrong x = 3/2

  • @ziyadb2526
    @ziyadb2526 2 місяці тому

    X=2/3

  • @ChristopherAwesome-ix1bg
    @ChristopherAwesome-ix1bg 3 місяці тому

    Don’t show Terrence Howard this haha

  • @Petrichor708
    @Petrichor708 3 місяці тому

    The way you draw your 4 is a warcrime anyway good luck stranger I won’t see you again hope your life is good.

  • @MK_0841
    @MK_0841 3 місяці тому

    drop the base! i like exponential ecuations

  • @KayOScode
    @KayOScode 3 місяці тому

    You can also just do 50 percent of 20 which is clearly 10, and 30 percent of that which is clearly 3

  • @lp7343
    @lp7343 3 місяці тому

    Or you can just do it in your head like a smart person does.

  • @harstar12345
    @harstar12345 3 місяці тому

    So much harder than it needs to be. 30% of 50 is 15. 20% of 15 is 3.

  • @nancydelu4061
    @nancydelu4061 3 місяці тому

    Oh, and a lefty to boot!!! Me mum and grandmum the same

  • @nancydelu4061
    @nancydelu4061 3 місяці тому

    Yummy problem, a hot cocoa lover meself, danke to you!!

    • @KasyannoEZMath
      @KasyannoEZMath 3 місяці тому

      Thanks, Nancy! Have a wonderful day!

  • @1gn30us
    @1gn30us 3 місяці тому

    I don’t believe it has a solution, or at least needs more clarification around the quotient part.

    • @KasyannoEZMath
      @KasyannoEZMath 3 місяці тому

      The quotient indicates division, and the first number/ variable mentioned is the numerator, and the second mentioned is the denominator.

    • @1gn30us
      @1gn30us 3 місяці тому

      @@KasyannoEZMath so 7/x or x/7? Im a little stupid rn sry

    • @KasyannoEZMath
      @KasyannoEZMath 3 місяці тому

      @1gn30us, it's x/7.

    • @1gn30us
      @1gn30us 3 місяці тому

      @@KasyannoEZMath I threw away the Papier but I believe that would make it 7(3x/2)=x, witch i believe is unsolvable? I’d have too double check if I get time tmrw, end of school got a lot of work

    • @1gn30us
      @1gn30us 3 місяці тому

      @@KasyannoEZMath it would be 7(3x/2 - 2) = x then no? I believe that makes it unsolvable, if it were 7/x I think it would be x=3

  • @davidseed2939
    @davidseed2939 3 місяці тому

    what a dreadful problem

    • @KasyannoEZMath
      @KasyannoEZMath 3 місяці тому

      Not really. Practice solving is the key.

  • @1gn30us
    @1gn30us 3 місяці тому

    It is 1 o clock for me someone reply in like 7 hours and I’ll do it.

  • @mtc-j9i
    @mtc-j9i 3 місяці тому

    I don’t understand the step where you put parentheses around everything and then put a “ -1” outside. What were you doing in that step exactly?

    • @KasyannoEZMath
      @KasyannoEZMath 3 місяці тому

      Multiplying the whole equation by -1.

  • @AliHassan-hb1bn
    @AliHassan-hb1bn 3 місяці тому

    Conjugate and u-sub is the same result.