- 523
- 1 687 752
Math E Connect
India
Приєднався 15 вер 2017
Asst. Prof. Shafiqahmed M Yellur, Jain College of Engineering Belgaum
Відео
Solve 𝟑𝟐 𝝏𝒖/𝝏𝒕=(𝝏^𝟐 𝒖)/〖𝝏𝒙〗^𝟐 (𝟎, 𝟏) given that h=0.25, upto t=5 𝒖=(𝟎,𝒕)=𝟎=𝒖(𝟏,𝒕), 𝒖=(𝒙,𝟎).
Переглядів 947Рік тому
21MAT11 : Solve 𝟑𝟐 𝝏𝒖/𝝏𝒕=(𝝏^𝟐 𝒖)/〖𝝏𝒙〗^𝟐 (𝟎, 𝟏) given that h=0.25, upto t=5 𝒖=(𝟎,𝒕)=𝟎=𝒖(𝟏,𝒕), 𝒖=(𝒙,𝟎). #MathEConnect #Shafiqahmedyellur
Solve 𝝏𝒖/𝝏𝒕=(𝝏^𝟐 𝒖)/𝝏𝒙^𝟐 (𝟎, 𝟏) at t=0.002 𝒖=(𝟎,𝒕)=𝟎=𝒖(𝟏,𝒕), 𝒖(𝒙,𝟎)={(𝟐𝒙 (𝟎, 𝟎.𝟓) @𝟐(𝟏−𝒙), (𝟎.𝟓, 𝟏)
Переглядів 261Рік тому
21MAT41 : Solve 𝝏𝒖/𝝏𝒕=(𝝏^𝟐 𝒖)/〖𝝏𝒙〗^𝟐 (𝟎, 𝟏 at t=0.002 𝒖=(𝟎,𝒕)=𝟎=𝒖(𝟏,𝒕), 𝒖(𝒙,𝟎)={(𝟐𝒙 (𝟎, 𝟎.𝟓) 𝟎@𝟐(𝟏−𝒙) (𝟎.𝟓, 𝟏) #MathEConnec #Shafiqahmedyellur
Find the numerical solution (𝝏^𝟐 𝒖)/𝝏𝒙^𝟐 =𝟐 𝝏𝒖/𝝏𝒕 , 𝒖=(𝟎,𝒕)=𝟎=𝒖(𝟒,𝒕), 𝒖(𝒙,𝟎)=𝒙(𝟒−𝒙) ,h=1,t=4 steps.
Переглядів 67Рік тому
21MAT31 : Find the numerical solution of the parabolic equation (𝝏^𝟐 𝒖)/𝝏𝒙^𝟐 =𝟐 𝝏𝒖/𝝏𝒕 when 𝒖=(𝟎,𝒕)=𝟎=𝒖(𝟒,𝒕), 𝒖(𝒙,𝟎)=𝒙(𝟒−𝒙) by taking h=1, upto t=4 steps. #MathEConnect #Shafiqahmedyellur
Numerical Solution of the one dimensional Heat equation & working procedure.
Переглядів 50Рік тому
21MAT31 : Numerical Solution of the one dimensional Heat equation & working procedure #MathEConnect #Shafiqahmedyellur
Show that: 𝒊)𝑷_𝟐(𝒄𝒐𝒔𝜽)=1/4 (𝟏+𝟑𝒄𝒐𝒔𝜽), 𝒊𝒊) 𝑷_𝟑 (𝒄𝒐𝒔𝜽)=𝟏/𝟖 (𝟑𝒄𝒐𝒔𝜽+𝟓𝒄𝒐𝒔𝟑𝜽).
Переглядів 80Рік тому
21MAT11 : Show that: 𝒊)𝑷_𝟐(𝒄𝒐𝒔𝜽)=1/4 (𝟏 𝟑𝒄𝒐𝒔𝜽) 𝒊𝒊) 𝑷_𝟑 (𝒄𝒐𝒔𝜽)=𝟏/ (𝟑𝒄𝒐𝒔𝜽 𝟓𝒄𝒐𝒔𝟑𝜽) #MathEConnect #Shafiqahmedyellur
Express 𝒇(𝒙)=𝒙^𝟒−𝟑𝒙^𝟑−𝒙^𝟐+𝟓𝒙 in terms of Legendre polynomial.
Переглядів 1,3 тис.Рік тому
21MAT41 : Express 𝒇(𝒙)=𝒙^𝟒−𝟑𝒙^𝟑−𝒙^𝟐 𝟓𝒙 in terms of Legendre polynomial. #MathEConnect #Shafiqahmedyellur
Express 𝟐𝒙^𝟑−𝒙^𝟐−𝟑𝒙+𝟐 in terms of Legendre polynomial
Переглядів 1,1 тис.Рік тому
21MAT41 : Express 𝟐𝒙^𝟑−𝒙^𝟐−𝟑𝒙 𝟐 in terms of Legendre polynomial. #MathEConnect #Shafiqahmedyellur
If 𝒙^𝟑+𝟐𝒙^𝟐−𝒙+𝟏=𝒂𝑷_𝟎 (𝒙)+𝐛_𝑷 𝟏( 𝒙)+c𝑷 _𝟐 (𝒙) +d𝑷_𝟑 (𝒙) .Find the value of a, b, c, d.
Переглядів 33Рік тому
21MAT41 : If 𝒙^𝟑 𝟐𝒙^𝟐−𝒙 𝟏=𝒂𝑷_𝟎 (𝒙) 𝐛_𝑷 𝟏( 𝒙) c𝑷 _𝟐 (𝒙) d𝑷_𝟑 (𝒙) .Find the value of a, b, c, d. #MathEConnect #Shafiqahmedyellur
Express 𝒙^𝟑+𝟐𝒙^𝟐−𝟒𝒙+𝟓 in terms of Legendre polynomial
Переглядів 469Рік тому
21MAT41 : Express 𝒙^𝟑 𝟐𝒙^𝟐−𝟒𝒙 𝟓 in terms of Legendre polynomial #MathEConnect #Shafiqahmedyellur
Rodrigues Formula & Results.
Переглядів 36Рік тому
21MAT41 : Rodrigues Formula & Results. #MathEConnect #Shafiqahmedyellur
Series Solution of Legendre s Differential Equation
Переглядів 49Рік тому
21MAT41 : Series Solution Of Legendre’s Differential Equation.. #MathEConnect #Shafiqahmedyellur
Orthogonality of Bessel s Functions
Переглядів 37Рік тому
21MAT41 : Orthogonality of Bessel s Functions #MathEConnect #Shafiqahmedyellur
Prove that : 𝑱((−𝟏)⁄𝟐) (𝒙)=√(𝟐/𝝅𝒙) 𝒄𝒐𝒔𝒙.
Переглядів 54Рік тому
Prove that : 𝑱((−𝟏)⁄𝟐) (𝒙)=√(𝟐/𝝅𝒙) 𝒄𝒐𝒔𝒙.
Bessel's Functions: Series solution of Bessel's Differential Equation Leading to Bessel's Function.
Переглядів 91Рік тому
Bessel's Functions: Series solution of Bessel's Differential Equation Leading to Bessel's Function.
Solve the wave equation (𝝏^𝟐 𝒖)/〖𝝏𝒙〗^𝟐 =(𝝏^𝟐 𝒖)/〖𝝏𝒕〗^𝟐 𝒖(𝒙,𝟎)=𝒔𝒊𝒏𝝅𝒙 (0,1), h=0.2, k=0.2 at 𝒕=𝟏.
Переглядів 39Рік тому
Solve the wave equation (𝝏^𝟐 𝒖)/〖𝝏𝒙〗^𝟐 =(𝝏^𝟐 𝒖)/〖𝝏𝒕〗^𝟐 𝒖(𝒙,𝟎)=𝒔𝒊𝒏𝝅𝒙 (0,1), h=0.2, k=0.2 at 𝒕=𝟏.
Solve the wave equation 25 (𝝏^𝟐 𝒖)/𝝏𝒙^𝟐 =(𝝏^𝟐 𝒖)/𝝏𝒕^𝟐 𝒖(𝒙,𝟎)={(𝟐𝟎𝒙 𝟎≤𝒙≤𝟏, 𝟓(𝟓−𝒙) 𝟏≤𝒙≤𝟓) h=1, 𝟎≤𝒕≤𝟏.
Переглядів 55Рік тому
Solve the wave equation 25 (𝝏^𝟐 𝒖)/𝝏𝒙^𝟐 =(𝝏^𝟐 𝒖)/𝝏𝒕^𝟐 𝒖(𝒙,𝟎)={(𝟐𝟎𝒙 𝟎≤𝒙≤𝟏, 𝟓(𝟓−𝒙) 𝟏≤𝒙≤𝟓) h=1, 𝟎≤𝒕≤𝟏.
Solve the Wave equation (𝝏^𝟐 𝒖)/(𝝏𝒙^𝟐) =𝟎.𝟎𝟔𝟓 (𝝏^𝟐 𝒖)/𝝏𝒕^𝟐 , 𝒖(𝒙,𝟎)=𝒙^𝟐 (𝒙−𝟓), h=1, k=0.5 ,4 steps.
Переглядів 35Рік тому
Solve the Wave equation (𝝏^𝟐 𝒖)/(𝝏𝒙^𝟐) =𝟎.𝟎𝟔𝟓 (𝝏^𝟐 𝒖)/𝝏𝒕^𝟐 , 𝒖(𝒙,𝟎)=𝒙^𝟐 (𝒙−𝟓), h=1, k=0.5 ,4 steps.
Solve the wave equation (𝝏^𝟐 𝒖)/〖𝝏𝒕〗^𝟐 =𝟒 (𝝏^𝟐 𝒖)/〖𝝏𝒙〗^𝟐 𝒖(𝒙,𝟎)=𝒙(𝟒−𝒙) , h=1, k=0.5 upto 4 steps.
Переглядів 25Рік тому
Solve the wave equation (𝝏^𝟐 𝒖)/〖𝝏𝒕〗^𝟐 =𝟒 (𝝏^𝟐 𝒖)/〖𝝏𝒙〗^𝟐 𝒖(𝒙,𝟎)=𝒙(𝟒−𝒙) , h=1, k=0.5 upto 4 steps.
Working procedure for one dimensional wave equation
Переглядів 32Рік тому
Working procedure for one dimensional wave equation
21MAT31: Numerical solution of the one dimensional wave equation.
Переглядів 71Рік тому
21MAT31: Numerical solution of the one dimensional wave equation.
21MAT31:Numerical Method PDE, Classification of PDE of second order & Finite difference approximate.
Переглядів 116Рік тому
21MAT31:Numerical Method PDE, Classification of PDE of second order & Finite difference approximate.
# Partial Derivatives || # Definition || #Symbols
Переглядів 2,1 тис.2 роки тому
# Partial Derivatives || # Definition || #Symbols
#Evaluate || lim_𝒙→𝟎(𝒔𝒊𝒏𝒙𝒙^𝟏⁄𝒙^𝟐 ) || 21MAT11 || Module : 2 || Differential Calculus ||BMATE101
Переглядів 1 тис.2 роки тому
#Evaluate || lim_𝒙→𝟎(𝒔𝒊𝒏𝒙𝒙^𝟏⁄𝒙^𝟐 ) || 21MAT11 || Module : 2 || Differential Calculus ||BMATE101
Evaluate || lim_𝒙→𝟎(𝒕𝒂𝒏𝒙𝒙^𝟏⁄𝒙 ) || 21MAT11 || Module : 2 || Differential Calculus ||
Переглядів 7182 роки тому
Evaluate || lim_𝒙→𝟎(𝒕𝒂𝒏𝒙𝒙^𝟏⁄𝒙 ) || 21MAT11 || Module : 2 || Differential Calculus ||
Evaluate || lim┬(𝒙→𝟎)[((𝒂^𝒙+𝒃^𝒙+𝒄^𝒙+𝒅^𝒙 ))/𝟒]^(𝟏⁄𝒙) || 18MAT11 || Differential Calculus
Переглядів 4,9 тис.2 роки тому
Evaluate || lim┬(𝒙→𝟎)[((𝒂^𝒙 𝒃^𝒙 𝒄^𝒙 𝒅^𝒙 ))/𝟒]^(𝟏⁄𝒙) || 18MAT11 || Differential Calculus
Evaluate || lim_𝑥→𝜋/2(𝒔𝒊𝒏𝒙^𝒕𝒂𝒏𝒙 )|| 18MAT11 || Differential Calculus
Переглядів 7 тис.2 роки тому
Evaluate || lim_𝑥→𝜋/2(𝒔𝒊𝒏𝒙^𝒕𝒂𝒏𝒙 )|| 18MAT11 || Differential Calculus
Evaluate || lim┬(𝒙→𝟎) ([𝒄𝒐𝒔𝒙]^(𝟏⁄𝒙^𝟐 )) || Differential Calculus || #Math E Connect
Переглядів 2892 роки тому
Evaluate || lim┬(𝒙→𝟎) ([𝒄𝒐𝒔𝒙]^(𝟏⁄𝒙^𝟐 )) || Differential Calculus || #Math E Connect
Evaluate || lim_(𝒙→𝟏)(𝒙^(𝟏⁄(𝟏−𝒙)) )|| Differential Calculus || #Math E Connect||
Переглядів 2262 роки тому
Evaluate || lim_(𝒙→𝟏)(𝒙^(𝟏⁄(𝟏−𝒙)) )|| Differential Calculus || #Math E Connect||
Thanks❤
Alyson Harbor
Thank you ❤
Aaron Lock
Very very very very very bad and wrost handwriting
Ruben Crest
Sir how to get the fraction value of y??
you did shit here
no entiendo 😭😭
Thank Youu❤❤
my answer using newton raphson is 3.5425 can the answer change if we are using different formula ?
For a different method formula there will be slight change in answer.
Cortez Way
Becker Crest
Vandervort Roads
TQ uu so much sir ji ❤
Kennedi Creek
Jones Crest
Verna Points
Amazing
Ellis Inlet
Thank you so much sir❤.... Really helped a lot and your teaching is just fabulous🫡
First write neatly
Sir 1/8+1/8=1/4, not a 2/8
thank you for this clear explanation
❤❤❤❤❤❤❤ kaleja faad explanation sir thank u sir hatts off sir
Deven Causeway
Emmanuelle Cliff
Nice explanation but please improve your handwriting sir
I will try my best
Thank you🙏 very much sir
Most welcome
Thank you so much sir
Most welcome
Sir why cant we use intial a and b as 1 and 2??
Thank you 😊🙏🏻 Sir✨🙏🏻
We can consider a=2.3 b =2.4. For first iteration, but y 2,3 as given in question? Sir please reply
If the initial value is given in question then we have to use that only.
For above question roots lie in 2 and 3.
Sir a humble request could you write neatly so we could understand better .
Yes sure.
Thank u sir❤
how to calculate in calculator ?
Tq sir🙏🏻
Wrong
can you upload the notes also in some drive or social secction of youtube, sir ?
Can anyone explain me in the end the eqn 3 how it changes front left to right side and in some cases it keeps in original form how pls help me
It is just to solve the simultaneous equations.
Writing😢
Thank you Sir😊
Thank you Sir 😊
How is n=6
Ordinate will be odd in numbers so always 1 less of it will be n value.
Sir can u explain in CASIO fx-991MS
Our calsii & ur calsi is too different soo all calsii mode you have to tell it is use full to us thank you sir
Sir,why should be take this in only radian mode.why not in degree mode
Bruh coz it's 0.2 gap you'd never use such small values for degree for degree you'd use larger values like 10 degrees or higher
@@NiggasinGTAVIthanks
These problems will be calculated in radian mode if trigonometric functions are there.
Sir if the base of the log is not mentioned what base should we take sir??
ln
thank you
Our mam told to use degree in calci can we use sir
Correct, but actually here we have to calculate in radian mode if trigonometric functions are present.
@@MathEConnect thank you sir for your reply today my exam is there
@@MathEConnect OK sir