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Doctrina
United States
Приєднався 5 гру 2015
Greetings and welcome to my channel, Doctrina. The name "Doctrina" comes from the Latin word for learning, and that is the ultimate goal of this channel. Here, you can find a variety of supplementary math videos covering various mathematical topics, each categorized by playlists dedicated to a particular subject (such as calculus). As a math educator, I strive to make these videos as detailed as possible, understanding that students may have questions about setting up problems or simplifying algebraic expressions. However, it's important to note that these videos should be used as supplementary materials and not as a replacement for a traditional teacher or course. In my opinion, no set of videos can replace the learning experience of an in person class. I always remind my students that to truly learn math, you must practice, as it is a cumulative subject that builds on previous topics. For additional supplementary materials, please visit my website listed below.
Відео
Finding the Complex and Real Roots of a Polynomial
Переглядів 29Місяць тому
Finding the Complex and Real Roots of a Polynomial
Solving a Polynomial Equation Given a Complex Root
Переглядів 88Місяць тому
Solving a Polynomial Equation Given a Complex Root
College Level Precalculus - Section 3.7 (Rational Functions)
Переглядів 58Місяць тому
openstax.org/books/precalculus-2e/pages/3-7-rational-functions
College Level Precalculus - Section 3.6 (Complex Zeros)
Переглядів 78Місяць тому
openstax.org/books/precalculus-2e/pages/3-6-zeros-of-polynomial-functions
College Level Precalculus - Section 3.3 & 3.4 (Power Functions and Graphs of Polynomial Functions).
Переглядів 158Місяць тому
Section 3.3: openstax.org/books/precalculus-2e/pages/3-3-power-functions-and-polynomial-functions Section 3.4: openstax.org/books/precalculus-2e/pages/3-4-graphs-of-polynomial-functions
College Level Precalculus - Section 3.2 (Quadratic Functions)
Переглядів 122Місяць тому
openstax.org/books/precalculus-2e/pages/3-2-quadratic-functions
College Level Precalculus - Section 2.2 (Graphs of Linear Functions)
Переглядів 49Місяць тому
openstax.org/books/precalculus-2e/pages/2-2-graphs-of-linear-functions
LU Factorization of a Matrix
Переглядів 131Місяць тому
In this video I discuss the LU factorization of a matrix A, where L is the lower triangular matrix and U is the upper triangular matrix. I also provide an example on how to solve a system using a LU factorization approach.
College Level Precalculus - Section 2.1 (Linear Functions)
Переглядів 201Місяць тому
openstax.org/books/precalculus-2e/pages/2-1-linear-functions
College Level Precalculus - Section 1.7 (Inverse Functions)
Переглядів 902 місяці тому
openstax.org/books/precalculus-2e/pages/1-7-inverse-functions
Finding the Relative Minimum and Relative Maximum Using the TI 84 Calculator.
Переглядів 732 місяці тому
Finding the Relative Minimum and Relative Maximum Using the TI 84 Calculator.
College Level Precalculus - Section 1.5 (Transformation of Functions)
Переглядів 1872 місяці тому
Transformation of Functions openstax.org/books/precalculus-2e/pages/1-5-transformation-of-functions
College Level Precalculus - Section 1.3 (Rates of Change and Behavior of Graphs)
Переглядів 1882 місяці тому
Rates of Change and Behavior of Graphs Reference: openstax.org/books/precalculus-2e/pages/1-3-rates-of-change-and-behavior-of-graphs
College Level Precalculus - Section 1.1 (Functions and Function Notation)
Переглядів 1102 місяці тому
Functions and Function Notation Reference: openstax.org/books/precalculus-2e/pages/1-1-functions-and-function-notation
Solving Logarithm & Exponential Equations
Переглядів 1107 місяців тому
Solving Logarithm & Exponential Equations
Graphing a Piecewise Function 2 (Section 1.2 Problem #41)
Переглядів 47Рік тому
Graphing a Piecewise Function 2 (Section 1.2 Problem #41)
Graphing a Piecewise Function (Section 1.2 Problem #39)
Переглядів 96Рік тому
Graphing a Piecewise Function (Section 1.2 Problem #39)
Section 1.5: Solution Sets of Linear Equations
Переглядів 229Рік тому
Section 1.5: Solution Sets of Linear Equations
Section 1.4: The Matrix Equation Ax = b
Переглядів 295Рік тому
Section 1.4: The Matrix Equation Ax = b
Homogeneous Linear Systems of Differential Equations
Переглядів 102Рік тому
Homogeneous Linear Systems of Differential Equations
Solving Initial Value Problems Using Laplace Transforms
Переглядів 89Рік тому
Solving Initial Value Problems Using Laplace Transforms
Approximating a Definite Integral Given an Error
Переглядів 261Рік тому
Approximating a Definite Integral Given an Error
An Introduction to the Laplace Transform
Переглядів 127Рік тому
An Introduction to the Laplace Transform
I did this problem over and over and kept getting different answers then i found this video and its was the exact same problem with the exact numbers and i had gotten the right answer with regular method but this was a way better way of doing it.
Glad you're finding success with determinants!
where is the link of the other part
The link is in the video description. ua-cam.com/video/8c6IG72chtE/v-deo.htmlsi=GdO1Gac2WZr3Bdsa
where is the application
The purpose of this video is to show how to use the TI calculator to put a matrix into reduced row echelon form. Here is a possible application involving the heat flow of a plate: ua-cam.com/video/HE8Ra5o0xUU/v-deo.htmlsi=02t5PBvLLHVbh8Ef
Thank you so much for this video
You are welcome.
why -2 not 2 ?
Since there is a 2 is in the second row and third column the sign will be negative (-1)^(3+2) = (-1)^5 = -1. Here is the sign chart (same one that is used in the video): tinyurl.com/cofactorsigns
Finally I'm student and i see 😅
شكرا
مرحباً بك.🙏
Thank you for the video.
You're welcome
Thank you so muchh❤
You're welcome 😊
What a great video. Perfect in every way. Thank you for sharing. Your handwriting is perfect; it rivals the great Sal Khan's...
Thank you for the delightful comment.
great content, but wouldn't the solution be undefined? The initial value is (1,4), if you plug in 1 into y, y' would be square root of -8, which doesn't exist. Or maybe (1,4) is not initial value?
Given that the initial value is (1,4) then x = 1 and y = 4.
Thanks, this was helpful!
You are welcome.
Having been out of Calc 2 for several years now, and having never taken calc 3, I really appreciate how thorough you are in explaining what you are doing. Thanks for uploading this!
Glad it was helpful!
you mentioned section 4.4 of some book you are using - what is it?
"Linear Algebra and Its Applications" by David Lay, 6th edition.
Sir final answer will be -6
The answer is 6, I would suggest reviewing your work and checking your co-factor signs. matrixcalc.org/det.html#%7B%7B4,0,-7,3,-5%7D,%7B0,0,2,0,0%7D,%7B7,3,-6,4,-8%7D,%7B5,0,5,2,-3%7D,%7B0,0,9,-1,2%7D%7Dexpand-along-column1
Thank you man Really helpful
Glad to hear that!
Why is there a subtraction sign just before you start the multiplication?
The sign of the cofactor is (-1)^(i +j), so since 2 is located in the second row (i = 2) and third column (j = 3) then the sign will be (-1)^(2 + 3) = (-1)^5 = -1. Here is the sign chart (same one that is used in the video): tinyurl.com/cofactorsigns
If we perform coloum transformation and make all zero in row 1 expect one non zero values and again do the same for 2 row and find the determinant for 3x3 matrix and so then can we get the answer ?
Yes, but keep in mind that certain elementary row operations will change the determinant of the original matrix. This is discussed in my notes: blogs.nvcc.edu/mwesterhoff/files/2019/09/Section3.2-Properties-of-Determinants.pdf
I should look at math lectures from UA-cam more often. I'm not sure why but they tend to be a lot more effective than the slideshows, textbooks, and lectures my course offers.
I believe videos can be helpful, but reading and understanding material from a book forces the mind to engage more deeply, resulting in better retention. When I was in college, we didn't have videos, so we had to thoroughly read the material. If we didn't understand something, we would re-read it or look for alternative explanations in other textbooks, often spending a lot of time in the library. Otherwise, we had to visit the professor during office hours, hoping they could provide a hint, as they definitely wouldn't solve it for us. Struggling with a problem or concept is a crucial part of learning math. That's why I always tell my students to try to solve the problem before looking at the detailed solution. It's fine if they don't get it right on the first attempt; they just need to review their work, think about it, and try again.
@@DoctrinaMathVideos Yep, looking at online lectures is a last resort. I said that I should do it more often because sometimes I am stubborn about that to a fault and don't use anything other than what the course gives to me for far too long.
That's so interesting ,I hope u can make more videos like this
I am pleased you are intrigued by this. Feel free to share which particular subjects you would like me to cover in my videos.
Good to see my favorite professor uploading a new video.
It is great to hear from you! I am glad you are enjoying the new video uploads. Let me know if there are any topics you would like to see covered in future videos.
This lecture was so helpful
I am glad that you found this lecture to be helpful.
thank you!
You are welcome.
This was sooo helpful, thank you!!
You're so welcome!
Hi .. I wanna ask from which book you took this problem...kindly share the name of that book...
Hello. "Linear Algebra and Its Applications", 5th edition, David Lay. Problem #33 of Section 1.1 on page 11. Edit: In the 6th edition it is problem #43 on page 12.
Thank you very much 😊
Bro thank you
You are welcome.
What if the second original row and coloumn was with two vaules different from zero and 3 zeros what should we do in this case ?
Just apply the co-factor expansion to each of the other columns that do not contain zero.
This only works for matrices with 1 row or column value and the rest is zero
I think you will have to add additional terms and include non zero row or column values
This example was specifically chosen (by request) to illustrate that it is important to look at the rows and columns carefully to illustrate that the number of steps can be reduced by choosing the row or column with the most zeros. Once you learn the basic technique of the cofactor expansion concept it becomes an iterative process. If an application requires the use of the determinant of a 4 x 4 matrix or higher then I would highly recommend using some type of computational tool such as Matlab or Octave.
@@DoctrinaMathVideos Tell that to my linear algebra professor who expects us to do the determinant of a 5x5 by hand without a calculator! 😭😭
Been there done that, but I do find it kind of ridiculous. Better hope that there is a column or row with some zeros in it. :)
this trick is EXTREMELY helpful
It's not really trick it's more of just taking advantage of the row or column with the most zeros and understanding how the cofactor technique works for finding the determinant of a matrix.
final is in 2 days heh thanks!
Good luck!
thanks for making this video 😃😃
You are welcome.
Life saver
Glad you found it useful.
So helpful! Knewton told me to approximate the definite integral, but I did not realize I had to use a calculator in this way to solve for the answer.
Glad this was helpful. This function shown in the video does not have an antiderivative so you must rely on technology (such as the graphing calculator) or numerical techniques such as the Trapezoidal rule, Simpson's rule, and series.The choice of numerical method depends on the nature of the function being integrated, the desired level of accuracy, and the computational resources available. In more advanced math/engineering courses and scientific applications, you will often encounter a combination of these techniques to solve complex integration problems effectively.
thanks man
You are welcome.
Thank you so much 👍
You are welcome.
Thankyou for this video
My pleasure 😊
Thank you sir
You are welcome.
thanks
You are welcome.
Thank you sir
You are welcome.
Best méthode !
Merci!
Thankyou sir
You are welcome.
Amazing explanation and fascinating subject! :D
Glad it was helpful!
Thanks!
You are welcome.
is there a limitation to this method? i find it works sometimes and sometimes it doesn't
There is no limitation for the cofactor expansion technique as long as the matrix is square. The last step where you see the diagonal lines can only be applied for 3 x 3 matrices. Instead of the diagonal lines approach you could have continued using the cofactor approach and end up with the same solution.
This was really helpful, thanks!
Glad it was helpful!
thank you
You're welcome
Thank you very much, now I understand the issue that I did not understand since morning.
Glad it helped!
Helpful
I am glad it was helpful.
NIce. Thank you! None of the other videos explained that you might have to rewrite the sequence before input. Very helpful.