Відео

Madam .your writting board is not good. we can see nothing on the board .

My idol scientist

Thank you

To draw a reciprocal function it is enough to make a symmetry with respect to the axis y=x

interesting problem, good explanation

Après 2:41, la démonstration devient lourde, à la limite tordue

Thank you. What is the advantage in using the Lambert W to solve equations (considering real solutions) rather than just using an iterative approximation on a spreadsheet? In both cases the answer is an approximation to some desired precision.

Funny how no one wants to graph to verify. Graphing y = 6x and graphing y = e^2x you can see there are 2 real solutions.

Hey I am a 15years old student from India And your new subscriber. I just watched your Lambert lambda function video and I understand it easily and This video is not in English language so I can't understand it but I think it is very useful, so can you please re make it in English😅😅 I would be very grateful if you do so. thank you

So I’m noticing that if you graph those two functions, they do not intersect. Which explains why x = -(ln 8)/5 does not work for an input into the Lambert function Valid input …. -1/e < x < infinity -1/e =-0.368 and our value is less than that

Beautiful video, thank you!

Hi, Ok.

what I like to do for my strategy to solve these problems is to eliminate the exponent over the X first. in this problem, I do the 5th root of both sides to give me x=8^(x/5). this makes solving the problem easier. when I saw lambert W functions a few weeks ago for the first time, I noticed doing this strategy made lamber W function problems that were similar to this easier to solve.

Excelente profesora, se agradece por entregar sus conocimientos......

Thank you ,I'm go to croacia and go to the village Nikola Tesla norn.

How calculate the function w of lambert to w(ln(8))/5)? If there'inst method , is bether input The function in The computar program.......

Glad to know the Lambert W at 57 years old !

No automatic CC. 🙁

Ovo je predobronikad nije kasno da poradimo na sebi ucimo dok smo zivi.

Male stvari svaki dan cine veliku promjenu. Hvala. Savršeno kao i uvijek. ❤

Ovo je vrh. Bas za naučiti kako biti bolja osoba.

Some of you tell me that you can't turn on English subtitles. I'm sorry that's the case. I tried to set it up, but UA-cam keeps not confirming it. I will keep trying and I hope it will work.

pored toga scega što ste naveli možda je televizija mnogo veće zlo i za mladju i za stariju generaciju_inteligenciju kod ljudi smanjuju informacije opšte koje su 90% laži pa onda razna muzička takmičenja koja su se motala na raličitim televizijama tu spadaju i razni rialiti programi i površna muzika koja se plasira još od devedesetih pa nadalje_sve je to uticalo na ljudski mozak tu su poremećeni i medjuljudski odnosi pa onda imao i mnogo rastavljenih brakova i imamo dosta ljudi koji su sami_čak šta više društvene mreze budu jedan period pa onda polako stagniraju dok televizija iako se možda manje gleda danas nego li ranije nažalost i dalje opstaje_

It would be nice to remark that reflecting the graph of a monotone real function across the line y = x yields the graph of the inverse function.

Upornost se isplati,bravo

Moin. Grüß dich. Danke für Lambert Funktion Erklärung.

Thanks.

How to find w(4)=?

Congrats! You already reached more than 5000 subscriptions.

Although very interesting it is impossible to read your text. Can you use a white board with black marker.

I do not understand a word, and unfortunately, subtitles are off. Schade....

Svaka čast ❤

To nije bilo lako 🎉 Svaka čast 😊

Za konkretne savjete preskocite na 7:15.

Hvala na informacijijama. Lijepo je to sve znati

Si c'est du polonais, ça une sonorité proche du russe

You can on your cc for English language because I am old student of your channel.

We can solve it without using W lambert ...x ^x= 1/(-2)² = (-2)-² then x=-2

Dear Intellecta you are ver smart. Please go back to the channel

Hello, I'm just saying hello. I hope you are happy. I do not know what country you are from and what language you are speaking. I'm 71yo. All the best and many thanks, 🙂 Peter Nolan. Ph.D.(physics), Dublin, Ireland.

X^2 = 2^x. ; Square root both sides ; x= 2^x/2; Now we can solve using W function

Thank you ma'am and It helped me so much☺️☺️

In Wolfram Alpha: solve -2x = productlog( -1/3 ) for x

Thankyou madam. Im from srilanka ❤❤

from Morocco thank you miss for your clear explanation

You a wonderful teacher! This is something I never learned even at a University with a very top notch Mathematics department. Lambert W problems have been on You Tube for a while now but your introductory video is the best I have seen. Thank you!