Відео

I love it

Wonderful story

Nice surprise to find such a lovely reader🎉 thank you

Very good 👍🏻

This whole book was ass

the accents are ok except the belgique one, i suggest you just do a normal accent, as it doesn't work, i prefer to others that have awful music in background or something

nettspenmddddddddd

Who's reading this book?

I have searched for ages,trying to find a narrator who would suit the story,only one and it was an American narrator ( not good)Having read everything Le Carre had ever written there have only been two people who have been first rate……..LeCarre,himself and Michael Jayston at reading LeCarre’s work. This narrator is good.

A legend 🙌recorded this video 12 years ago so we can benefit

this is the only video i can find that explains the jerk in a way i can understand it thank you

Promo-SM

Point taken. When trying to force a person, pushing is preferred over hitting.

Love it like the voices 🦊🐺🐱🦌🦁🐈

У меня логин не запрашивало ни разу , а при попытке сделать коммит пуш строчки с сообщением нет и просить ввести сообщение, что это может быть?

Wow.. You lectures are so amazing and unique..

спасибо

I liked this lecture

There should be a R times N in the center.

👍👍👍👍👍

когда указал какие файлы нужно добавить на гит, пишу логин и пароль и вылетает ошибка идентификации.

Сейчас при попытке пуша постоянно требует логин/пароль, будто они введены неверно, при отмене пишет not authorized. Eclipse 2021-06 (4.20.0) Build id: 20210612-2011 Upd. Fix: в GitHub сгенерирйуте токен (Settings / Developer settings / Personal access tokens) хотя бы с правами "repo" и каким хотите сроком действия и вставляйте его вместо пароля. Всё работает.

Come on man 2 minutes into the video and I feel like I know everything 👍

Спасибо! выручил!!!!

Спасибо большое, пол дня голову ломал, пока твое видео не нашел :)

Спасибо

Spasibo

I created a computer simulation of this phenomenon.

Спасибо Всё очень понятно.

Complicated way of saying we care about changes in forces

Were they shooting from AK's in the audience? Great lecture, but I can barely hear it over the noise in the class...

that is really cool how calculators work

Gizmo

Person in other room who hears tapping on the wall: "that's definitely a jerk next door."

This is super cool.

how can you find all these are orthogonal basis vector other than finding their inner product?

bro.. what?

P < 1 / f''(0) "when the point is closer than the inverse of the second derivative at zero" I've been exploding my brain trying to solve this - I haven't found anything online about it, and I can't even guess what name this critical point might have you're trying to find the "minimum distance" to the curve, from some point on the y-axis, so you need to minimize the 'distance function' - ok then, if: the curve is f(x) the point on the y-axis is (0, Py) and some closest point is (x, f(x)) then the distance to that point closest point is: D(x) = sqrt( x^2 + ( f(x) - Py)^2 ) the MINIMUM value for that is somewhere when D'(x) = 0 so let's find D'(x) D'(x) = x + (f(x) - Py) * f'(x) then solve it for zero, and you'll have your candidates -- you check which is the smallest value, and then ... oh WAIT - we don't actually care about any of that! all we care about is if ZERO is the closest answer - which it will be when the SECOND derivative of this distance function, evaluated at zero, has a positive slope - is that right? that is to say: D''(0) > 0 hmm - well, what IS the second derivative of the distance function D(x) ? D''(x) = 1 + (f(x) - Py) * f''(x) + f'(x)^2 we're positive that we want this to be greater than zero when evaluated at x equals zero 1 + ( f(0) - Py ) * f''(0) + f'(0)^2 > 0 we've also specifically positioned this curve to be symmetric about the y-axis, and to have its 'vertex' at the origin - so we already know that f(0) is zero, AND that the slope of the tangent to the curve at zero is ALSO zero - which means that f'(0) is zero aswell - substituting that, we reduce [1 + (0 - Py) * f''(0) + 0^2 > 0] to [1 - Py * f''(0) > 0] and rearrange it to tell us something about Py: Py < 1/f''(0) I created a desmos graph to check this out, and it _does_ werk for an ellipse or a parabola, but NOT for x^4 in certain cases, it's possible to have solutions that are closer than zero even if the slope of D'' is positive at zero I described the critical point a little more succinctly as: Py * f''(0) < 1 I ought to be able to figure out the second derivative of an ellipse in terms of the major and minor axes, and end up with a more geometric - instead of a calculine one - possibly doing implicit differentiation of ax^2 + by^2 = r^2

Dismissing the fact that velocity is something that will never be a given. Which put into mathematics will break any equation. Then goes on and says what if I want it to crash and transfer that velocity over before it stops. If that happened then the energy given onward will lose strength overtime too and not change anything. With each "crash" the velocity will still be on a decline. Eventually coming to a stop and eventually breaking your equation. So dont dismiss physics because physics plays a huge role in that equation even working to begin with.

thanks so much this is fucking awesome, brilliant .

This needs more recognition, amazing lecture!!

I've always loved your lecture videos. Very different. Not tuned at doing meaningless calculations focused at techniques that do not yield insight or scale well as the student progress into more advanced content. Thank you

Спасибо большое!

mathematics is like magic ,u can go anywhere from ur current knowledge , but how they really found the gradient concept , using this approach or something else?

so now u started to talk about dot product , but this is the first time u mention it , and i wasn't not explained, that means this series of vids come after another series?

also if the ball is sliding it will stay straight line

now its clear why we need a vector to describe the line in space ..thanks

great

Thank you for the comprehensive explanation, but how do you prove L'hospital's rule in the case of infinite/infinite?