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Engineering Mechanics - Statics and Dynamics
Приєднався 10 гру 2014
Відео
Work Energy Methods - Example 2
Переглядів 4,9 тис.9 років тому
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Work Energy Methods - Example 1
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Impulse/Momentum - Example 4
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Impulse/Momentum - Example 2
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Impulse/Momentum - Example 3
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Impulse/Momentum - Example 1
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Center of Percussion - Example
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Dynamics -Example 4
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Dynamics -Example 3
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Dynamics -Example 2
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Dynamics -Example 1
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Particle Kinematics - Curvilinear Coordinates
Переглядів 8 тис.9 років тому
Particle Kinematics - Curvilinear Coordinates
Dr.Mahesh V Panchagnula course intro
Переглядів 41 тис.10 років тому
Dr.Mahesh V Panchagnula course intro
only worth mechanics course
It is a good lecture and an even better course. I wonder how no one has commented yet till now.
YOU ARE THE BEST TO EXPLAIN THIS!!!!!!!!!!!!!!!!!!!!!!!!!!!! thanks
thank you sir
thank you sir
Old is gold
Sir, your videos are helpful for upsc mathematics optional? Plz tell me sir .
Your're a legend! Thank you!
L aur 2l k chakkar me mamla gadbda gya
Calculation mistake hone k karan expression galat aya h, while the concept is correct.
Fast and furious 11 calculation speed
but in mechanics we deals only with external forces na!!
ty very much sir
ty very much sir
ty very much sir
In the last of this lecture there has a short mistake, Value of x is (5+power1/2(105))/2 instead of (5+power1/2(125))/2. Am I right??
Yes you're right
thank you sir for this valuable content
....................??
ty very much sir
ty very much sir
tyvm sir
I got Normal force N=128 N instead of 96 N. I think cos @ = 4/5 .
whole solution is wrong the value of d must be one third of the length
thank u sir for providing us
Sir , if point A is fixed then also a moment come about point A, along with normal and horizontal reactions. Sir please explain.
explained well sir.
Sir mechanical engineering is easy or not
not the easiest
Difficult
Easy
Sir, why you had not considered the weight while calculating force equations
Rod is in horizontal plane.
Rod is in horizontal plane
There is calculation mistake sir
Sir U forgot to keep negative sign in Acceleration(C/B) in rw^2 component
At 12 calculation has an error while subtracting the F term which is outside the bracket. The answer should have been d=2l/3 which will give COP as l/3 from centre which is the standard result that can be obtained from physical pendulum analysis also. Great work though for the benefit of learners...
Why weight force is not considered while calculating force equations
@@chandrashekharghotekar4063 evaluation is on a 2D plane . Force of gravity is going into the paper..so not needed.
Very well explained sir... thank you very much
Why is the effect of weight not considered sir ??
That's a good Question, I would also like to know why the effect of weight was not taken into consideration since it's also action on the rod at the center of mass G.
@@ericlekwane6344 i think,in the diagram it was shown that g acts perpendicular to the plane inwards,hence has no contribution in the kinetics of the rod,am i right?
Nice explanation but Center of percussion of given rod was L/3 from the end and not L/2.
Sir sorry to say I didn't get anything in this video
bro listen word to word then you will definitely gonna get it...
@@shivanshuudeniya3338 Whats constraint force by inclined plane on block (F1)..i cant understand. ...plz tell me why how this F1 appears
@@subrataray9442 Here F1 is the Normal Reaction force caused by inclined plane whic is equal to the F2*cos (a) where a is the angle between inclined plane and x axis
@@shivanshuudeniya3338 Oh..but sr. Says its distributed constraint force it has'nt unic line of action. ....but normal force = reaction to body weight which has unic line of action...so what is it..?.. Plz explain..
@@shivanshuudeniya3338 distributed constraint force f1 has'nt unic line of action. & this f1 exrted by inclined plane resist to penetrate the block into inclined plane..How f1= Normal reaction force.!!...plzz tel me..
very interesting and great explanation...
thankyou sir
Sir Kya pura syllabus cover ho rha hai
marvelous .. teaching style tnx u sir
nice sir..
Sir I've been watching these videos for a couple of days. I found out that the lectures from here onward was taught by another professor. I meant to ask if that was the intended course of action, or is there some sort of error?
awesome explanation
of course yes, because if a body is in uniform motion then according to the 1st law zero force is acting on it, thus the body is in equilibrim....
Your statement is incomplete. • Body is continuous to be in rest or uniform motion (Along straight line) unless & until the external force acts. • Not only uniform motion as it can be any uniform motion but every uniform motion is not non-accelarating type. • For eg. Uniform circular motion means (constant angular velocity), even if tangential accelaration is zero but there is still radial (centripetal) accelaration on it.
@@NAYAN-t3e Yes. Uniform motion in a straight line.
sir if a body is in uniform velocity, then an object is in equilibrium?(according yo 1st law)
You have finished school, right? If not, go back and finish school.
Great lecture sir
how to calculate cop of pendulam
Sandip Jagtap hello do you know the order of the order video vise
19:00 Perfect!
I've some doubts in this...is there a way to clear it...??
Me too, Please tell me also, How can i clear my dobts
this is one deadly problem.. bit more explanation while using the old formulas would have been more helpful for less intelligent students like me.... which you are expecting the viewers to know already...
thanku sir its very helpfull....