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Rashel's Classroom
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Can You solve this Maths Olympiad Questions? A tricky maths olympiad question.
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Cambridge University admission interviews maths tricks. A Nice radical maths olympiad question. Maths simplification tricks. #maths #mathematics #algebra For others videos @rashel1
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This is not a solution. It is reduction to simplest form.
This is how I found my answer. a+2b+b = 8 a(1+2b)+b = 8 (÷a) (1+2b)+b/a = 8/a 1+2b = (8-b)/a a = (8-b)/(1+2b) If b = -9 then a = (8-(-9))/(1+2(-9)) = -1 a+b = (-1)+(-9) = -10 'Ans#1 ElseIf b = 8 then a = (8-8)/(1+2(8)) = 0 a+b = 0+8 = 8 'Ans#2 End if ...And many more just by substituting values "b" 😅😂😊🎉
Those who say he’s over complicating the problem, did you even finished the video?
Nice and simple either way.
I got the answer before calculate . x = 4
wrong
That is only one of the four answers.
Six answers.
it took me like 5 seconds , x^6=4^6, therefore x=4
There are six answers.
How do people get x=1/3?? 2 tetrated to 3 is the same as 2^2^2, which is 2^4. (2^4)^x+1 = 2^4 , 4*(x+1) = 4 , 4x+4 = 4 , 4x = 0 , x=0.
x=5/3
Good teaching; thanks.
x=4
2(a+b+c)= 600 a+b+c-300=0
27
27
❤
You're overcomplicating this problem, you might have simply multiplied the fractions on either of the sides and taken cube root on both the sides so the equation would be much simpler as 4 over x equals x over 4 then multiply x over 4 or 4 over x on both the sides you will appear at a situation where x square equal 4 square, this can be simply solved by taking square root on both the sides, then you will get x equals positive or negative 4. Sounds simple, right?
If they ask all possible solutions, you're approach was correct and acceptable, also well explained!
X=4
why do you use a complicated method instead of using a simpler method??
This can be simplified
too long while simple when power same then bases are equal
thank you Mr. I really thank you
X=4
16.16^4_16^4= (16-1)16^4 =15.16^4 or 15.2^16 Loves from Türkiye❤
It takes me just 3 seconds
Amazing. I never thought that the exponential function to base 4 could be undone by the logarithm to base 4, which is the inverse of the exponential. Here's another one with same difficulty: 4*x=20 Why is this super trivial stuff labeled "math olympiad"? 😂
x+y=12 square both sides (x+y)²=12 x²+2xy+y²=12² given xy=12 x²+2(12)+y²=12² x²+24+y²=12² x²+y²=144-24=120 x²+y²=120 x²=120-y² x=√(120-y²)= √120-y x=√4×30-y x=2√30-y now xy=12 (2√30-y)y=12 (2√30)-y²=12 (2√30)²-y⁴=144 (2√30+y²)(2√30-y²)=144 root 1 2√30+y²=144 y²=144-2√30 y=√(144+2√30) y=12+√(2√30) now x=2√30-y x=2√30-(12+√(2√30) x=2√30-12+(√(2√30)
thanks
@rashel1 welcome, by the way I'm only in 8th grade
@@ApexGC91732 I thought Einstein was dead
You explained it in easy and slowly in understandable way. Respect ! Respect Redpect !
D is correct
BULLSHIT 😂
Veeeery easy Math. specially to Korean students.
x=1
Like what a commentor said earlier, trial and error is a much easier method. Just find the number that fits for the exponent. n = 3 (3^3 + 2^3 = 27 + 8 = 35)
0.783381 by calculator
Supper & easyer explaination tks. Sir.
Well,it was way easier to solve just by hit and trial method 😁
(9^-2^-1)^-3=1/537,841 Thus, None Of The Answers Are Correct
81^3=(80+1)^3=(80^3)+((80^2)3)+((80^1)3)+(1^3) 80^3=512,000 80^2=6,400 3*6,400=19,200 80^1=80 80*3=240 1^3=1 512,000+6,400+19,200+240+1=537,841
81^-3=1/(81^3)
1/(1/81)=1*81=81
1/81^-1=1/(1/81)
9^-2=1/81
9^2=81
x^-y=1/(x^y)
Did he literally write “1+1+1” ?
(9-²-¹)-³ = (1/9-²)‐³ =( 9²)-³=1/(9²)-³=1/81³ , мне кажется ответ D - none .
ขอบคุณครับ
Not correct. I reported this video for misinformation
Can you make videos about like 1-Sin²x/Sin²x-Cos²x=Cos²x I hope you know what I'm saying it's like Take left side or right side about this problem
Don't you just subtract exponents? It's 16
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